Book 12C

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Course 12Book 12C: Extinction and the ProofChapter 2

Two-Spheres Disappear

Morgan and Tian's §18.2: finitely many essential sphere surgeries, the minimal-area sphere and its −4π decay, and why every component eventually has π₂ = 0; the sphere theorem as a corollary.

27 min read · Updated Oct 23, 2026

Read Morgan and Tian, chapter 18, §§1–2 (Theorem 18.1, Definition 18.2, Lemmas 18.3 and 18.5, Proposition 18.7 with Claim 18.8, Proposition 18.9, Lemmas 18.10–18.11 with Claims 18.12–18.13, Corollary 18.14 and Remark 18.15). Perelman III, §1 (two pages), states the corresponding estimate for disks. Hamilton's "Non-singular solutions of the Ricci flow on three-manifolds" (1999), §11, is the origin of the method.

In this chapter · 7 sections
  1. 2.1The theorem
  2. 2.2Essential spheres are finite in number
  3. 2.3The minimal essential sphere
  4. 2.4Every component loses its π2\pi_2π2​
  5. 2.5The sphere theorem
  6. 2.6History
  7. 2.7Exercises
  8. ↗Free resources

12C.1 Reading Off the Topology showed that the topology of MM can be read off from a Ricci flow with surgery that becomes extinct: MM is then a connected sum of spherical space forms and S2S^2-bundles over S1S^1. What remains is to prove extinction. Perelman's third preprint and Colding and Minicozzi's paper prove it for manifolds whose prime decomposition has no aspherical factors, which includes every simply connected one, by finding a geometric quantity, defined by the topology, that the Ricci flow forces to decrease at a definite rate until it would become negative. Morgan and Tian split the argument into two stages, according to the homotopy group that supplies the quantity.

  1. π2\pi_2. The minimal area of a homotopically nontrivial 22-sphere decreases at rate at least 4π4\pi (up to a curvature correction). So after a finite time, no component has nontrivial π2\pi_2. This is this chapter.
  2. π3\pi_3. Once π2=0\pi_2 = 0, a nontrivial element of π3\pi_3 is a sphere's worth of loops, and the maximal area of their minimal spanning disks decreases at rate at least 2π2\pi. So the components must disappear: 12C.3 Finite Extinction gives the overview and Colding and Minicozzi's version, and 12C.4 Loops, Disks and Curve Shrinking the rigorous proof with the curve-shrinking flow.

The method is Hamilton's: in his 1999 paper on nonsingular solutions he used minimal disks to show that the boundary tori of almost hyperbolic pieces become incompressible, by proving that the area of a compressing disk would have to become negative in finite time. The same idea, with spheres instead of disks, kills π2\pi_2.

By the end of this chapter you will be able to:

  • state Morgan and Tian's finite-extinction theorem and derive the Poincaré conjecture and the elliptization conjecture from it;
  • prove that a compact three-manifold has a bound on the number of disjoint, essential, pairwise non-homotopic 22-spheres, and deduce that only finitely many surgeries are along essential spheres;
  • prove that the minimal area W2(t)W_2(t) of an essential sphere satisfies ddtW2≤−4π−12Rmin⁡W2\frac{d}{dt}W_2 \leq -4\pi - \frac12R_{\min}W_2, is continuous between surgeries and does not jump up at surgeries;
  • integrate the differential inequality and conclude that every component eventually has π2=0\pi_2 = 0;
  • deduce the sphere theorem for closed three-manifolds.

The theorem

Theorem 2.1 Finite-time extinction (Morgan–Tian, Theorem 18.1; Perelman III, Theorem 1.1; Colding–Minicozzi)

Let (M,g(0))(M, g(0)) be a compact, connected, normalized Riemannian three-manifold whose fundamental group is a free product of finite groups and infinite cyclic groups. Then MM contains no embedded RP2\mathbb{RP}^2 with trivial normal bundle, and the Ricci flow with surgery from (M,g(0))(M, g(0)) given by 12B.13 Ricci Flow with Surgery for All Time becomes extinct in finite time: its time slices are empty for all large tt.

The theorem gives the Poincaré conjecture at once: by Morgan and Tian's Corollary 15.4 (12B.10 Surgery on a δ-Neck), if some time slice is empty, MM is a connected sum of spherical space forms and S2S^2-bundles over S1S^1; if MM is simply connected, every summand is simply connected, so every summand is S3S^3 and M≅S3M \cong S^3. If π1(M)\pi_1(M) is finite, MM is a connected sum of one spherical space form and copies of S3S^3, so MM is a spherical space form: the elliptization conjecture.

Perelman's version is phrased through prime decompositions ("whose prime decomposition contains no aspherical factors"); Morgan and Tian's group-theoretic hypothesis is equivalent by standard three-manifold topology, and is what the proof uses. The first claim is a short topological argument: an RP2\mathbb{RP}^2 with trivial normal bundle does not separate (it has Euler characteristic 11, so it bounds no compact three-manifold), can be moved off the spheres of a connected sum decomposition by innermost-disk surgery, and then, in the prime factor containing it, forces H1H_1 to surject onto Z\mathbb{Z} while π1\pi_1 contains an element of order 22: neither finite nor infinite cyclic. So Assumption (1) of 12B.10 Surgery on a δ-Neck holds, and the flow with surgery exists.

Paths of components (Definition 18.2). Since surgery can split a component into several, the objects that persist through time are paths of components: a connected open subset X\mathcal X of space-time over an interval II whose slice at each time is a single component. Between surgery times it is the Ricci flow of one component; at a surgery time, if the component is cut along spheres, the path continues into one of the pieces, and if the component is removed, the path ends.

Essential spheres are finite in number

A 22-sphere embedded in XX is homotopically essential if it is not homotopic to a point. A family of disjoint embedded spheres is homotopically essential if each is, and no two are homotopic to each other (Definition 18.4).

Lemma 2.2 Bounded essential families (Morgan–Tian, Lemma 18.5, with Lemma 18.3)

In a compact three-manifold XX there is a bound on the number of spheres in a homotopically essential family.

Proof. For connected XX, cutting along a family F\mathcal F of EE disjoint spheres gives, by van Kampen, a graph of groups decomposition of π1(X)\pi_1(X) with trivial edge groups: a graph with one vertex per complementary piece and one edge per sphere, whose vertex groups are the fundamental groups of the pieces. So π1(X)\pi_1(X) is the free product of the vertex groups and kk copies of Z\mathbb{Z}, k=rank⁡H1(graph)≤rank⁡H1(X)k = \operatorname{rank}H_1(\text{graph}) \leq \operatorname{rank}H_1(X). Essentiality makes the groups at vertices of valence 11 and 22 nontrivial: a valence-11 piece with trivial π1\pi_1 would be a homotopy ball, making its boundary sphere inessential, and a valence-22 piece with trivial π1\pi_1 would be a homotopy S2×IS^2\times I, making its two spheres homotopic. A count on graphs gives 2V1+V2≥E+3(1−k)2V_1 + V_2 \geq E + 3(1 - k), so π1(X)\pi_1(X) is a free product of at least E+3(1−k)E + 3(1 - k) nontrivial factors. By Grushko's theorem a group generated by rr elements is a free product of at most rr nontrivial factors (Lemma 18.3). Since π1\pi_1 of a compact manifold is finitely generated, EE is bounded.

A surgery at time tt along a sphere S0S_0 is essential if S0S_0, flowed back to slightly earlier times, is homotopically essential (Definition 18.6).

Proposition 2.3 Finitely many essential sphere surgeries (Morgan–Tian, Proposition 18.7)

A Ricci flow with surgery satisfying Assumptions (1)–(7) has only finitely many homotopically essential surgeries along 22-spheres.

Proof. Let s(t)s(t) be the maximal size of a homotopically essential family in MtM_t, finite by the lemma. It does not increase in time, and strictly decreases at an essential sphere surgery (Claim 18.8). At a surgery time the operations are: surgery along inessential spheres, which leaves a manifold homotopy equivalent to the old one plus homotopy spheres, so does not change ss; removal of components, which does not increase ss; and surgery along an essential sphere S0S_0. In the last case, take an essential family Ft\mathcal F_t after surgery, push it off the new caps, and flow it back to Ft′′\mathcal F_t'' before surgery, disjoint from S0S_0. Then Ft′′∪{S0}\mathcal F_t''\cup\{S_0\} is essential: a sphere of Ft′′\mathcal F_t'' bounding a homotopy ball would bound one after surgery, unless the ball contained S0S_0, which would make S0S_0 inessential; and two spheres of the family cobounding a homotopy S2×IS^2\times I would remain homotopic after surgery, unless S0S_0 lay inside, in which case S0S_0 is homotopic to one of them or inessential, both excluded. So s(t−)≥s(t)+1s(t^-) \geq s(t) + 1.

So after some time T0T_0 every sphere surgery is along an inessential sphere. From then on, a path of components with nontrivial π2\pi_2 is determined by its starting component: at each surgery its component is either untouched, or split into one piece homotopy equivalent to it and some homotopy spheres, or removed. So the number of components with nontrivial π2\pi_2 does not increase after T0T_0, and it suffices to show that each such path ends.

The minimal essential sphere

Lemma 2.4 Minimal spheres (Morgan–Tian, Lemma 18.10; Sacks–Uhlenbeck)

If XX is a compact Riemannian manifold with π2(X)≠0\pi_2(X) \neq 0, there is e0(X)>0e_0(X) > 0 such that every map S2→XS^2 \to X of area less than e0e_0 is homotopic to a constant, and there is a homotopically nontrivial conformal harmonic map f:S2→Xf : S^2 \to X, a branched minimal immersion, of area exactly e0e_0.

The proof is the Sacks–Uhlenbeck existence theory for harmonic spheres (6C.7 Harmonic Maps and Their Heat Flow): minimize the perturbed energy Eα(s)=∫S2(1+∣ds∣2)αE_\alpha(s) = \int_{S^2}(1 + |ds|^2)^\alpha for α>1\alpha > 1, which satisfies the Palais–Smale condition, among nontrivial maps, and let α→1\alpha \to 1. The minimizers converge away from finitely many points; if the convergence is strong, the limit is the answer, and if energy concentrates, rescaling at a concentration point produces a bubble, a nonconstant harmonic sphere. Morgan and Tian show that the bubble is itself homotopically nontrivial, since otherwise one could cut it off and replace it by a small disk, lowering the energy below the infimum by a definite amount; so the bubble realises the minimum. A minimizing harmonic sphere is conformal (there are no nonzero holomorphic quadratic differentials on S2S^2), hence a branched minimal immersion.

For a path of components X\mathcal X with π2≠0\pi_2 \neq 0 define

W2(t)=e0(X(t))=min⁡{Area⁡f(S2):f:S2→X(t) homotopically nontrivial}.W_2(t) = e_0(\mathcal X(t)) = \min\{\operatorname{Area}f(S^2) : f : S^2 \to \mathcal X(t)\text{ homotopically nontrivial}\}.
Lemma 2.5 The evolution of W2W_2 (Morgan–Tian, Lemma 18.11)

In the sense of forward difference quotients,

ddtW2≤−4π−12Rmin⁡(t)W2(t).\frac{d}{dt}W_2 \leq -4\pi - \frac12R_{\min}(t)W_2(t).

W2W_2 is continuous at non-surgery times, and at a surgery time tt, W2(t)≤lim inf⁡t′→t−W2(t′)W_2(t) \leq \liminf_{t'\to t^-}W_2(t').

Proof. The derivative (Claim 18.12). Let ff be a minimal sphere realising W2(t0)W_2(t_0). Holding the map fixed and letting the metric evolve, the first variation of area under ∂tg=−2Ric⁡\partial_tg = -2\operatorname{Ric} is

ddtArea⁡g(t)f(S2)∣t0=∫S212tr⁡S2(∂tg) da=−∫S2(R−Ric⁡(ν,ν)) da,\frac{d}{dt}\operatorname{Area}_{g(t)}f(S^2)\Big|_{t_0} = \int_{S^2}\frac12\operatorname{tr}_{S^2}(\partial_tg)\,da = -\int_{S^2}\big(R - \operatorname{Ric}(\nu, \nu)\big)\,da,

with ν\nu the unit normal. By the Gauss equation, on a surface in a three-manifold R−Ric⁡(ν,ν)=12R+Kamb(TΣ)=12R+KΣ−det⁡IIR - \operatorname{Ric}(\nu, \nu) = \frac12R + K_{\text{amb}}(T\Sigma) = \frac12R + K_\Sigma - \det\mathrm{II}, and on a minimal surface det⁡II=−12∣II∣2≤0\det\mathrm{II} = -\frac12|\mathrm{II}|^2 \leq 0 (Exercise 2.8). So

ddtArea⁡=−∫KΣ da−12∫(∣II∣2+R) da≤−4π−12Rmin⁡Area⁡,\frac{d}{dt}\operatorname{Area} = -\int K_\Sigma\,da - \frac12\int\big(|\mathrm{II}|^2 + R\big)\,da \leq -4\pi - \frac12R_{\min}\operatorname{Area},

by Gauss–Bonnet, ∫S2KΣ=4π\int_{S^2}K_\Sigma = 4\pi (branch points only help: the formula holds on the immersed part, and Gauss–Bonnet for branched immersions gives at least 4π4\pi). Since ff stays nontrivial at nearby times, W2(t)≤Area⁡g(t)f(S2)W_2(t) \leq \operatorname{Area}_{g(t)}f(S^2), which gives the forward difference quotient bound.

Continuity (Claim 18.13). Upper semicontinuity: a fixed sphere's area varies continuously with tt. Lower semicontinuity: if ∣Ric⁡∣≤D|\operatorname{Ric}| \leq D, areas change by at most a factor e2D∣t−t′∣e^{2D|t - t'|} (since ∣ddtArea⁡∣≤2DArea⁡|\frac{d}{dt}\operatorname{Area}| \leq 2D\operatorname{Area}; Morgan and Tian state it with e4De^{4D}), so minimal spheres at times tn→t′t_n \to t' give competitors at t′t' with area at most W2(tn)+o(1)W_2(t_n) + o(1).

Surgery times. For t′t' just before a surgery time tt, the surgery spheres are inessential, hence separating, and the surgery map ψt′:X(t′)→X(t)\psi_{t'} : \mathcal X(t') \to \mathcal X(t), the identity on the continuing region and mapping the rest into the caps, is a homotopy equivalence and (1+η)(1 + \eta)-Lipschitz for t′t' close to tt (Morgan and Tian's Proposition 15.12, from the distance-decreasing property of surgery in 12B.10 Surgery on a δ-Neck). So a minimal sphere at time t′t' maps to a nontrivial sphere at time tt of area at most (1+η)2W2(t′)(1 + \eta)^2W_2(t').

The 4π4\pi is topology: it is 2πχ(S2)2\pi\chi(S^2). The minimal sphere's area decreases because the Ricci flow shrinks the metric in the directions tangent to the sphere at a rate given by curvature, and Gauss–Bonnet turns the total intrinsic curvature of any sphere into the constant 4π4\pi.

Every component loses its π2\pi_2

Proposition 2.6 π2\pi_2 dies in finite time (Morgan–Tian, Proposition 18.9)

For a Ricci flow with surgery as in 12B.13 Ricci Flow with Surgery for All Time there is T1<∞T_1 < \infty such that every component of MTM_T, T≥T1T \geq T_1, has π2=0\pi_2 = 0. Each such component has finite fundamental group, with universal cover a homotopy 33-sphere, or has contractible universal cover.

Proof. Suppose a path of components X\mathcal X with π2≠0\pi_2 \neq 0 exists for all t≥T0t \geq T_0. Pinching gives Rmin⁡(t)≥−61+4tR_{\min}(t) \geq \frac{-6}{1 + 4t}, so W2W_2 is a subsolution of

w2′=−4π+3w21+4t,w_2' = -4\pi + \frac{3w_2}{1 + 4t},

in the sense of forward difference quotients, with jumps only downward at surgery times; by ODE comparison (Morgan–Tian, Lemma 2.22) W2≤w2W_2 \leq w_2 with w2(T0)=W2(T0)w_2(T_0) = W_2(T_0). The equation is linear, with integrating factor (1+4t)−3/4(1 + 4t)^{-3/4} (Exercise 2.9):

w2(t)=W2(T0)(1+4t)3/4(1+4T0)3/4+4π(1+4T0)1/4(1+4t)3/4−4π(1+4t).w_2(t) = W_2(T_0)\frac{(1 + 4t)^{3/4}}{(1 + 4T_0)^{3/4}} + 4\pi(1 + 4T_0)^{1/4}(1 + 4t)^{3/4} - 4\pi(1 + 4t).

The last term dominates: w2(t)→−∞w_2(t) \to -\infty, while W2>0W_2 > 0. Contradiction. So each of the finitely many components with nontrivial π2\pi_2 at time T0T_0 is gone, or has lost π2\pi_2, by a time T1T_1.

For the last statement: if π2(X)=0\pi_2(X) = 0 the universal cover X~\tilde X is 22-connected. If π1(X)\pi_1(X) is finite, X~\tilde X is a closed simply connected three-manifold, a homotopy sphere by Poincaré duality. If π1(X)\pi_1(X) is infinite, X~\tilde X is noncompact, so H3(X~)=0H_3(\tilde X) = 0, all homology vanishes, by Hurewicz all homotopy groups vanish (10A.4 Homotopy Groups, Degree and the Hurewicz Theorem), and by Whitehead X~\tilde X is contractible.

Notice that only finitely many surgeries are along essential spheres, but the proof never needs to know when they happen: the area argument works on each path of components, and the bound on T1T_1 comes from the finitely many components at time T0T_0. Notice too that nothing here uses the fundamental group hypothesis of Theorem 2.1: every Ricci flow with surgery on a closed three-manifold eventually has only components with π2=0\pi_2 = 0.

The sphere theorem

Corollary 2.7 The sphere theorem (Morgan–Tian, Corollary 18.14)

Let MM be a closed connected three-manifold with no embedded RP2\mathbb{RP}^2 with trivial normal bundle, and π2(M)≠0\pi_2(M) \neq 0. Then MM contains an embedded homotopically nontrivial 22-sphere.

Proof. Run the flow with surgery. By Proposition 2.6 some surgery must kill π2\pi_2: either it removes a component with nontrivial π2\pi_2, or it cuts along an essential sphere. Consider the first such surgery. The removed components with nontrivial π2\pi_2 are S2S^2-bundles over S1S^1 or RP3#RP3\mathbb{RP}^3\#\mathbb{RP}^3 (Remark 18.15), each containing an embedded essential sphere; or the surgery sphere itself is essential. Since all earlier sphere surgeries were along inessential spheres, which only split off homotopy spheres, this embedded essential sphere can be pulled back to MM.

The classical sphere theorem (Papakyriakopoulos, 1957) is proved by topology; here it falls out of geometry, an example of the Ricci flow proving topological theorems that were already known, as a test of its strength. Remark 18.15 also records what the flow does to a manifold without RP3\mathbb{RP}^3 summands and without non-separating spheres: by time T0T_0 it has performed a connected sum decomposition into components with π2=0\pi_2 = 0, that is, into prime pieces of the two kinds in the proposition.

In the world Analogy A soap film on a shrinking frame

Dip a wire frame into soap solution and the film spans it with least area. If the frame is slowly shrunk, the film shrinks with it. Here the frame is the manifold itself, shrunk by the Ricci flow wherever it is positively curved, and the film is the minimal sphere. The Gauss–Bonnet theorem says that a closed film always carries total curvature 4π4\pi, and the flow converts that curvature into a steady loss of area. A film of positive area cannot keep losing area at a fixed rate forever.

Where the picture breaks

The analogy breaks at negative curvature: there the flow expands the manifold, and the term −12Rmin⁡W2-\frac12R_{\min}W_2 can be positive. Pinching limits the damage to the factor 31+4t\frac{3}{1 + 4t}, which decays, so the constant loss 4π4\pi wins eventually. Without pinching (in higher dimensions, say) the argument would fail. And the "film" is not one surface followed in time: at each time the minimal sphere is chosen afresh, and only the minimum area is followed.

Where this goes The third homotopy group

Once π2=0\pi_2 = 0, the remaining nontrivial homotopy of a non-aspherical component is in π3\pi_3, and the same strategy needs a quantity built from it. 12C.3 Finite Extinction presents Perelman's choice (the maximal area of minimal disks spanning a sphere's worth of loops, which decreases at rate 2π2\pi) and Colding and Minicozzi's (the width of sweepouts by spheres), and 12C.4 Loops, Disks and Curve Shrinking proves Perelman's estimate rigorously with the curve-shrinking flow.

History

Hamilton used minimal disks and the Gauss–Bonnet estimate in "Non-singular solutions of the Ricci flow on three-manifolds" (1999, §11) to show that compressing disks for the boundary tori of hyperbolic pieces disappear in finite time. Perelman's third preprint (2003) applied the method to disks spanning loops, and Colding and Minicozzi (2005) to spheres in sweepouts. Morgan and Tian (2007, §18.2) added the separate treatment of π2\pi_2 with minimal spheres, using the Sacks–Uhlenbeck theory (1981), and derived the sphere theorem as a corollary.

Recall Where we stand

Finite extinction (for π1\pi_1 a free product of finite and infinite cyclic groups) gives the Poincaré and elliptization conjectures. The first stage: by Grushko's theorem a compact three-manifold has a bounded number of disjoint, essential, non-homotopic spheres, so only finitely many surgeries are along essential spheres; afterwards, components with nontrivial π2\pi_2 persist along unique paths. On such a path the minimal area W2W_2 of an essential sphere (realised by Sacks–Uhlenbeck) satisfies ddtW2≤−4π−12Rmin⁡W2\frac{d}{dt}W_2 \leq -4\pi - \frac12R_{\min}W_2, from the first variation of area, the Gauss equation for minimal surfaces and Gauss–Bonnet; it is continuous between surgeries and does not jump up at surgeries, which are distance non-increasing homotopy equivalences. With Rmin⁡≥−61+4tR_{\min} \geq -\frac{6}{1 + 4t} the comparison solution becomes negative, so every component eventually has π2=0\pi_2 = 0. The sphere theorem follows.

Exercises

Exercise 2.8 The Gauss equation on a minimal surface

Let Σ\Sigma be a surface in a Riemannian three-manifold with unit normal ν\nu, and e1,e2e_1, e_2 an orthonormal frame of TΣT\Sigma. (a) Show that R=2(K(e1,e2)+Ric⁡(ν,ν))R = 2\big(K(e_1, e_2) + \operatorname{Ric}(\nu, \nu)\big), so R−Ric⁡(ν,ν)=12R+K(e1,e2)R - \operatorname{Ric}(\nu, \nu) = \frac12R + K(e_1, e_2). (b) By the Gauss equation K(e1,e2)=KΣ−det⁡IIK(e_1, e_2) = K_\Sigma - \det\mathrm{II}. Show that on a minimal surface det⁡II=−12∣II∣2\det\mathrm{II} = -\frac12|\mathrm{II}|^2. (c) Deduce the formula for ddtArea⁡\frac{d}{dt}\operatorname{Area} in the proof of Lemma 2.5.

Solution

(a) R=2∑i<jK(ei,ej)R = 2\sum_{i<j}K(e_i, e_j) over an orthonormal frame e1,e2,e3=νe_1, e_2, e_3 = \nu, and Ric⁡(ν,ν)=K(e1,ν)+K(e2,ν)\operatorname{Ric}(\nu, \nu) = K(e_1, \nu) + K(e_2, \nu); so R=2K(e1,e2)+2Ric⁡(ν,ν)R = 2K(e_1, e_2) + 2\operatorname{Ric}(\nu, \nu). (b) With principal curvatures κ1+κ2=0\kappa_1 + \kappa_2 = 0: det⁡II=κ1κ2=−κ12=−12(κ12+κ22)=−12∣II∣2\det\mathrm{II} = \kappa_1\kappa_2 = -\kappa_1^2 = -\frac12(\kappa_1^2 + \kappa_2^2) = -\frac12|\mathrm{II}|^2. (c) −∫(R−Ric⁡(ν,ν))=−∫(12R+KΣ+12∣II∣2)-\int(R - \operatorname{Ric}(\nu, \nu)) = -\int(\frac12R + K_\Sigma + \frac12|\mathrm{II}|^2).

Exercise 2.9 Integrating the comparison equation

Solve w′=−4π+3w1+4tw' = -4\pi + \frac{3w}{1 + 4t}, w(T0)=W0w(T_0) = W_0, and show that w(t)<0w(t) < 0 for tt large. Estimate how large, when T0=0T_0 = 0 and W0=AW_0 = A. Compare with the case Rmin⁡≥0R_{\min} \geq 0, where w′=−4πw' = -4\pi.

Solution

With u=(1+4t)−3/4wu = (1 + 4t)^{-3/4}w: u′=(1+4t)−3/4(w′−3w1+4t)=−4π(1+4t)−3/4u' = (1 + 4t)^{-3/4}(w' - \frac{3w}{1 + 4t}) = -4\pi(1 + 4t)^{-3/4}, so u(t)=u(T0)−4π∫T0t(1+4s)−3/4ds=u(T0)−4π((1+4t)1/4−(1+4T0)1/4)u(t) = u(T_0) - 4\pi\int_{T_0}^t(1 + 4s)^{-3/4}ds = u(T_0) - 4\pi\big((1 + 4t)^{1/4} - (1 + 4T_0)^{1/4}\big). Multiplying back gives the formula in the text. With T0=0T_0 = 0: w(t)=(A+4π)(1+4t)3/4−4π(1+4t)w(t) = (A + 4\pi)(1 + 4t)^{3/4} - 4\pi(1 + 4t), negative once (1+4t)1/4>1+A4π(1 + 4t)^{1/4} > 1 + \frac{A}{4\pi}, that is t>14((1+A4π)4−1)t > \frac14\big((1 + \frac{A}{4\pi})^4 - 1\big). With Rmin⁡≥0R_{\min} \geq 0, w=A−4πtw = A - 4\pi t, negative after A4π\frac{A}{4\pi}: a much shorter time. The negative curvature allowed by pinching delays extinction polynomially but cannot prevent it.

Exercise 2.10 The cylinder S2×S1S^2\times S^1

Let M=S2×S1M = S^2\times S^1 with the product of a round sphere of radius aa and a circle of length LL. (a) What is W2W_2? (b) Under Ricci flow, a(t)2=a2−2ta(t)^2 = a^2 - 2t and LL is constant. Compute ddtW2\frac{d}{dt}W_2 and compare with the lemma. (c) What happens at t=a22t = \frac{a^2}{2}?

Solution

(a) The essential spheres include the fibres S2×{θ}S^2\times\{\theta\}, of area 4πa24\pi a^2, which is the minimum (an essential sphere maps with nonzero degree onto the S2S^2 factor, and projection to S2S^2 does not increase area). (b) W2=4π(a2−2t)W_2 = 4\pi(a^2 - 2t), so ddtW2=−8π\frac{d}{dt}W_2 = -8\pi. The lemma gives −4π−12Rmin⁡W2=−4π−12⋅2a2−2t⋅4π(a2−2t)=−8π-4\pi - \frac12R_{\min}W_2 = -4\pi - \frac12\cdot\frac{2}{a^2 - 2t}\cdot4\pi(a^2 - 2t) = -8\pi: equality, because the fibre is totally geodesic (II=0\mathrm{II} = 0) and RR is constant. (c) The whole manifold becomes singular and is removed by surgery (it is a component covered by necks), consistent with W2→0W_2 \to 0.

Exercise 2.11 Counting free factors

(a) Show that the free group of rank rr is a free product of exactly rr nontrivial factors in its standard decomposition, and that it cannot be a free product of more than rr nontrivial factors. (b) Use Grushko's theorem to show that Z/2∗Z/3\mathbb{Z}/2*\mathbb{Z}/3 is not a free product of three nontrivial groups. (c) In #i=1r(S2×S1)\#_{i=1}^r(S^2\times S^1), exhibit a homotopically essential family of rr spheres. Can there be more?

Solution

(a) By Grushko's theorem the minimal number of generators is additive under free products. A nontrivial group needs at least one generator, so a free product of mm nontrivial groups needs at least mm generators; FrF_r is generated by rr elements, so m≤rm \leq r, with equality for Z∗⋯∗Z\mathbb{Z}*\cdots*\mathbb{Z}. (b) Z/2∗Z/3\mathbb{Z}/2*\mathbb{Z}/3 is generated by 22 elements, so it has at most 22 nontrivial free factors. (c) The spheres S2×{θi}S^2\times\{\theta_i\}, one in each summand: each is non-separating, hence essential, and no two are homotopic (they are dual to different generators of H1H_1). For r≥2r \geq 2 one can add separating spheres between summands (each complementary piece has π1≠1\pi_1 \neq 1, so they are essential and not homotopic to the fibres), so a maximal family is larger than rr, but still bounded by Lemma 2.2. For r=1r = 1 the fibre is all there is: any two disjoint fibres are homotopic.

Exercise 2.12 Hamilton's disks

Schematically, Hamilton's estimate for a minimal disk DD with boundary on a torus, moving with the torus, has the form ddtArea⁡(D)≤−2π−12Rmin⁡Area⁡(D)+(boundary terms)\frac{d}{dt}\operatorname{Area}(D) \leq -2\pi - \frac12R_{\min}\operatorname{Area}(D) + (\text{boundary terms}). (a) Where does 2π2\pi instead of 4π4\pi come from? (b) Why does a boundary term appear, and why can it be controlled when the boundary lies on a totally geodesic (or nearly so) torus?

Solution

(a) Gauss–Bonnet for a disk: ∫DK+∫∂Dkg=2πχ(D)=2π\int_DK + \int_{\partial D}k_g = 2\pi\chi(D) = 2\pi. (b) The first variation of area has a boundary term from the motion of the boundary, and the Gauss–Bonnet formula has the geodesic curvature of the boundary. If the boundary moves within a nearly totally geodesic, nearly flat torus that the flow keeps nearly stationary up to scaling, these terms are small compared with 2π2\pi. Perelman's disks have boundaries on loops that move by curve shortening, which makes the geodesic curvature term exactly cancel, as 12C.4 Loops, Disks and Curve Shrinking shows.

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