Book 4A

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Course 4Book 4A: Function Spaces and Sobolev SpacesChapter 13

Unbounded Operators and the Spectral Theorem

Closed operators and adjoints, symmetric versus self-adjoint, the Friedrichs extension, Kato–Rellich, the functional calculus and Stone's theorem: the operator theory of the Laplacian, Schrödinger operators and −4Δ + R.

39 min read · Updated Oct 24, 2026

Read with Reed and Simon, Methods of Modern Mathematical Physics I: Functional Analysis, chapter VIII (unbounded operators, the basic criterion, the spectral theorem in multiplication form, Stone's theorem) and §X.1–X.3 of volume II (Kato–Rellich, the Friedrichs extension); or Brezis §7.1–7.2 for the Hilbert-space basics; or Schmüdgen, Unbounded Self-adjoint Operators on Hilbert Space, chapters 3, 5 and 10, which is the most complete modern account.

In this chapter · 10 sections
  1. 13.1Observables and boundary conditions
  2. 13.2Unbounded operators, graphs and closures
  3. 13.3Symmetric and self-adjoint
  4. 13.4The Friedrichs extension
  5. 13.5The spectral theorem
  6. 13.6Perturbations: Kato–Rellich
  7. 13.7Min–max
  8. 13.8The operator −4Δ+R-4\Delta + R−4Δ+R
  9. 13.9History
  10. 13.10Exercises
  11. ↗Free resources

The operators that matter most in analysis and geometry are unbounded. Differentiation is unbounded on every LpL^p space (4A.1 Banach Spaces and Bounded Operators); the Laplacian, the Schrödinger operators of quantum mechanics −Δ+V-\Delta + V, and Perelman's operator −4Δ+R-4\Delta + R (12A.2 Ricci Flow as a Gradient Flow) are all defined only on a dense subspace of L2L^2, and on that subspace they can make norms arbitrarily large. Yet we want to treat them like symmetric matrices: diagonalise them, take their square roots and exponentials, solve ∂tu=Δu\partial_tu = \Delta u by u=etΔu0u = e^{t\Delta}u_0 and i∂tψ=Hψi\partial_t\psi = H\psi by ψ=e−itHψ0\psi = e^{-itH}\psi_0.

This works, but only for a carefully defined class: the self-adjoint operators. The distinction between "symmetric" (⟨Au,v⟩=⟨u,Av⟩\langle Au, v\rangle = \langle u, Av\rangle on the domain) and "self-adjoint" (symmetric with the right domain) is invisible for matrices and decisive for differential operators. It is where boundary conditions live: −d2dx2-\frac{d^2}{dx^2} on an interval is symmetric on smooth functions vanishing near the ends, and it has many self-adjoint extensions, one for each physically meaningful boundary condition, each with its own spectrum. This chapter develops the theory needed to make these statements precise, and proves the spectral theorem in the form in which the rest of the guide uses it.

By the end of this chapter you will be able to:

  • work with closed and closable operators and with adjoints of densely defined operators, and compute the closure of a differential operator;
  • distinguish symmetric from self-adjoint operators, and prove the basic criterion Ran⁡(A±i)=H\operatorname{Ran}(A \pm i) = H;
  • construct the Friedrichs extension of a semibounded symmetric operator, and identify it for the Laplacian as the Dirichlet Laplacian;
  • prove the spectral theorem for self-adjoint operators with compact resolvent, define the functional calculus f(A)f(A), and use it for e−tAe^{-tA}, e−itAe^{-itA} and AsA^s; state the general spectral theorem and Stone's theorem;
  • prove the Kato–Rellich theorem and use it to show that atomic Hamiltonians are self-adjoint;
  • prove the min–max characterisation of eigenvalues, and apply all of this to −4Δ+R-4\Delta + R on a closed manifold.

Observables and boundary conditions

In the world Model The rules of quantum mechanics

In quantum mechanics, the state of a system is a unit vector ψ\psi in a Hilbert space, observable quantities are self-adjoint operators, the possible measured values of an observable are the points of its spectrum, and time evolution is ψ(t)=e−itH/ℏψ(0)\psi(t) = e^{-itH/\hbar}\psi(0) for the energy operator HH, the Hamiltonian. For a particle in R3\mathbb{R}^3 in a potential VV, H=−ℏ22mΔ+VH = -\frac{\hbar^2}{2m}\Delta + V. John von Neumann made these rules precise in his 1932 book Mathematische Grundlagen der Quantenmechanik, and created the theory of unbounded self-adjoint operators to do it. The discrete energy levels of the hydrogen atom, En=−13.6 eVn2E_n = -\frac{13.6\text{ eV}}{n^2}, observed as spectral lines since Balmer (1885), are the eigenvalues of −ℏ22mΔ−e24πε0∣x∣-\frac{\hbar^2}{2m}\Delta - \frac{e^2}{4\pi\varepsilon_0|x|}.

Where the picture breaks

"Self-adjoint" is not a technicality that physics can ignore. A symmetric operator that is not self-adjoint does not determine a unitary time evolution: the evolution depends on a choice of extension, that is, on extra physical input such as a boundary condition at a wall, or at a singularity of the potential. Kato's 1951 theorem that atomic Hamiltonians are self-adjoint on their natural domain, proved below, is the statement that for atoms no such choice is needed: the Coulomb singularity is mild enough.

Unbounded operators, graphs and closures

An operator AA on a Hilbert space HH is a linear map A:D(A)→HA : D(A) \to H from a subspace D(A)D(A), its domain; it is densely defined if D(A)D(A) is dense. Two operators are equal only if their domains are; BB extends AA, written A⊆BA \subseteq B, if D(A)⊆D(B)D(A) \subseteq D(B) and B=AB = A on D(A)D(A). The graph Γ(A)={(u,Au):u∈D(A)}\Gamma(A) = \{(u, Au) : u \in D(A)\} is a subspace of H×HH\times H.

Definition 13.1 Closed and closable operators

AA is closed if its graph is closed in H×HH\times H: whenever uk∈D(A)u_k \in D(A), uk→uu_k \to u and Auk→vAu_k \to v, then u∈D(A)u \in D(A) and Au=vAu = v. AA is closable if the closure of its graph is the graph of an operator, the closure Aˉ\bar A; equivalently, uk→0u_k \to 0 and Auk→vAu_k \to v imply v=0v = 0.

By the closed graph theorem (4A.2 Baire Category and Its Consequences), a closed operator defined on all of HH is bounded. So unbounded closed operators are necessarily defined only on a proper subspace: the domain is part of the operator.

Example 13.2 The derivative and its closure

On H=L2(0,1)H = L^2(0, 1), let A0u=u′A_0u = u' with D(A0)=C1([0,1])D(A_0) = C^1([0, 1]). It is not closed: smooth functions converging in H1H^1 to a function with a corner have convergent derivatives but a limit outside C1C^1. It is closable: if uk→0u_k \to 0 in L2L^2 and uk′→vu_k' \to v in L2L^2, then for every test function ϕ\phi, ∫vϕ=lim⁡∫uk′ϕ=−lim⁡∫ukϕ′=0\int v\phi = \lim\int u_k'\phi = -\lim\int u_k\phi' = 0, so v=0v = 0. Its closure is Aˉ0u=u′\bar A_0u = u' with D(Aˉ0)=H1(0,1)D(\bar A_0) = H^1(0, 1): the graph norm (∥u∥2+∥u′∥2)1/2(\|u\|^2 + \|u'\|^2)^{1/2} is the H1H^1 norm (4A.10 Sobolev Spaces), C1C^1 is dense in H1H^1, and H1H^1 is complete. Closing a differential operator means passing to a Sobolev space.

The adjoint. For densely defined AA, let D(A∗)D(A^*) be the set of v∈Hv \in H for which u↦⟨Au,v⟩u \mapsto \langle Au, v\rangle is bounded on D(A)D(A); by Riesz (4A.5 Hilbert Spaces and Lax–Milgram) there is then a unique A∗vA^*v with ⟨Au,v⟩=⟨u,A∗v⟩\langle Au, v\rangle = \langle u, A^*v\rangle for all u∈D(A)u \in D(A). Density of D(A)D(A) makes A∗vA^*v unique. Basic facts (Exercise 13.15):

  • A∗A^* is always closed: its graph {(v,w):⟨Au,v⟩=⟨u,w⟩ ∀u∈D(A)}\{(v, w) : \langle Au, v\rangle = \langle u, w\rangle\ \forall u \in D(A)\} is the orthogonal complement (JΓ(A))⊥(J\Gamma(A))^\perp, with J(x,y)=(−y,x)J(x, y) = (-y, x).
  • AA is closable exactly when A∗A^* is densely defined, and then Aˉ=A∗∗\bar A = A^{**}.
  • A⊆BA \subseteq B implies B∗⊆A∗B^* \subseteq A^*: extending an operator shrinks its adjoint.

Symmetric and self-adjoint

Definition 13.3 Symmetric, self-adjoint, essentially self-adjoint

A densely defined AA is symmetric if ⟨Au,v⟩=⟨u,Av⟩\langle Au, v\rangle = \langle u, Av\rangle for u,v∈D(A)u, v \in D(A), that is A⊆A∗A \subseteq A^*. It is self-adjoint if A=A∗A = A^*, domains included. It is essentially self-adjoint if its closure is self-adjoint.

For a symmetric AA, A⊆Aˉ=A∗∗⊆A∗A \subseteq \bar A = A^{**} \subseteq A^*. Extending a symmetric operator enlarges its domain and shrinks its adjoint's; self-adjointness is the moment the two meet. A self-adjoint operator has no proper symmetric extension (A⊆B⊆B∗⊆A∗=AA \subseteq B \subseteq B^* \subseteq A^* = A), so self-adjoint operators are maximal symmetric. An essentially self-adjoint operator has exactly one self-adjoint extension, its closure.

Example 13.4 Momentum on an interval and on a half-line

On L2(0,1)L^2(0, 1) let Pu=−iu′Pu = -iu' on D(P)={u∈H1:u(0)=u(1)=0}D(P) = \{u \in H^1 : u(0) = u(1) = 0\}. Integrating by parts, ⟨Pu,v⟩=⟨u,−iv′⟩\langle Pu, v\rangle = \langle u, -iv'\rangle for all v∈H1v \in H^1, since the boundary terms vanish because uu does; so P∗v=−iv′P^*v = -iv' on D(P∗)=H1D(P^*) = H^1, strictly larger than D(P)D(P). PP is symmetric and closed but not self-adjoint. Its self-adjoint extensions are PαP_\alpha on {u∈H1:u(1)=eiαu(0)}\{u \in H^1 : u(1) = e^{i\alpha}u(0)\}, α∈[0,2π)\alpha \in [0, 2\pi): one for each "twisted periodic" boundary condition, with spectrum {α+2πk:k∈Z}\{\alpha + 2\pi k : k \in \mathbb{Z}\} (Exercise 13.16). On the half-line L2(0,∞)L^2(0, \infty), −iddx-i\frac{d}{dx} on {u∈H1:u(0)=0}\{u \in H^1 : u(0) = 0\} has no self-adjoint extension at all: the solutions of −iu′=±iu-iu' = \pm iu, namely e∓xe^{\mp x}, are in L2L^2 for one sign only, and von Neumann's theory (below) says the two counts must match.

The physical meaning: momentum generates translations, and a particle on a half-line cannot be translated past the wall without losing probability, so there is no unitary translation group and no self-adjoint momentum.

Von Neumann's theory. For a closed symmetric AA, the deficiency spaces K±=ker⁡(A∗∓i)K_\pm = \ker(A^* \mp i) have dimensions n±n_\pm, the deficiency indices. Von Neumann proved (1929): AA is self-adjoint iff n+=n−=0n_+ = n_- = 0; AA has self-adjoint extensions iff n+=n−n_+ = n_-, and they correspond to unitary maps K+→K−K_+ \to K_-. For the momentum on (0,1)(0, 1), n±=1n_\pm = 1 and the extensions are the circle of PαP_\alpha; on the half-line n+=1≠n−=0n_+ = 1 \neq n_- = 0.

The case n±=0n_\pm = 0 is the one used in practice, and it has a direct proof.

Theorem 13.5 The basic criterion

For a symmetric operator AA, the following are equivalent: (a) AA is self-adjoint; (b) AA is closed and ker⁡(A∗±i)=0\ker(A^* \pm i) = 0; (c) Ran⁡(A±i)=H\operatorname{Ran}(A \pm i) = H.

Proof. Key identity. For u∈D(A)u \in D(A), symmetry makes ⟨Au,u⟩\langle Au, u\rangle real, so ∥(A±i)u∥2=∥Au∥2+∥u∥2\|(A \pm i)u\|^2 = \|Au\|^2 + \|u\|^2. Hence A±iA \pm i is injective, and if AA is closed its range is closed (if (A+i)uk(A + i)u_k converges, then uku_k and AukAu_k are Cauchy).

(a)⇒(b): if A∗v=∓ivA^*v = \mp iv then Av=∓ivAv = \mp iv and ∥(A±i)v∥=0\|(A \pm i)v\| = 0, so v=0v = 0; adjoints are closed.

(b)⇒(c): Ran⁡(A±i)⊥=ker⁡(A∗∓i)=0\operatorname{Ran}(A \pm i)^\perp = \ker(A^* \mp i) = 0, and the range is closed, so it is HH.

(c)⇒(a): let v∈D(A∗)v \in D(A^*). By (c) pick u∈D(A)u \in D(A) with (A−i)u=(A∗−i)v(A - i)u = (A^* - i)v. Since A⊆A∗A \subseteq A^*, (A∗−i)(v−u)=0(A^* - i)(v - u) = 0. For any w∈D(A)w \in D(A), ⟨v−u,(A+i)w⟩=⟨(A∗−i)(v−u),w⟩=0\langle v - u, (A + i)w\rangle = \langle(A^* - i)(v - u), w\rangle = 0, and (A+i)(A + i) is onto, so v=u∈D(A)v = u \in D(A). So D(A∗)=D(A)D(A^*) = D(A).

Proposition 13.6 Spectrum of a self-adjoint operator

If AA is self-adjoint, then A−z:D(A)→HA - z : D(A) \to H is bijective for every non-real zz, with ∥(A−z)−1∥≤1∣Im⁡z∣\|(A - z)^{-1}\| \leq \frac{1}{|\operatorname{Im}z|}. In particular the spectrum σ(A)={z:A−z has no bounded inverse}\sigma(A) = \{z : A - z \text{ has no bounded inverse}\} is a closed subset of R\mathbb{R}.

Proof. With z=a+ibz = a + ib, b≠0b \neq 0, ∥(A−z)u∥2=∥(A−a)u∥2+b2∥u∥2≥b2∥u∥2\|(A - z)u\|^2 = \|(A - a)u\|^2 + b^2\|u\|^2 \geq b^2\|u\|^2, using that A−aA - a is symmetric. Surjectivity follows by applying the basic criterion to the self-adjoint operator A−a∣b∣\frac{A - a}{|b|}.

The Friedrichs extension

For differential operators, the most useful way to produce a self-adjoint operator is through its quadratic form, where Lax–Milgram (4A.5 Hilbert Spaces and Lax–Milgram) does the work.

Theorem 13.7 Friedrichs extension (Friedrichs 1934)

Let AA be symmetric and semibounded: ⟨Au,u⟩≥−c∥u∥2\langle Au, u\rangle \geq -c\|u\|^2 for u∈D(A)u \in D(A). Then AA has a self-adjoint extension AFA_F with the same lower bound, obtained as follows. Complete D(A)D(A) in the norm ∥u∥q2=⟨Au,u⟩+(c+1)∥u∥2\|u\|_q^2 = \langle Au, u\rangle + (c + 1)\|u\|^2 to a Hilbert space Q⊆HQ \subseteq H; then D(AF)={u∈Q:v↦q(u,v) is H-bounded on Q}D(A_F) = \{u \in Q : v \mapsto q(u, v) \text{ is } H\text{-bounded on } Q\}, where qq is the extended form, and AFA_F is the operator represented by qq.

Proof. Replace AA by A+c+1A + c + 1, so that ⟨Au,u⟩≥∥u∥2\langle Au, u\rangle \geq \|u\|^2 and ∥u∥q2=⟨Au,u⟩\|u\|_q^2 = \langle Au, u\rangle.

The completion embeds in HH. The form norm dominates the HH norm, so a ∥⋅∥q\|\cdot\|_q-Cauchy sequence converges in HH; the issue is that two Cauchy sequences with the same HH-limit have the same QQ-limit. If uku_k is qq-Cauchy with uk→0u_k \to 0 in HH, then ∥uk∥q2=⟨Auk,uk−um⟩+⟨Auk,um⟩\|u_k\|_q^2 = \langle Au_k, u_k - u_m\rangle + \langle Au_k, u_m\rangle; the first term is at most ∥uk∥q∥uk−um∥q\|u_k\|_q\|u_k - u_m\|_q (Cauchy–Schwarz for the form), small for k,mk, m large, and the second tends to 00 as m→∞m \to \infty for fixed kk, since um→0u_m \to 0 in HH. So ∥uk∥q→0\|u_k\|_q \to 0. Here symmetry of AA is what makes the form positive and the argument work.

The operator. For f∈Hf \in H, v↦⟨v,f⟩v \mapsto \langle v, f\rangle is bounded on QQ (as ∥v∥≤∥v∥q\|v\| \leq \|v\|_q), so by Riesz in QQ there is a unique u=Gf∈Qu = Gf \in Q with q(u,v)=⟨u,v⟩q=⟨f,v⟩q(u, v) = \langle u, v\rangle_q = \langle f, v\rangle for all v∈Qv \in Q. G:H→HG : H \to H is bounded (∥Gf∥≤∥Gf∥q≤∥f∥\|Gf\| \leq \|Gf\|_q \leq \|f\|), injective, and symmetric: ⟨Gf,g⟩=q(Gf,Gg)=⟨f,Gg⟩\langle Gf, g\rangle = q(Gf, Gg) = \langle f, Gg\rangle. So GG is a bounded self-adjoint injective operator, and AF=G−1A_F = G^{-1}, on D(AF)=Ran⁡GD(A_F) = \operatorname{Ran}G, is self-adjoint (the inverse of an injective self-adjoint operator is self-adjoint, Exercise 13.17). For u∈D(A)u \in D(A) and v∈Qv \in Q, q(u,v)=⟨Au,v⟩q(u, v) = \langle Au, v\rangle, so GAu=uGAu = u: A⊆AFA \subseteq A_F. And ⟨AFu,u⟩=q(u,u)≥∥u∥2\langle A_Fu, u\rangle = q(u, u) \geq \|u\|^2.

Example 13.8 The Dirichlet Laplacian

Let Ω⊆Rn\Omega \subseteq \mathbb{R}^n be open and bounded, A=−ΔA = -\Delta on D(A)=Cc∞(Ω)D(A) = C_c^\infty(\Omega), which is symmetric and nonnegative: ⟨−Δu,u⟩=∫∣∇u∣2\langle-\Delta u, u\rangle = \int|\nabla u|^2. The form norm is the H1H^1 norm, the completion QQ is H01(Ω)H^1_0(\Omega) (4A.10 Sobolev Spaces), and AF=−ΔDA_F = -\Delta_D, the Dirichlet Laplacian: u∈D(−ΔD)u \in D(-\Delta_D) iff u∈H01u \in H^1_0 and Δu∈L2\Delta u \in L^2 in the sense of distributions, with −ΔDu=−Δu-\Delta_Du = -\Delta u. For smooth bounded Ω\Omega, elliptic regularity (6A.6 Weak Solutions and Elliptic Regularity) gives D(−ΔD)=H2∩H01D(-\Delta_D) = H^2\cap H^1_0. Other boundary conditions give other self-adjoint extensions: completing in H1(Ω)H^1(\Omega) with the form ∫∣∇u∣2\int|\nabla u|^2 gives the Neumann Laplacian (Exercise 13.18). The Friedrichs extension always picks the Dirichlet condition: it is the extension whose form domain is the smallest.

The spectral theorem

With compact resolvent. Most operators in this guide have compact resolvent: (A−z)−1(A - z)^{-1} is compact for some, hence every, zz in the resolvent set. This happens for the Dirichlet Laplacian on a bounded domain (Rellich's theorem makes H01↪L2H^1_0 \hookrightarrow L^2 compact, 4A.11 Sobolev Embeddings and Critical Exponents) and for −Δ+V-\Delta + V on a closed manifold. Then the spectral theorem for compact self-adjoint operators (4A.8 Compact Operators and Spectra) does everything.

Theorem 13.9 Self-adjoint operators with compact resolvent

Let AA be self-adjoint, bounded below, with compact resolvent, on a separable infinite-dimensional Hilbert space. Then there is an orthonormal basis (ek)(e_k) of HH with ek∈D(A)e_k \in D(A), Aek=λkekAe_k = \lambda_ke_k, λ1≤λ2≤⋯→∞\lambda_1 \leq \lambda_2 \leq \dots \to \infty, each eigenvalue of finite multiplicity, and

D(A)={u:∑λk2∣⟨u,ek⟩∣2<∞},Au=∑λk⟨u,ek⟩ek.D(A) = \Big\{u : \sum\lambda_k^2|\langle u, e_k\rangle|^2 < \infty\Big\}, \qquad Au = \sum\lambda_k\langle u, e_k\rangle e_k.

Proof. Choose cc with A+c≥1A + c \geq 1. Then G=(A+c)−1G = (A + c)^{-1} is compact, self-adjoint, injective and positive, so it has an orthonormal eigenbasis eke_k with eigenvalues μk↓0\mu_k \downarrow 0, μk>0\mu_k > 0 (4A.8 Compact Operators and Spectra). From Gek=μkekGe_k = \mu_ke_k, ek∈Ran⁡G=D(A)e_k \in \operatorname{Ran}G = D(A) and Aek=(μk−1−c)ekAe_k = (\mu_k^{-1} - c)e_k. For u∈D(A)u \in D(A), ⟨Au,ek⟩=⟨u,Aek⟩=λk⟨u,ek⟩\langle Au, e_k\rangle = \langle u, Ae_k\rangle = \lambda_k\langle u, e_k\rangle, so AuAu has the stated expansion and the coefficients are square summable; conversely if they are, u=G(∑(λk+c)⟨u,ek⟩ek)∈D(A)u = G\big(\sum(\lambda_k + c)\langle u, e_k\rangle e_k\big) \in D(A).

Functional calculus. For any Borel function ff on the spectrum, define

f(A)u=∑kf(λk)⟨u,ek⟩ek,D(f(A))={u:∑∣f(λk)∣2∣⟨u,ek⟩∣2<∞}.f(A)u = \sum_kf(\lambda_k)\langle u, e_k\rangle e_k, \qquad D(f(A)) = \Big\{u : \sum|f(\lambda_k)|^2|\langle u, e_k\rangle|^2 < \infty\Big\}.

Then f↦f(A)f \mapsto f(A) is an algebra homomorphism, ∥f(A)∥=sup⁡k∣f(λk)∣\|f(A)\| = \sup_k|f(\lambda_k)| for bounded ff, fˉ(A)=f(A)∗\bar f(A) = f(A)^*, and real ff give self-adjoint operators. Three choices of ff are used constantly.

  • f(λ)=e−tλf(\lambda) = e^{-t\lambda}: the heat semigroup e−tAe^{-tA}, t≥0t \geq 0. For A=−ΔDA = -\Delta_D, u(t)=etΔu0u(t) = e^{t\Delta}u_0 solves the heat equation with Dirichlet conditions: u(t)=∑e−tλk⟨u0,ek⟩eku(t) = \sum e^{-t\lambda_k}\langle u_0, e_k\rangle e_k, Fourier's own solution (2B.7 Fourier Series and the First Heat Equation), now justified for every u0∈L2u_0 \in L^2. It is a contraction, ∥etΔ∥=e−tλ1≤1\|e^{t\Delta}\| = e^{-t\lambda_1} \leq 1, and smoothing: ∥Ae−tA∥=sup⁡kλke−tλk≤1et\|Ae^{-tA}\| = \sup_k\lambda_ke^{-t\lambda_k} \leq \frac{1}{et} for A≥0A \geq 0, which says that after any positive time the solution is in the domain of every power of AA, hence smooth by elliptic regularity.
  • f(λ)=e−itλf(\lambda) = e^{-it\lambda}: the unitary group e−itAe^{-itA}, solving the Schrödinger equation i∂tψ=Aψi\partial_t\psi = A\psi. It preserves norms and does not smooth.
  • f(λ)=λsf(\lambda) = \lambda^s for A≥0A \geq 0: fractional powers, such as (−Δ)1/2(-\Delta)^{1/2}, the Dirichlet-to-Neumann type operator of 4A.12 Interpolation and Fractional Sobolev Spaces, and (−Δ)−1(-\Delta)^{-1}, the solution operator of the Poisson equation.

The general spectral theorem. Without compact resolvent, the spectrum can be continuous (for −Δ-\Delta on Rn\mathbb{R}^n it is [0,∞)[0, \infty) with no eigenvalues at all), and sums become integrals.

Theorem 13.10 Spectral theorem, multiplication form (von Neumann 1929; statement)

For every self-adjoint AA on a separable Hilbert space HH there are a σ\sigma-finite measure space (Σ,μ)(\Sigma, \mu), a real measurable function aa on Σ\Sigma, and a unitary U:H→L2(Σ,μ)U : H \to L^2(\Sigma, \mu) such that UAU−1UAU^{-1} is multiplication by aa, with domain {ϕ:aϕ∈L2}\{\phi : a\phi \in L^2\}.

For A=−ΔA = -\Delta on L2(Rn)L^2(\mathbb{R}^n), UU is the Fourier transform and a(ξ)=4π2∣ξ∣2a(\xi) = 4\pi^2|\xi|^2 (4A.6 The Fourier Transform): the Fourier transform diagonalises the Laplacian, and the functional calculus is the Fourier multiplier calculus of 4A.12 Interpolation and Fractional Sobolev Spaces. In general f(A)=U−1f(a)Uf(A) = U^{-1}f(a)U. The equivalent "projection-valued measure" form writes A=∫λ dE(λ)A = \int\lambda\,dE(\lambda).

Theorem 13.11 Stone's theorem (1932)

If AA is self-adjoint, U(t)=e−itAU(t) = e^{-itA} is a strongly continuous one-parameter group of unitary operators, and AA is recovered as Au=ilim⁡t→0U(t)u−utAu = i\lim_{t\to0}\frac{U(t)u - u}{t} on the set of uu where the limit exists. Conversely, every strongly continuous one-parameter unitary group is e−itAe^{-itA} for a unique self-adjoint AA.

The forward direction is immediate from the multiplication form and dominated convergence (Exercise 13.19). Stone's theorem is why observables generate symmetries in quantum mechanics: momentum generates translations, angular momentum rotations, energy time evolution; and why the momentum on a half-line, which cannot generate translations, cannot be self-adjoint.

Perturbations: Kato–Rellich

To prove self-adjointness of −Δ+V-\Delta + V, one perturbs the known self-adjoint −Δ-\Delta.

Theorem 13.12 Kato–Rellich theorem

Let AA be self-adjoint and BB symmetric with D(A)⊆D(B)D(A) \subseteq D(B) and

∥Bu∥≤a∥Au∥+b∥u∥(u∈D(A))\|Bu\| \leq a\|Au\| + b\|u\| \qquad (u \in D(A))

for some a<1a < 1 and b≥0b \geq 0 (AA-bounded with relative bound less than 11). Then A+BA + B is self-adjoint on D(A)D(A). If AA is bounded below, so is A+BA + B.

Proof. By the basic criterion it suffices to show Ran⁡(A+B±iμ)=H\operatorname{Ran}(A + B \pm i\mu) = H for some μ>0\mu > 0 (apply the criterion to A+Bμ\frac{A + B}{\mu}). Write A+B±iμ=(I+B(A±iμ)−1)(A±iμ)A + B \pm i\mu = \big(I + B(A \pm i\mu)^{-1}\big)(A \pm i\mu). The second factor maps D(A)D(A) onto HH. For the first, with u=(A±iμ)−1fu = (A \pm i\mu)^{-1}f, ∥Au∥2+μ2∥u∥2=∥f∥2\|Au\|^2 + \mu^2\|u\|^2 = \|f\|^2 gives ∥Au∥≤∥f∥\|Au\| \leq \|f\| and ∥u∥≤∥f∥μ\|u\| \leq \frac{\|f\|}{\mu}, so ∥B(A±iμ)−1f∥≤(a+bμ)∥f∥\|B(A \pm i\mu)^{-1}f\| \leq (a + \frac b\mu)\|f\|. For μ\mu large this is less than 11, and the Neumann series (4A.1 Banach Spaces and Bounded Operators) makes I+B(A±iμ)−1I + B(A \pm i\mu)^{-1} invertible on HH. So A+B±iμA + B \pm i\mu is onto.

Example 13.13 The hydrogen atom (Kato 1951)

On L2(R3)L^2(\mathbb{R}^3), H=−Δ−1∣x∣H = -\Delta - \frac{1}{|x|} (in units where the constants are 11) is self-adjoint on D(−Δ)=H2(R3)D(-\Delta) = H^2(\mathbb{R}^3). The Coulomb potential is not bounded, but it is Δ\Delta-bounded with relative bound 00. Split 1∣x∣=V1+V2\frac1{|x|} = V_1 + V_2 with V1=1∣x∣1∣x∣<RV_1 = \frac{1}{|x|}\mathbf 1_{|x|<R} in L2L^2 and V2V_2 bounded by 1R\frac1R. In three dimensions H2⊆L∞H^2 \subseteq L^\infty with ∥u∥∞≤ϵ∥Δu∥2+Cϵ∥u∥2\|u\|_\infty \leq \epsilon\|\Delta u\|_2 + C_\epsilon\|u\|_2 for every ϵ>0\epsilon > 0 (Sobolev embedding, 4A.6 The Fourier Transform, with the high frequencies weighted by ϵ\epsilon; Exercise 13.20). So ∥V1u∥2≤∥V1∥2∥u∥∞≤ϵ∥V1∥2∥Δu∥+C∥u∥\|V_1u\|_2 \leq \|V_1\|_2\|u\|_\infty \leq \epsilon\|V_1\|_2\|\Delta u\| + C\|u\| and ∥V2u∥≤1R∥u∥\|V_2u\| \leq \frac1R\|u\|. Kato–Rellich applies with any a>0a > 0. Tosio Kato's 1951 paper did this for all atoms and molecules, with NN electrons and ∑1∣xi−xj∣\sum\frac{1}{|x_i - x_j|} repulsions, giving the first rigorous foundation of their quantum mechanics; the eigenvalues −14n2-\frac{1}{4n^2} of this HH are the Balmer–Rydberg energy levels.

Min–max

For self-adjoint operators bounded below with compact resolvent, eigenvalues are values of a variational problem, which is how they are estimated in practice.

Theorem 13.14 Courant–Fischer min–max principle

Let AA be self-adjoint, bounded below, with compact resolvent, eigenvalues λ1≤λ2≤…\lambda_1 \leq \lambda_2 \leq \dots counted with multiplicity, and quadratic form qq with form domain QQ. Then

λk=min⁡V⊆Qdim⁡V=k max⁡u∈V∖0q(u,u)∥u∥2.\lambda_k = \min_{\substack{V \subseteq Q\\ \dim V = k}}\ \max_{u \in V\setminus0}\frac{q(u, u)}{\|u\|^2}.

Proof. Let Ek=span⁡(e1,…,ek)E_k = \operatorname{span}(e_1, \dots, e_k). For u=∑j≤kcjeju = \sum_{j\leq k}c_je_j, q(u,u)=∑j≤kλj∣cj∣2≤λk∥u∥2q(u, u) = \sum_{j\leq k}\lambda_j|c_j|^2 \leq \lambda_k\|u\|^2, so the min is at most λk\lambda_k. Conversely, any kk-dimensional V⊆QV \subseteq Q contains a nonzero u⊥e1,…,ek−1u \perp e_1, \dots, e_{k - 1} (a dimension count), and for it q(u,u)=∑j≥kλj∣⟨u,ej⟩∣2≥λk∥u∥2q(u, u) = \sum_{j\geq k}\lambda_j|\langle u, e_j\rangle|^2 \geq \lambda_k\|u\|^2, where the expansion of qq in the eigenbasis holds on the form domain by the functional calculus (Q=D((A+c)1/2)Q = D((A + c)^{1/2})). So every VV has max at least λk\lambda_k.

Consequences: eigenvalues increase when the form increases (larger potential, larger domain constraints), and Dirichlet eigenvalues decrease when the domain grows (H01(Ω)⊆H01(Ω′)H^1_0(\Omega) \subseteq H^1_0(\Omega') for Ω⊆Ω′\Omega \subseteq \Omega'), a monotonicity used to prove Weyl's law by bracketing (6B.15 Spectral Theory and Heat Trace Asymptotics). With k=1k = 1 it is the Rayleigh quotient of 4A.8 Compact Operators and Spectra and 6B.16 Eigenvalue Problems and Perelman’s λ.

The operator −4Δ+R-4\Delta + R

On a closed Riemannian manifold (M,g)(M, g), L=−4Δ+RL = -4\Delta + R with RR smooth is the operator whose lowest eigenvalue is Perelman's λ(g)\lambda(g) (12A.2 Ricci Flow as a Gradient Flow). The theory above gives, with elliptic regularity on manifolds (9B.7 The Heat Equation on a Manifold):

  1. −Δ-\Delta is essentially self-adjoint on C∞(M)C^\infty(M) (no boundary, so no boundary conditions to choose), with self-adjoint closure on H2(M)H^2(M) and compact resolvent by Rellich on MM.
  2. Multiplication by RR is bounded, so LL is self-adjoint on H2(M)H^2(M) by Kato–Rellich (with a=0a = 0), bounded below by min⁡R\min R, with compact resolvent and an orthonormal eigenbasis.
  3. λ(g)=λ1(L)=min⁡∫(4∣∇w∣2+Rw2)∫w2\lambda(g) = \lambda_1(L) = \min\frac{\int(4|\nabla w|^2 + Rw^2)}{\int w^2} by min–max, and the minimiser can be taken positive: if ww minimises, so does ∣w∣|w| (with ∣∇∣w∣∣=∣∇w∣|\nabla|w|| = |\nabla w| almost everywhere), which then solves Lw=λ1wLw = \lambda_1w, is smooth, and by the strong maximum principle (6A.5 Maximum Principles) is everywhere positive. Two positive eigenfunctions cannot be orthogonal, so λ1\lambda_1 is simple.
  4. The heat semigroup e−tLe^{-tL} and its kernel exist, and e−tLe^{-tL} maps positive functions to positive functions (it is positivity preserving, by the maximum principle); this is the operator-theoretic home of the conjugate heat equation □∗u=0\square^*u = 0, whose solutions Perelman runs backward in time (12A.3 The 𝓦-Entropy).

Simplicity and positivity of the ground state are what make λ(g)\lambda(g) a smooth function of the metric, by the perturbation theory of simple eigenvalues (4A.3 Calculus and Fixed Points in Banach Spaces).

In the world In use Spectra in the laboratory and in computation

The functional calculus is how spectra are computed in practice. Quantum chemistry packages compute the low eigenvalues of molecular Hamiltonians (made self-adjoint by Kato's theorem) by min–max on finite-dimensional trial spaces: the Rayleigh–Ritz method, which by min–max gives upper bounds for each eigenvalue. Finite element software computes vibration modes of structures and electromagnetic cavities the same way. The upper-bound property is exactly the min–max principle: restricting the form to a subspace can only raise the min–max values.

Where this goes Where operators return

The heat semigroup of a self-adjoint operator, its smoothing and its kernel are developed in 6B.13 Semigroups and Evolution Equations and 6B.15 Spectral Theory and Heat Trace Asymptotics, where Weyl's law follows from the heat trace; Perelman's λ\lambda and the eigenvalue problems of geometry are in 6B.16 Eigenvalue Problems and Perelman’s λ and 12A.2 Ricci Flow as a Gradient Flow. 4A.14 Hölder Spaces returns to function spaces with the Hölder spaces, in which elliptic and parabolic operators gain exactly two derivatives.

History

John von Neumann created the theory of unbounded self-adjoint operators in 1929–1932 for quantum mechanics, including the spectral theorem and the theory of deficiency indices; Marshall Stone proved his theorem and developed the theory independently (1929–1932). Kurt Friedrichs introduced his extension in 1934. Franz Rellich (1939) and Tosio Kato (1951) proved the perturbation theorem; Kato's paper on the self-adjointness of atomic Hamiltonians is a landmark of mathematical physics. The min–max principle goes back to Fischer (1905) and Courant (1920), and the Rayleigh–Ritz method to Ritz (1908).

Recall Where we stand

Unbounded operators come with domains; closed operators have closed graphs, and closing a differential operator passes to a Sobolev space. The adjoint of a densely defined operator is closed; symmetric means A⊆A∗A \subseteq A^*, self-adjoint means A=A∗A = A^*. The gap between them is where boundary conditions live: momentum on an interval has a circle of self-adjoint extensions, on a half-line none. A symmetric operator is self-adjoint iff Ran⁡(A±i)=H\operatorname{Ran}(A \pm i) = H; self-adjoint operators have real spectrum and ∥(A−z)−1∥≤∣Im⁡z∣−1\|(A - z)^{-1}\| \leq |\operatorname{Im}z|^{-1}. A semibounded symmetric operator has a Friedrichs extension, built from its form by Riesz; for −Δ-\Delta on Cc∞(Ω)C_c^\infty(\Omega) it is the Dirichlet Laplacian. With compact resolvent, a self-adjoint operator has an eigenbasis with λk→∞\lambda_k \to \infty and a functional calculus giving e−tAe^{-tA}, e−itAe^{-itA} and AsA^s; in general the spectral theorem makes AA a multiplication operator, and Stone's theorem matches self-adjoint operators with unitary groups. Kato–Rellich makes −Δ+V-\Delta + V self-adjoint for relatively bounded VV, including atoms. Min–max characterises eigenvalues variationally. On a closed manifold, −4Δ+R-4\Delta + R is self-adjoint with compact resolvent and a simple, positive ground state: Perelman's λ\lambda.

Exercises

Exercise 13.15 Graphs and adjoints

With J(x,y)=(−y,x)J(x, y) = (-y, x) on H×HH\times H, show that Γ(A∗)=(JΓ(A))⊥\Gamma(A^*) = (J\Gamma(A))^\perp for densely defined AA. Deduce that A∗A^* is closed, and that A⊆BA \subseteq B implies B∗⊆A∗B^* \subseteq A^*.

Solution

(v,w)⊥J(u,Au)=(−Au,u)(v, w) \perp J(u, Au) = (-Au, u) iff −⟨Au,v⟩+⟨u,w⟩=0-\langle Au, v\rangle + \langle u, w\rangle = 0 for all u∈D(A)u \in D(A), iff v∈D(A∗)v \in D(A^*) with A∗v=wA^*v = w. Orthogonal complements are closed. If Γ(A)⊆Γ(B)\Gamma(A) \subseteq \Gamma(B) then (JΓ(B))⊥⊆(JΓ(A))⊥(J\Gamma(B))^\perp \subseteq (J\Gamma(A))^\perp.

Exercise 13.16 Twisted boundary conditions

(a) Show that Pα=−iddxP_\alpha = -i\frac{d}{dx} on {u∈H1(0,1):u(1)=eiαu(0)}\{u \in H^1(0, 1) : u(1) = e^{i\alpha}u(0)\} is self-adjoint. (b) Find its eigenvalues and eigenfunctions, and check that they form an orthonormal basis. (c) For which α\alpha is 00 an eigenvalue?

Solution

(a) For u,v∈H1u, v \in H^1, ⟨−iu′,v⟩−⟨u,−iv′⟩=−i(u(1)vˉ(1)−u(0)vˉ(0))\langle-iu', v\rangle - \langle u, -iv'\rangle = -i(u(1)\bar v(1) - u(0)\bar v(0)). For uu in the domain this is −iu(0)(eiαvˉ(1)−vˉ(0))-iu(0)(e^{i\alpha}\bar v(1) - \bar v(0)), which vanishes for all such uu iff v(1)=eiαv(0)v(1) = e^{i\alpha}v(0). So D(Pα∗)=D(Pα)D(P_\alpha^*) = D(P_\alpha) (that D(Pα∗)⊆H1D(P_\alpha^*) \subseteq H^1 follows as for the closure of the derivative). (b) −iu′=λu-iu' = \lambda u gives u=eiλxu = e^{i\lambda x}, and the boundary condition gives eiλ=eiαe^{i\lambda} = e^{i\alpha}: λk=α+2πk\lambda_k = \alpha + 2\pi k, ek=ei(α+2πk)x=eiαxe2πikxe_k = e^{i(\alpha + 2\pi k)x} = e^{i\alpha x}e^{2\pi ikx}, an orthonormal basis since the e2πikxe^{2\pi ikx} are (2B.7 Fourier Series and the First Heat Equation) and multiplication by eiαxe^{i\alpha x} is unitary. (c) α=0\alpha = 0: periodic boundary conditions, constants.

Exercise 13.17 Inverses of self-adjoint operators

Let GG be bounded, self-adjoint and injective. Show that G−1G^{-1}, defined on Ran⁡G\operatorname{Ran}G, is densely defined and self-adjoint.

Solution

(Ran⁡G)⊥=ker⁡G∗=ker⁡G=0(\operatorname{Ran}G)^\perp = \ker G^* = \ker G = 0, so the range is dense. The graph of G−1G^{-1} is the graph of GG with coordinates swapped, SΓ(G)S\Gamma(G) with S(x,y)=(y,x)S(x, y) = (y, x). Then Γ((G−1)∗)=(JSΓ(G))⊥\Gamma((G^{-1})^*) = (JS\Gamma(G))^\perp, and JS(x,y)=(−x,y)JS(x, y) = (-x, y); so (v,w)(v, w) is in it iff ⟨−x,v⟩+⟨Gx,w⟩=0\langle-x, v\rangle + \langle Gx, w\rangle = 0 for all xx, iff v=G∗w=Gwv = G^*w = Gw, iff (v,w)∈SΓ(G)=Γ(G−1)(v, w) \in S\Gamma(G) = \Gamma(G^{-1}).

Exercise 13.18 The Neumann Laplacian

On Ω=(0,1)\Omega = (0, 1), complete C∞([0,1])C^\infty([0, 1]) in the form q(u,u)=∫01u′2+u2q(u, u) = \int_0^1u'^2 + u^2. (a) Show the completion is H1(0,1)H^1(0, 1). (b) Show that the operator represented by qq is −d2dx2+1-\frac{d^2}{dx^2} + 1 on {u∈H2:u′(0)=u′(1)=0}\{u \in H^2 : u'(0) = u'(1) = 0\}. (c) Find the eigenvalues of the Neumann Laplacian on (0,1)(0, 1) and compare with the Dirichlet ones.

Solution

(a) The form norm is the H1H^1 norm, and C∞([0,1])C^\infty([0, 1]) is dense in H1(0,1)H^1(0, 1). (b) If q(u,v)=⟨f,v⟩q(u, v) = \langle f, v\rangle for all v∈H1v \in H^1, then taking v∈Cc∞v \in C_c^\infty gives −u′′+u=f-u'' + u = f weakly, so u∈H2u \in H^2; integrating by parts with general vv leaves u′(1)v(1)−u′(0)v(0)=0u'(1)v(1) - u'(0)v(0) = 0 for all vv, so u′(0)=u′(1)=0u'(0) = u'(1) = 0. The boundary condition is not imposed but natural: it comes out of the variational problem. (c) −u′′=λu-u'' = \lambda u, u′=0u' = 0 at both ends: u=cos⁡(kπx)u = \cos(k\pi x), λ=k2π2\lambda = k^2\pi^2, k=0,1,2,…k = 0, 1, 2, \dots. Dirichlet: sin⁡(kπx)\sin(k\pi x), k≥1k \geq 1, same values but starting at k=1k = 1. Each Neumann eigenvalue λkN≤λkD\lambda_k^N \leq \lambda_k^D, as min–max predicts (H01⊆H1H^1_0 \subseteq H^1).

Exercise 13.19 Stone's theorem, forward direction

Using the multiplication form, show that U(t)=e−itAU(t) = e^{-itA} is a strongly continuous unitary group, and that iU(t)u−ut→Aui\frac{U(t)u - u}{t} \to Au for u∈D(A)u \in D(A).

Solution

In L2(μ)L^2(\mu), U(t)U(t) is multiplication by e−itae^{-ita}, unitary, with U(t+s)=U(t)U(s)U(t + s) = U(t)U(s). For ϕ∈L2\phi \in L^2, ∥U(t)ϕ−ϕ∥2=∫∣e−ita−1∣2∣ϕ∣2→0\|U(t)\phi - \phi\|^2 = \int|e^{-ita} - 1|^2|\phi|^2 \to 0 by dominated convergence. For aϕ∈L2a\phi \in L^2, ∣ie−ita−1t−a∣∣ϕ∣≤2∣a∣∣ϕ∣\big|i\frac{e^{-ita} - 1}{t} - a\big||\phi| \leq 2|a||\phi| (since ∣e−ix−1∣≤∣x∣|e^{-ix} - 1| \leq |x|) and tends to 00 pointwise, so again by dominated convergence.

Exercise 13.20 An ϵ\epsilon-Sobolev inequality

On R3\mathbb{R}^3, show that for every ϵ>0\epsilon > 0 there is CϵC_\epsilon with ∥u∥∞≤ϵ∥Δu∥2+Cϵ∥u∥2\|u\|_\infty \leq \epsilon\|\Delta u\|_2 + C_\epsilon\|u\|_2 for u∈H2u \in H^2. (Bound ∥u∥∞≤∥u^∥1\|u\|_\infty \leq \|\hat u\|_1 and split ∫∣u^∣\int|\hat u| into ∣ξ∣<R|\xi| < R and ∣ξ∣>R|\xi| > R, using Cauchy–Schwarz on each.)

Solution

∫∣ξ∣<R∣u^∣≤(43πR3)1/2∥u∥2\int_{|\xi|<R}|\hat u| \leq (\frac43\pi R^3)^{1/2}\|u\|_2. ∫∣ξ∣>R∣u^∣=∫∣ξ∣>R∣ξ∣−2⋅∣ξ∣2∣u^∣≤(∫∣ξ∣>R∣ξ∣−4)1/2∥Δu∥24π2=(4πR)1/2∥Δu∥24π2\int_{|\xi|>R}|\hat u| = \int_{|\xi|>R}|\xi|^{-2}\cdot|\xi|^2|\hat u| \leq \big(\int_{|\xi|>R}|\xi|^{-4}\big)^{1/2}\frac{\|\Delta u\|_2}{4\pi^2} = \big(\frac{4\pi}{R}\big)^{1/2}\frac{\|\Delta u\|_2}{4\pi^2}. Choose RR large so that the second coefficient is below ϵ\epsilon. The high frequencies are controlled by Δu\Delta u with a constant that becomes small, which is what relative bound 00 needs.

Exercise 13.21 Rehearsal: the ground state is positive and simple

On a closed connected manifold, let L=−4Δ+RL = -4\Delta + R and let ww be a real minimiser of the Rayleigh quotient. (a) Show ∣w∣|w| is also a minimiser. (b) Assuming minimisers are smooth eigenfunctions and the strong maximum principle for (L−λ1+c)(L - \lambda_1 + c) with cc large, show ∣w∣>0|w| > 0 everywhere, hence ww has constant sign. (c) Deduce that λ1\lambda_1 is simple.

Solution

(a) ∫∣∇∣w∣∣2=∫∣∇w∣2\int|\nabla|w||^2 = \int|\nabla w|^2 (the gradient of ∣w∣|w| is ±∇w\pm\nabla w almost everywhere, and 00 where w=0w = 0) and ∫R∣w∣2=∫Rw2\int R|w|^2 = \int Rw^2. (b) v=∣w∣≥0v = |w| \geq 0 solves −4Δv+(R−λ1)v=0-4\Delta v + (R - \lambda_1)v = 0, hence −4Δv+(R−λ1+c)v=cv≥0-4\Delta v + (R - \lambda_1 + c)v = cv \geq 0 with R−λ1+c>0R - \lambda_1 + c > 0: a supersolution of an operator with positive zeroth-order term, so if vv vanished at a point it would vanish identically (strong maximum principle, 6A.5 Maximum Principles). As ww is continuous and ∣w∣>0|w| > 0, ww never vanishes, so has constant sign on the connected MM. (c) If λ1\lambda_1 had two independent eigenfunctions, a combination orthogonal to a positive one would be an eigenfunction changing sign, contradicting (b).

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