Book 12A

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Course 12Book 12A: Entropy and NoncollapsingChapter 2

Ricci Flow as a Gradient Flow

The 𝓕 functional, its monotonicity, and no steady breathers.

18 min read Β· Updated Oct 3, 2026

Read Perelman I, Β§Β§1–2, then Kleiner and Lott's notes on those sections, and Topping's Lectures on the Ricci Flow, the chapter on the F\mathcal F-functional. Morgan and Tian cover the same material in their chapter on Perelman's functionals.

In this chapter Β· 7 sections
  1. 2.1Going downhill
  2. 2.2The first variation
  3. 2.3The gradient flow and the Ricci flow
  4. 2.4The eigenvalue Ξ»(g)\lambda(g)Ξ»(g)
  5. 2.5No steady breathers
  6. 2.6History
  7. 2.7Exercises

Perelman's first idea is that the Ricci flow is a gradient flow. Hamilton had looked for a functional whose gradient flow is the Ricci flow and not found one, and there is a good reason: in the obvious sense there is none. Perelman found one in a less obvious sense. Add an auxiliary function ff to the metric, consider

F(g,f)=∫M(R+βˆ£βˆ‡f∣2)eβˆ’f dV,\mathcal F(g, f) = \int_M\big(R + |\nabla f|^2\big)e^{-f}\,dV,

and fix the measure dm=eβˆ’f dVdm = e^{-f}\,dV. Then the gradient flow of F\mathcal F is the Ricci flow, modified by a diffeomorphism. Along it, F\mathcal F is nondecreasing, with equality exactly on steady gradient solitons. Its minimum over ff, Ξ»(g)\lambda(g), is the first eigenvalue of the operator βˆ’4Ξ”+R-4\Delta + R, and it too is nondecreasing along the flow. As a first application: the Ricci flow has no nontrivial breathers, solutions that return to themselves up to diffeomorphism, other than solitons.

By the end of this chapter you will be able to:

  • compute the first variation of F\mathcal F and identify its gradient for a fixed measure;
  • derive the coupled flow, and relate it by a diffeomorphism to the Ricci flow coupled with the conjugate heat equation;
  • prove the monotonicity formula ddtF=2∫∣Ric⁑+βˆ‡2f∣2 dm\frac{d}{dt}\mathcal F = 2\int|\operatorname{Ric} + \nabla^2f|^2\,dm;
  • define Ξ»(g)\lambda(g), identify it as an eigenvalue, and show it is nondecreasing;
  • prove that steady breathers on closed manifolds are Ricci-flat.

Going downhill

In the world Analogy Gradient descent

In optimisation, gradient descent minimises a function by repeatedly stepping in the direction of steepest descent. The "steepest" direction depends on how lengths are measured, so different choices of metric on the space of parameters give different gradient flows of the same function (6A.9 Calculus of Variations and Gradient Flows). Many evolution equations are gradient flows in this sense: the heat equation is the gradient flow of the Dirichlet energy for the L2L^2 metric, and curve shortening is the gradient flow of length (6A.8 Curve Shortening and the First Geometric Flows). Perelman showed that the Ricci flow is, too: it increases F\mathcal F as fast as possible, for a weighted L2L^2 metric on symmetric tensors.

Where the picture breaks

The analogy needs two adjustments. The Ricci flow is a gradient flow only after a change of gauge: the flow that is literally a gradient flow differs from it by a family of diffeomorphisms, and it depends on a choice of the measure dmdm. And, with Perelman's sign conventions, the flow goes uphill: F\mathcal F increases. Neither changes the essential point: there is a monotone quantity whose equality case is a soliton.

The first variation

Let Ξ΄g=v\delta g = v and Ξ΄f=h\delta f = h, with v=tr⁑vv = \operatorname{tr}v. Using the variation of the scalar curvature from 11A.2 How Curvature Evolves, Ξ΄R=βˆ’Ξ”v+βˆ‡iβˆ‡jvijβˆ’βŸ¨v,Ric⁑⟩\delta R = -\Delta v + \nabla^i\nabla^jv_{ij} - \langle v, \operatorname{Ric}\rangle, and Ξ΄(dV)=v2 dV\delta(dV) = \frac v2\,dV, Perelman computes (Exercise 2.4)

Ξ΄F=∫Meβˆ’f[βˆ’vij(Rij+βˆ‡iβˆ‡jf)+(v2βˆ’h)(2Ξ”fβˆ’βˆ£βˆ‡f∣2+R)]dV.\delta\mathcal F = \int_Me^{-f}\Big[-v_{ij}\big(R_{ij} + \nabla_i\nabla_jf\big) + \Big(\frac v2 - h\Big)\big(2\Delta f - |\nabla f|^2 + R\big)\Big]dV.

The factor v2βˆ’h\frac v2 - h vanishes exactly when the measure dm=eβˆ’fdVdm = e^{-f}dV is unchanged. So if the measure is held fixed, the variation is βˆ«βˆ’vij(Rij+βˆ‡iβˆ‡jf) dm\int-v_{ij}(R_{ij} + \nabla_i\nabla_jf)\,dm: the gradient of F\mathcal F, for the L2(dm)L^2(dm) metric on symmetric tensors, is βˆ’(Ric⁑+βˆ‡2f)-(\operatorname{Ric} + \nabla^2f).

The gradient flow and the Ricci flow

The gradient flow of F\mathcal F with dmdm fixed is

βˆ‚tg=βˆ’2(Ric⁑+βˆ‡2f),βˆ‚tf=βˆ’Rβˆ’Ξ”f,\partial_tg = -2\big(\operatorname{Ric} + \nabla^2f\big), \qquad \partial_tf = -R - \Delta f,

the second equation being what keeps eβˆ’fdVe^{-f}dV fixed. Since βˆ’2βˆ‡2f=βˆ’Lβˆ‡fg-2\nabla^2f = -\mathcal L_{\nabla f}g, this differs from the Ricci flow only by the Lie derivative along βˆ‡f\nabla f. Pulling back by the diffeomorphisms generated by βˆ‡f\nabla f (as in DeTurck's trick, 11A.3 Short-Time Existence and Uniqueness) turns the system into

βˆ‚tg=βˆ’2Ric⁑,βˆ‚tf=βˆ’Ξ”f+βˆ£βˆ‡f∣2βˆ’R.\partial_tg = -2\operatorname{Ric}, \qquad \partial_tf = -\Delta f + |\nabla f|^2 - R.

The equation for ff is the conjugate heat equation for u=eβˆ’fu = e^{-f}: β–‘βˆ—u=(βˆ’βˆ‚tβˆ’Ξ”+R)u=0\square^*u = (-\partial_t - \Delta + R)u = 0 (Exercise 2.5, 9B.7 The Heat Equation on a Manifold). So the gradient flow is equivalent to the Ricci flow, coupled with a solution of the conjugate heat equation running backwards in time, which keeps ∫u dV\int u\,dV constant. Perelman remarks that different choices of dmdm give the same flow up to diffeomorphism, as different choices of gauge.

Figure 2.1. The gauge picture. The gradient flow of F\mathcal F with the measure fixed (top) and the Ricci flow coupled with the conjugate heat equation (bottom) differ at each time by a diffeomorphism generated by βˆ‡f\nabla f. Since F\mathcal F is invariant under diffeomorphisms, its monotonicity holds along both.
Theorem 2.1 Monotonicity of F\mathcal F (Perelman I, Β§1)

Along the Ricci flow coupled with βˆ‚tf=βˆ’Ξ”f+βˆ£βˆ‡f∣2βˆ’R\partial_tf = -\Delta f + |\nabla f|^2 - R on a closed manifold,

ddtF(g(t),f(t))=2∫M∣Ric⁑+βˆ‡2f∣2eβˆ’f dVβ‰₯0.\frac{d}{dt}\mathcal F(g(t), f(t)) = 2\int_M\big|\operatorname{Ric} + \nabla^2f\big|^2e^{-f}\,dV \geq 0.

Equality at some time holds exactly when Ric⁑+βˆ‡2f=0\operatorname{Ric} + \nabla^2f = 0: a steady gradient soliton.

Proof. By diffeomorphism invariance it is enough to compute along the gradient flow, where v=βˆ’2(Ric⁑+βˆ‡2f)v = -2(\operatorname{Ric} + \nabla^2f) and h=βˆ’Rβˆ’Ξ”fh = -R - \Delta f, so that v2βˆ’h=0\frac v2 - h = 0. The first variation formula gives

ddtF=∫eβˆ’f(2(Rij+βˆ‡iβˆ‡jf))(Rij+βˆ‡iβˆ‡jf) dV=2∫∣Ric⁑+βˆ‡2f∣2 dm.\frac{d}{dt}\mathcal F = \int e^{-f}\big(2(R_{ij} + \nabla_i\nabla_jf)\big)\big(R_{ij} + \nabla_i\nabla_jf\big)\,dV = 2\int|\operatorname{Ric} + \nabla^2f|^2\,dm.

The eigenvalue Ξ»(g)\lambda(g)

Define

Ξ»(g)=inf⁑{F(g,f):∫Meβˆ’f dV=1}.\lambda(g) = \inf\Big\{\mathcal F(g, f) : \int_Me^{-f}\,dV = 1\Big\}.

With w=eβˆ’f/2w = e^{-f/2}, F=∫(Rw2+4βˆ£βˆ‡w∣2) dV\mathcal F = \int(Rw^2 + 4|\nabla w|^2)\,dV and the constraint is ∫w2=1\int w^2 = 1, so Ξ»(g)\lambda(g) is the smallest eigenvalue of βˆ’4Ξ”+R-4\Delta + R (Exercise 2.6). It is attained by a positive eigenfunction ww (by the spectral theory of 4A.7 Compact Operators and Spectra with the variational argument of 4A.6 Weak Convergence and the Direct Method), smooth by elliptic regularity (6A.5 Weak Solutions and Elliptic Regularity). For a homogeneous metric, where RR is constant, Ξ»=R\lambda = R, attained by constants.

Proposition 2.2 Ξ»\lambda is nondecreasing

Along the Ricci flow on a closed manifold, Ξ»(g(t))\lambda(g(t)) is nondecreasing, and strictly increasing unless gg is a steady gradient soliton (hence Ricci-flat, Theorem 2.3).

Proof. Fix t1<t2t_1 < t_2. Let f(t2)f(t_2) achieve Ξ»(g(t2))\lambda(g(t_2)), and solve the conjugate heat equation backwards from t2t_2 to t1t_1; it preserves ∫eβˆ’fdV=1\int e^{-f}dV = 1. By monotonicity, Ξ»(g(t1))≀F(g(t1),f(t1))≀F(g(t2),f(t2))=Ξ»(g(t2))\lambda(g(t_1)) \leq \mathcal F(g(t_1), f(t_1)) \leq \mathcal F(g(t_2), f(t_2)) = \lambda(g(t_2)).

Figure 2.2 shows Ξ»=R\lambda = R increasing along the Berger sphere flow of 11A.6 Hamilton’s 1982 Theorem.

Figure 2.2. Ξ»(g(t))\lambda(g(t)) along the Ricci flow of the Berger sphere with AB=0.3\frac AB = 0.3 initially (computed from the ODE of 11A.6 Hamilton’s 1982 Theorem). Since the metric is homogeneous, Ξ»=R=8Bβˆ’2AB2\lambda = R = \frac{8B - 2A}{B^2}; it increases, as the proposition requires, and blows up as the sphere becomes extinct.

No steady breathers

A breather is a solution with g(t2)=cβ€‰Ο•βˆ—g(t1)g(t_2) = c\,\phi^*g(t_1) for some t1<t2t_1 < t_2, c>0c > 0 and diffeomorphism Ο•\phi. It is steady, shrinking or expanding as c=1c = 1, c<1c < 1 or c>1c > 1. Solitons are breathers; the question is whether there are others.

Theorem 2.3 No steady breathers (Perelman I, Β§2)

A steady breather on a closed manifold is a steady gradient soliton, and hence Ricci-flat.

Proof. Ξ»\lambda is diffeomorphism invariant, so Ξ»(g(t2))=Ξ»(Ο•βˆ—g(t1))=Ξ»(g(t1))\lambda(g(t_2)) = \lambda(\phi^*g(t_1)) = \lambda(g(t_1)). Since Ξ»\lambda is nondecreasing, it is constant on [t1,t2][t_1, t_2], and the equality case of the monotonicity forces Ric⁑+βˆ‡2f=0\operatorname{Ric} + \nabla^2f = 0 for the minimisers. On a closed manifold, a steady gradient soliton is Ricci-flat: tracing gives R+Ξ”f=0R + \Delta f = 0, and the soliton identity R+βˆ£βˆ‡f∣2=cR + |\nabla f|^2 = c (11B.1 Ricci Solitons) gives Ξ”fβˆ’βˆ£βˆ‡f∣2=βˆ’c\Delta f - |\nabla f|^2 = -c, that is Ξ”eβˆ’f=ceβˆ’f\Delta e^{-f} = ce^{-f}; integrating, c∫eβˆ’f=0c\int e^{-f} = 0, so c=0c = 0, then Ξ”eβˆ’f=0\Delta e^{-f} = 0, so ff is constant and Ric⁑=0\operatorname{Ric} = 0.

The expanding case follows similarly from the scale-invariant quantity Ξ»(g)Vol⁑(g)2/n\lambda(g)\operatorname{Vol}(g)^{2/n}, which is nondecreasing when λ≀0\lambda \leq 0. The shrinking case, which is the one that matters for singularities, needs a functional that knows about scale: the W\mathcal W-entropy of 12A.3 The 𝓦-Entropy.

Where this goes From F\mathcal F to W\mathcal W

F\mathcal F is monotone, but it has no scale built into it, so it cannot see shrinking solitons as equality cases and cannot measure collapse at a given scale. 12A.3 The 𝓦-Entropy inserts a scale parameter Ο„\tau and the Gaussian weight (4πτ)βˆ’n/2(4\pi\tau)^{-n/2}, obtaining the entropy W\mathcal W, whose monotonicity is Perelman's main formula and whose equality cases are the shrinking solitons.

History

Perelman introduced F\mathcal F in Β§1 of his first preprint. The functional had appeared in physics as the low-energy effective action of string theory, with ff the dilaton; Perelman notes the connection in the historical remark of Β§1, along with the Bakry–Émery Ricci tensor Ric⁑+βˆ‡2f\operatorname{Ric} + \nabla^2f of a manifold with a smooth measure, studied by Dominique Bakry and Michel Γ‰mery in the 1980s. The identification of Ξ»\lambda with the bottom of the spectrum of βˆ’4Ξ”+R-4\Delta + R is in Β§2, together with the no-breathers theorem for the steady and expanding cases, which had been known in special cases (Ivey 1993, Hamilton).

Recall Where we stand

F(g,f)=∫(R+βˆ£βˆ‡f∣2)eβˆ’fdV\mathcal F(g, f) = \int(R + |\nabla f|^2)e^{-f}dV has gradient βˆ’(Ric⁑+βˆ‡2f)-(\operatorname{Ric} + \nabla^2f) for the L2(eβˆ’fdV)L^2(e^{-f}dV) metric when the measure is fixed. Its gradient flow is, up to diffeomorphism, the Ricci flow coupled with the conjugate heat equation β–‘βˆ—eβˆ’f=0\square^*e^{-f} = 0, and along it ddtF=2∫∣Ric⁑+βˆ‡2f∣2dmβ‰₯0\frac{d}{dt}\mathcal F = 2\int|\operatorname{Ric} + \nabla^2f|^2dm \geq 0, with equality on steady gradient solitons. Ξ»(g)=inf⁑F\lambda(g) = \inf\mathcal F is the bottom eigenvalue of βˆ’4Ξ”+R-4\Delta + R and is nondecreasing; hence steady breathers on closed manifolds are Ricci-flat. 12A.3 The 𝓦-Entropy adds a scale and handles shrinking breathers.

Exercises

Exercise 2.4 The first variation

Derive Perelman's formula. Write F=∫(R+βˆ£βˆ‡f∣2)eβˆ’fdV\mathcal F = \int(R + |\nabla f|^2)e^{-f}dV and vary: Ξ΄R=βˆ’Ξ”v+βˆ‡iβˆ‡jvijβˆ’vijRij\delta R = -\Delta v + \nabla^i\nabla^jv_{ij} - v_{ij}R_{ij}; Ξ΄βˆ£βˆ‡f∣2=βˆ’vijβˆ‡ifβˆ‡jf+2βŸ¨βˆ‡f,βˆ‡h⟩\delta|\nabla f|^2 = -v_{ij}\nabla_if\nabla_jf + 2\langle\nabla f, \nabla h\rangle; Ξ΄(eβˆ’fdV)=(v2βˆ’h)eβˆ’fdV\delta(e^{-f}dV) = (\frac v2 - h)e^{-f}dV. Integrate by parts against eβˆ’fe^{-f} (for instance ∫eβˆ’fβˆ‡iβˆ‡jvij=∫vijβˆ‡iβˆ‡jeβˆ’f\int e^{-f}\nabla^i\nabla^jv_{ij} = \int v_{ij}\nabla_i\nabla_je^{-f}) and collect terms.

Solution

The terms with derivatives of vv: ∫eβˆ’f(βˆ’Ξ”v+βˆ‡iβˆ‡jvij)=∫(βˆ’vΞ”eβˆ’f+vijβˆ‡iβˆ‡jeβˆ’f)\int e^{-f}(-\Delta v + \nabla^i\nabla^jv_{ij}) = \int(-v\Delta e^{-f} + v_{ij}\nabla_i\nabla_je^{-f}), with βˆ‡iβˆ‡jeβˆ’f=(βˆ’βˆ‡iβˆ‡jf+βˆ‡ifβˆ‡jf)eβˆ’f\nabla_i\nabla_je^{-f} = (-\nabla_i\nabla_jf + \nabla_if\nabla_jf)e^{-f} and Ξ”eβˆ’f=(βˆ’Ξ”f+βˆ£βˆ‡f∣2)eβˆ’f\Delta e^{-f} = (-\Delta f + |\nabla f|^2)e^{-f}. So they give ∫eβˆ’f[v(Ξ”fβˆ’βˆ£βˆ‡f∣2)βˆ’vijβˆ‡iβˆ‡jf+vijβˆ‡ifβˆ‡jf]\int e^{-f}[v(\Delta f - |\nabla f|^2) - v_{ij}\nabla_i\nabla_jf + v_{ij}\nabla_if\nabla_jf]. The hh-term: ∫2βŸ¨βˆ‡f,βˆ‡h⟩eβˆ’f=∫2h(βˆ’Ξ”f+βˆ£βˆ‡f∣2)eβˆ’f\int2\langle\nabla f, \nabla h\rangle e^{-f} = \int2h(-\Delta f + |\nabla f|^2)e^{-f}. Adding βˆ’vijRijβˆ’vijβˆ‡ifβˆ‡jf-v_{ij}R_{ij} - v_{ij}\nabla_if\nabla_jf and (R+βˆ£βˆ‡f∣2)(v2βˆ’h)(R + |\nabla f|^2)(\frac v2 - h), the vijβˆ‡ifβˆ‡jfv_{ij}\nabla_if\nabla_jf terms cancel, and the rest regroup as βˆ’vij(Rij+βˆ‡iβˆ‡jf)+(v2βˆ’h)(2Ξ”fβˆ’βˆ£βˆ‡f∣2+R)-v_{ij}(R_{ij} + \nabla_i\nabla_jf) + (\frac v2 - h)(2\Delta f - |\nabla f|^2 + R).

Exercise 2.5 The conjugate heat equation

Show that u=eβˆ’fu = e^{-f} satisfies βˆ’βˆ‚tuβˆ’Ξ”u+Ru=0-\partial_tu - \Delta u + Ru = 0 exactly when βˆ‚tf=βˆ’Ξ”f+βˆ£βˆ‡f∣2βˆ’R\partial_tf = -\Delta f + |\nabla f|^2 - R. Verify that ∫u dV\int u\,dV is constant along the Ricci flow (9B.7 The Heat Equation on a Manifold).

Solution

βˆ‚tu=βˆ’(βˆ‚tf)u\partial_tu = -(\partial_tf)u and Ξ”u=(βˆ’Ξ”f+βˆ£βˆ‡f∣2)u\Delta u = (-\Delta f + |\nabla f|^2)u, so βˆ’βˆ‚tuβˆ’Ξ”u+Ru=(βˆ‚tf+Ξ”fβˆ’βˆ£βˆ‡f∣2+R)u-\partial_tu - \Delta u + Ru = (\partial_tf + \Delta f - |\nabla f|^2 + R)u. And ddt∫u dV=∫(βˆ‚tuβˆ’Ru) dV=βˆ«βˆ’Ξ”u dV=0\frac{d}{dt}\int u\,dV = \int(\partial_tu - Ru)\,dV = \int-\Delta u\,dV = 0, using βˆ‚t dV=βˆ’R dV\partial_t\,dV = -R\,dV.

Exercise 2.6 Ξ»\lambda as an eigenvalue

With w=eβˆ’f/2w = e^{-f/2}, show βˆ£βˆ‡f∣2eβˆ’f=4βˆ£βˆ‡w∣2|\nabla f|^2e^{-f} = 4|\nabla w|^2, so F=∫(Rw2+4βˆ£βˆ‡w∣2)dV\mathcal F = \int(Rw^2 + 4|\nabla w|^2)dV and the constraint is ∫w2=1\int w^2 = 1. Conclude that Ξ»(g)\lambda(g) is the smallest eigenvalue of βˆ’4Ξ”+R-4\Delta + R, and that Ξ»=R\lambda = R for a metric of constant scalar curvature.

Solution

βˆ‡w=βˆ’12wβˆ‡f\nabla w = -\frac12w\nabla f, so 4βˆ£βˆ‡w∣2=w2βˆ£βˆ‡f∣2=eβˆ’fβˆ£βˆ‡f∣24|\nabla w|^2 = w^2|\nabla f|^2 = e^{-f}|\nabla f|^2. The infimum of the Rayleigh quotient ∫(4βˆ£βˆ‡w∣2+Rw2)\int(4|\nabla w|^2 + Rw^2) over ∫w2=1\int w^2 = 1 is the bottom of the spectrum of βˆ’4Ξ”+R-4\Delta + R (4A.7 Compact Operators and Spectra). If RR is constant, ∫(4βˆ£βˆ‡w∣2+Rw2)β‰₯R\int(4|\nabla w|^2 + Rw^2) \geq R with equality for constant ww.

Exercise 2.7 A bound from the gradient flow

Suppose the gradient flow exists on [0,T][0, T] with ∫dm=1\int dm = 1. (a) Show ∫(R+Ξ”f) dm=F\int(R + \Delta f)\,dm = \mathcal F (use βˆ«Ξ”f eβˆ’fdV=βˆ«βˆ£βˆ‡f∣2eβˆ’fdV\int\Delta f\,e^{-f}dV = \int|\nabla f|^2e^{-f}dV). (b) Use ∣Ric⁑+βˆ‡2f∣2β‰₯1n(R+Ξ”f)2|\operatorname{Ric} + \nabla^2f|^2 \geq \frac1n(R + \Delta f)^2 and Cauchy–Schwarz for dmdm to get ddtFβ‰₯2nF2\frac{d}{dt}\mathcal F \geq \frac2n\mathcal F^2. (c) Deduce F(0)≀n2T\mathcal F(0) \leq \frac{n}{2T}, Perelman's Proposition 1.2.

Solution

(a) Integrate by parts. (b) ddtFβ‰₯2n∫(R+Ξ”f)2dmβ‰₯2n(∫(R+Ξ”f)dm)2=2nF2\frac{d}{dt}\mathcal F \geq \frac2n\int(R + \Delta f)^2dm \geq \frac2n\big(\int(R + \Delta f)dm\big)^2 = \frac2n\mathcal F^2. (c) If F(0)>0\mathcal F(0) > 0, comparison with yβ€²=2ny2y' = \frac2ny^2 shows F\mathcal F blows up before time n2F(0)\frac{n}{2\mathcal F(0)}, so T<n2F(0)T < \frac{n}{2\mathcal F(0)}, i.e. F(0)≀n2T\mathcal F(0) \leq \frac{n}{2T}; if F(0)≀0\mathcal F(0) \leq 0 the bound is trivial.

Exercise 2.8 Rehearsal: the template "monotone, invariant, equality case"

The no-steady-breathers argument has three ingredients: a quantity that is (i) monotone along the flow, (ii) invariant under the symmetries that define a breather, with (iii) an equality case that is a soliton. Identify the three ingredients for Ξ»\lambda and steady breathers. Explain why Ξ»\lambda fails ingredient (ii) for shrinking breathers, and what kind of quantity would fix it.

Solution

(i) Ξ»(g(t))\lambda(g(t)) is nondecreasing. (ii) Ξ»(Ο•βˆ—g)=Ξ»(g)\lambda(\phi^*g) = \lambda(g) for diffeomorphisms. (iii) Constancy forces Ric⁑+βˆ‡2f=0\operatorname{Ric} + \nabla^2f = 0. For a shrinking breather, g(t2)=cΟ•βˆ—g(t1)g(t_2) = c\phi^*g(t_1) with c<1c < 1, and Ξ»(cg)=cβˆ’1Ξ»(g)\lambda(cg) = c^{-1}\lambda(g), so Ξ»\lambda changes under scaling and the comparison fails. A quantity invariant under scaling, which treats (g,Ο„)(g, \tau) and (cg,cΟ„)(cg, c\tau) alike, would fix it: Perelman's W(g,f,Ο„)\mathcal W(g, f, \tau), whose equality case is a shrinking soliton (12A.3 The 𝓦-Entropy).

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