Book 12A

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Course 12Book 12A: Entropy and NoncollapsingChapter 3

The 𝓦-Entropy

A scale-invariant entropy, log-Sobolev, and no shrinking breathers.

20 min read Β· Updated Oct 3, 2026

Read Perelman I, Β§3 and Β§5, then Kleiner and Lott's notes on those sections and Topping's chapter on the W\mathcal W-entropy. For the logarithmic Sobolev inequality, Gross's "Logarithmic Sobolev inequalities" (American Journal of Mathematics, 1975) is the source; 6A.10 Entropy, Information and Diffusion met it first.

In this chapter Β· 8 sections
  1. 3.1Logarithmic Sobolev inequalities
  2. 3.2The entropy and its monotonicity
  3. 3.3On Euclidean space: the Gaussian
  4. 3.4On a closed manifold
  5. 3.5No shrinking breathers
  6. 3.6Perelman's statistical analogy
  7. 3.7History
  8. 3.8Exercises

The functional F\mathcal F of 12A.2 Ricci Flow as a Gradient Flow has no scale in it, so it cannot see shrinking solitons or measure geometry at a given size. Perelman's remedy is to insert a scale Ο„>0\tau > 0 and a Gaussian weight. The result is the W\mathcal W-entropy

W(g,f,Ο„)=∫M[Ο„(βˆ£βˆ‡f∣2+R)+fβˆ’n](4πτ)βˆ’n/2eβˆ’f dV,∫M(4πτ)βˆ’n/2eβˆ’f dV=1.\mathcal W(g, f, \tau) = \int_M\big[\tau\big(|\nabla f|^2 + R\big) + f - n\big](4\pi\tau)^{-n/2}e^{-f}\,dV, \qquad \int_M(4\pi\tau)^{-n/2}e^{-f}\,dV = 1.

It is invariant under scaling (g,Ο„)↦(cg,cΟ„)(g, \tau) \mapsto (cg, c\tau). Along the Ricci flow, with Ο„\tau decreasing at unit rate and u=(4πτ)βˆ’n/2eβˆ’fu = (4\pi\tau)^{-n/2}e^{-f} solving the conjugate heat equation, it is nondecreasing, and constant exactly on shrinking gradient solitons. On Euclidean space, its positivity is exactly Gross's Gaussian logarithmic Sobolev inequality. Its minimum over ff, ΞΌ(g,Ο„)\mu(g, \tau), is the quantity that Perelman uses to prove noncollapsing (12A.4 ΞΊ-Noncollapsing). This monotonicity formula is the analytic heart of the proof of the PoincarΓ© conjecture.

By the end of this chapter you will be able to:

  • define W\mathcal W and ΞΌ\mu, and check scale invariance;
  • state the coupled evolution and the monotonicity formula, and explain its proof;
  • show that W=0\mathcal W = 0 for the Gaussian on Rn\mathbb{R}^n and connect μ≀0\mu \leq 0 on Rn\mathbb{R}^n to the logarithmic Sobolev inequality;
  • prove that shrinking breathers are shrinking gradient solitons;
  • explain Perelman's statistical analogy, and its status as a heuristic.

Logarithmic Sobolev inequalities

In the world Model Information, concentration and the Gaussian

Leonard Gross proved in 1975 the Gaussian logarithmic Sobolev inequality: for the standard Gaussian measure Ξ³\gamma on Rn\mathbb{R}^n and smooth Ο•\phi with βˆ«Ο•2 dΞ³=1\int\phi^2\,d\gamma = 1,

βˆ«Ο•2log⁑ϕ2 dγ≀2βˆ«βˆ£βˆ‡Ο•βˆ£2 dΞ³.\int\phi^2\log\phi^2\,d\gamma \leq 2\int|\nabla\phi|^2\,d\gamma.

It has no dimension-dependent constant, which makes it work in infinite dimensions, and Gross showed it is equivalent to the hypercontractivity of the Ornstein–Uhlenbeck semigroup, the heat flow that relaxes to the Gaussian. Logarithmic Sobolev inequalities are now basic tools in probability (concentration of measure: Lipschitz functions of many Gaussian variables are nearly constant), in information theory, where they relate entropy and Fisher information, and in the analysis of Markov chains and sampling algorithms. Perelman's ΞΌ(g,Ο„)\mu(g, \tau) asks how far a Riemannian manifold, viewed at scale Ο„\sqrt\tau, is from satisfying the Euclidean version.

The entropy and its monotonicity

Scale invariance. If g~=cg\tilde g = cg and Ο„~=cΟ„\tilde\tau = c\tau, then Ο„~R~=Ο„R\tilde\tau\tilde R = \tau R, Ο„~βˆ£βˆ‡f∣g~2=Ο„βˆ£βˆ‡f∣g2\tilde\tau|\nabla f|^2_{\tilde g} = \tau|\nabla f|^2_g, and (4πτ~)βˆ’n/2dV~=(4πτ)βˆ’n/2dV(4\pi\tilde\tau)^{-n/2}d\tilde V = (4\pi\tau)^{-n/2}dV: so W(cg,f,cΟ„)=W(g,f,Ο„)\mathcal W(cg, f, c\tau) = \mathcal W(g, f, \tau), and the constraint is preserved (Exercise 3.3).

The coupled evolution (Perelman I, (3.3)):

βˆ‚tg=βˆ’2Ric⁑,βˆ‚tf=βˆ’Ξ”f+βˆ£βˆ‡f∣2βˆ’R+n2Ο„,βˆ‚tΟ„=βˆ’1.\partial_tg = -2\operatorname{Ric}, \qquad \partial_tf = -\Delta f + |\nabla f|^2 - R + \frac{n}{2\tau}, \qquad \partial_t\tau = -1.

The equation for ff says exactly that u=(4πτ)βˆ’n/2eβˆ’fu = (4\pi\tau)^{-n/2}e^{-f} satisfies the conjugate heat equation β–‘βˆ—u=0\square^*u = 0 (9B.7 The Heat Equation on a Manifold), which preserves the constraint ∫u dV=1\int u\,dV = 1.

Theorem 3.1 Monotonicity of W\mathcal W (Perelman I, (3.4))

Along the coupled evolution on a closed manifold,

ddtW=∫M2Ο„βˆ£Ric⁑+βˆ‡2fβˆ’12Ο„g∣2(4πτ)βˆ’n/2eβˆ’f dVβ‰₯0,\frac{d}{dt}\mathcal W = \int_M2\tau\Big|\operatorname{Ric} + \nabla^2f - \frac{1}{2\tau}g\Big|^2(4\pi\tau)^{-n/2}e^{-f}\,dV \geq 0,

with equality exactly when Ric⁑+βˆ‡2f=12Ο„g\operatorname{Ric} + \nabla^2f = \frac{1}{2\tau}g: a shrinking gradient soliton.

Perelman calls the derivation "a routine computation", and it is, given 12A.2 Ricci Flow as a Gradient Flow. The cleanest route goes through a pointwise formula that he proves later (Proposition 9.1, 12A.6 Pseudolocality). The function v=[Ο„(2Ξ”fβˆ’βˆ£βˆ‡f∣2+R)+fβˆ’n]uv = [\tau(2\Delta f - |\nabla f|^2 + R) + f - n]u has integral W\mathcal W (integrate Ξ”f u\Delta f\,u by parts), and it satisfies β–‘βˆ—v=βˆ’2Ο„βˆ£Ric⁑+βˆ‡2fβˆ’12Ο„g∣2u\square^*v = -2\tau|\operatorname{Ric} + \nabla^2f - \frac{1}{2\tau}g|^2u. Since βˆ‚t dV=βˆ’R dV\partial_t\,dV = -R\,dV and βˆ«Ξ”v dV=0\int\Delta v\,dV = 0, the time derivative of ∫v dV\int v\,dV is βˆ’βˆ«β–‘βˆ—v dV-\int\square^*v\,dV, which is the monotonicity formula (Exercise 3.6). The pointwise formula is also how Perelman localises the argument in Β§Β§9–10.

ΞΌ\mu and Ξ½\nu. Let

ΞΌ(g,Ο„)=inf⁑{W(g,f,Ο„):∫(4πτ)βˆ’n/2eβˆ’fdV=1},Ξ½(g)=inf⁑τ>0ΞΌ(g,Ο„).\mu(g, \tau) = \inf\Big\{\mathcal W(g, f, \tau) : \int(4\pi\tau)^{-n/2}e^{-f}dV = 1\Big\}, \qquad \nu(g) = \inf_{\tau > 0}\mu(g, \tau).

On a closed manifold the infimum defining ΞΌ\mu is attained by a smooth ff; this follows from work of Oscar Rothaus (1981) on logarithmic Sobolev inequalities, and uses the Sobolev embedding (4A.10 Sobolev Embeddings and Critical Exponents) with care at the logarithmic term. By monotonicity, running the conjugate heat equation backwards from a minimiser as in 12A.2 Ricci Flow as a Gradient Flow:

ΞΌ(g(t1),Ο„+(t2βˆ’t1))≀μ(g(t2),Ο„)(t1<t2),\mu(g(t_1), \tau + (t_2 - t_1)) \leq \mu(g(t_2), \tau) \qquad (t_1 < t_2),

and Ξ½(g(t))\nu(g(t)) is nondecreasing.

On Euclidean space: the Gaussian

On flat Rn\mathbb{R}^n, take f=∣x∣24Ο„f = \frac{|x|^2}{4\tau}. Then u=(4πτ)βˆ’n/2eβˆ’βˆ£x∣2/4Ο„u = (4\pi\tau)^{-n/2}e^{-|x|^2/4\tau} is the heat kernel (6A.3 The Heat Equation on ℝⁿ), the constraint holds, and

W=∫[∣x∣24Ο„+∣x∣24Ο„βˆ’n]u dx=2nΟ„2Ο„βˆ’n=0,\mathcal W = \int\Big[\frac{|x|^2}{4\tau} + \frac{|x|^2}{4\tau} - n\Big]u\,dx = \frac{2n\tau}{2\tau} - n = 0,

using ∫∣x∣2u dx=2nΟ„\int|x|^2u\,dx = 2n\tau. The Gaussian is a shrinking soliton (with Ric⁑+βˆ‡2f=12Ο„g\operatorname{Ric} + \nabla^2f = \frac{1}{2\tau}g, 11B.1 Ricci Solitons), so it is the equality case. For any other ff on Rn\mathbb{R}^n, W(Ξ΄,f,Ο„)β‰₯0\mathcal W(\delta, f, \tau) \geq 0; Perelman notes that this is Gross's inequality after the substitution f=∣x∣22βˆ’2log⁑ϕf = \frac{|x|^2}{2} - 2\log\phi (at Ο„=12\tau = \frac12) and an integration by parts (Exercise 3.5). So ΞΌ(Rn,Ο„)=0\mu(\mathbb{R}^n, \tau) = 0, and Figure 3.1 shows the minimisation in a one-parameter family.

Figure 3.1. W(R,fΟƒ,Ο„)\mathcal W(\mathbb{R}, f_\sigma, \tau) for Gaussian test functions of width Οƒ\sigma at fixed Ο„\tau: W=12(Ο„Οƒβˆ’1+log⁑στ)β‰₯0\mathcal W = \frac12\big(\frac\tau\sigma - 1 + \log\frac\sigma\tau\big) \geq 0, with minimum 00 exactly at Οƒ=Ο„\sigma = \tau, where uu is the heat kernel (computed from the closed form and checked by numerical integration).

On a closed manifold

Perelman shows that for any closed (M,g)(M, g), ΞΌ(g,Ο„)<0\mu(g, \tau) < 0 for small Ο„>0\tau > 0 and ΞΌ(g,Ο„)β†’0\mu(g, \tau) \to 0 as Ο„β†’0\tau \to 0. He sketches the proof and leaves the details, which are not hard, to the reader. Negativity: run the conjugate heat equation backwards from a delta function at a later time Ο„Λ‰\bar\tau; along it Wβ†’0\mathcal W \to 0 as the delta is approached, so by monotonicity W<0\mathcal W < 0 earlier. The limit: rescaling the metric by 12Ο„\frac{1}{2\tau} (which takes Ο„\tau to 12\frac12), the manifold looks Euclidean at scale Ο„\sqrt\tau, and a minimiser with W≀c<0\mathcal W \leq c < 0 would produce a function on Rn\mathbb{R}^n violating Gross's inequality. So ΞΌ\mu measures the failure of the Euclidean logarithmic Sobolev inequality at scale Ο„\sqrt\tau. Figure 3.2 shows an upper bound for ΞΌ\mu on the round sphere.

Figure 3.2. An upper bound for ΞΌ\mu on the unit S2S^2: W\mathcal W of the constant test function, 2Ο„βˆ’logβ‘Ο„βˆ’22\tau - \log\tau - 2 (computed). It is negative near Ο„=12\tau = \frac12, with minimum log⁑2βˆ’1β‰ˆβˆ’0.31\log2 - 1 \approx -0.31, so ΞΌ(S2,12)<0\mu(S^2, \tfrac12) < 0. For small Ο„\tau the constant is a poor test function (the true ΞΌ\mu tends to 00, as Perelman shows, using test functions concentrated at a point), and for large Ο„\tau the bound grows like 2Ο„2\tau, reflecting Ξ»(S2)=2>0\lambda(S^2) = 2 > 0.

No shrinking breathers

Theorem 3.2 No shrinking breathers (Perelman I, Β§3)

A shrinking breather on a closed manifold, g(t2)=cβ€‰Ο•βˆ—g(t1)g(t_2) = c\,\phi^*g(t_1) with c<1c < 1, is a shrinking gradient soliton.

Proof. Choose Ο„1\tau_1 with Ο„1βˆ’(t2βˆ’t1)Ο„1=c\frac{\tau_1 - (t_2 - t_1)}{\tau_1} = c, so that Ο„2=Ο„1βˆ’(t2βˆ’t1)=cΟ„1\tau_2 = \tau_1 - (t_2 - t_1) = c\tau_1. By scale and diffeomorphism invariance, ΞΌ(g(t2),Ο„2)=ΞΌ(cΟ•βˆ—g(t1),cΟ„1)=ΞΌ(g(t1),Ο„1)\mu(g(t_2), \tau_2) = \mu(c\phi^*g(t_1), c\tau_1) = \mu(g(t_1), \tau_1). Monotonicity makes ΞΌ\mu constant along the flow between, so a minimiser at t2t_2, flowed backwards, achieves equality in Theorem 3.1: Ric⁑+βˆ‡2f=12Ο„g\operatorname{Ric} + \nabla^2f = \frac{1}{2\tau}g.

This is the template "monotone quantity, invariant under the symmetries, equality case is a soliton", now at full strength. The same structure appears throughout the Path:

monotone quantity flow equality case
Bishop–Gromov volume ratio (9B.2 Volume Comparison) (increasing radius) the model space
Li–Yau and the heat entropy (6A.10 Entropy, Information and Diffusion) heat equation the Gaussian heat kernel
Huisken's Gaussian density (6A.8 Curve Shortening and the First Geometric Flows) mean curvature flow self-shrinkers
Hamilton's surface entropy (11A.7 Ricci Flow on Surfaces) 2D normalised flow round sphere
F\mathcal F and Ξ»\lambda (12A.2 Ricci Flow as a Gradient Flow) Ricci flow steady gradient solitons
W\mathcal W and ΞΌ\mu (this chapter) Ricci flow shrinking gradient solitons
reduced volume (12A.5 Reduced Distance and Reduced Volume) Ricci flow, backwards the Gaussian soliton

Perelman's statistical analogy

In Β§5, Perelman interprets W\mathcal W through statistical mechanics. For a canonical ensemble at inverse temperature Ξ²\beta, the partition function Z=∫eβˆ’Ξ²EdΟ‰(E)Z = \int e^{-\beta E}d\omega(E) determines the average energy ⟨E⟩=βˆ’βˆ‚Ξ²log⁑Z\langle E\rangle = -\partial_\beta\log Z, the entropy S=β⟨E⟩+log⁑ZS = \beta\langle E\rangle + \log Z and the fluctuation Οƒ=βˆ‚Ξ²2log⁑Z\sigma = \partial_\beta^2\log Z. Perelman lets Ο„\tau play the part of the temperature, sets log⁑Z=∫(βˆ’f+n2) dm\log Z = \int(-f + \frac n2)\,dm with dm=u dVdm = u\,dV, and computes formally that

S=βˆ’βˆ«(Ο„(R+βˆ£βˆ‡f∣2)+fβˆ’n)dm=βˆ’W,Οƒ=2Ο„4∫∣Ric⁑+βˆ‡2fβˆ’12Ο„g∣2dmβ‰₯0,S = -\int\big(\tau(R + |\nabla f|^2) + f - n\big)dm = -\mathcal W, \qquad \sigma = 2\tau^4\int\Big|\operatorname{Ric} + \nabla^2f - \frac{1}{2\tau}g\Big|^2dm \geq 0,

so that W\mathcal W is minus an entropy and the monotonicity formula is the statement that the fluctuation is nonnegative, vanishing only on shrinking solitons. He explicitly sets aside the question of whether a "density of states" exists that would make this literal. It is a heuristic that explains the name and suggested the formula, not a physical model of anything, and the proofs do not use it. In the same section Perelman asks whether an ancient solution along which this entropy stays bounded must be a shrinking gradient soliton, a question close to the study of ΞΊ\kappa-solutions (12B.1 ΞΊ-Solutions).

Where this goes From entropy to volume

12A.4 ΞΊ-Noncollapsing uses ΞΌ\mu to prove noncollapsing. If a ball of radius rr with bounded curvature had very small volume, a test function concentrated on it would make W(g,f,r2)\mathcal W(g, f, r^2) very negative. Monotonicity carries this back to time 00, where ΞΌ\mu is bounded below on a closed manifold: a contradiction.

History

Gross proved the Gaussian logarithmic Sobolev inequality in 1975, and Rothaus studied minimisers of logarithmic Sobolev functionals in 1981. Bakry and Γ‰mery (1985) connected such inequalities to curvature. Perelman introduced W\mathcal W in Β§3 of his first preprint, noting in his historical remarks that the logarithmic Sobolev inequality had appeared in geometric evolution equations in work of Klaus Ecker, and that Ivey had proved the no-breathers theorem in dimension three.

Recall Where we stand

W(g,f,Ο„)=∫[Ο„(βˆ£βˆ‡f∣2+R)+fβˆ’n](4πτ)βˆ’n/2eβˆ’fdV\mathcal W(g, f, \tau) = \int[\tau(|\nabla f|^2 + R) + f - n](4\pi\tau)^{-n/2}e^{-f}dV, with ∫(4πτ)βˆ’n/2eβˆ’f=1\int(4\pi\tau)^{-n/2}e^{-f} = 1, is scale-invariant. Along the Ricci flow with βˆ‚tΟ„=βˆ’1\partial_t\tau = -1 and u=(4πτ)βˆ’n/2eβˆ’fu = (4\pi\tau)^{-n/2}e^{-f} solving β–‘βˆ—u=0\square^*u = 0, ddtW=∫2Ο„βˆ£Ric⁑+βˆ‡2fβˆ’g2Ο„βˆ£2uβ‰₯0\frac{d}{dt}\mathcal W = \int2\tau|\operatorname{Ric} + \nabla^2f - \frac{g}{2\tau}|^2u \geq 0, with equality on shrinking gradient solitons. On Rn\mathbb{R}^n the Gaussian gives W=0\mathcal W = 0 and ΞΌ=0\mu = 0 is Gross's log-Sobolev inequality; on closed manifolds ΞΌ(g,Ο„)\mu(g, \tau) is negative for small Ο„\tau and tends to 00. Shrinking breathers are shrinking solitons. Perelman's statistical analogy reads W\mathcal W as minus an entropy. 12A.4 ΞΊ-Noncollapsing turns ΞΌ\mu into a volume bound.

Exercises

Exercise 3.3 Scale invariance

Verify that W(cg,f,cΟ„)=W(g,f,Ο„)\mathcal W(cg, f, c\tau) = \mathcal W(g, f, \tau) and that the constraint is unchanged, using Rcg=cβˆ’1RgR_{cg} = c^{-1}R_g, βˆ£βˆ‡f∣cg2=cβˆ’1βˆ£βˆ‡f∣g2|\nabla f|^2_{cg} = c^{-1}|\nabla f|^2_g and dVcg=cn/2dVgdV_{cg} = c^{n/2}dV_g.

Solution

cΟ„β‹…cβˆ’1(βˆ£βˆ‡f∣2+R)=Ο„(βˆ£βˆ‡f∣2+R)c\tau\cdot c^{-1}(|\nabla f|^2 + R) = \tau(|\nabla f|^2 + R); fβˆ’nf - n is unchanged; (4Ο€cΟ„)βˆ’n/2eβˆ’fcn/2dV=(4πτ)βˆ’n/2eβˆ’fdV(4\pi c\tau)^{-n/2}e^{-f}c^{n/2}dV = (4\pi\tau)^{-n/2}e^{-f}dV. Both the integrand and the measure are invariant.

Exercise 3.4 Gaussians of the wrong width

On R\mathbb{R} (with n=1n = 1), let uu be the Gaussian density of variance 2Οƒ2\sigma, u=(4πσ)βˆ’1/2eβˆ’x2/4Οƒu = (4\pi\sigma)^{-1/2}e^{-x^2/4\sigma}, and define ff by u=(4πτ)βˆ’1/2eβˆ’fu = (4\pi\tau)^{-1/2}e^{-f}. Show f=x24Οƒ+12log⁑στf = \frac{x^2}{4\sigma} + \frac12\log\frac\sigma\tau, and compute W=12(Ο„Οƒβˆ’1+log⁑στ)\mathcal W = \frac12\big(\frac\tau\sigma - 1 + \log\frac\sigma\tau\big). Show it is β‰₯0\geq 0 with equality only at Οƒ=Ο„\sigma = \tau.

Solution

Taking logarithms, f=x24Οƒ+12log⁑4πσ4πτf = \frac{x^2}{4\sigma} + \frac12\log\frac{4\pi\sigma}{4\pi\tau}. Then ∣fβ€²βˆ£2=x24Οƒ2|f'|^2 = \frac{x^2}{4\sigma^2}, and with ∫x2u=2Οƒ\int x^2u = 2\sigma: W=Ο„2Οƒ4Οƒ2+2Οƒ4Οƒ+12logβ‘ΟƒΟ„βˆ’1=12(τσ+1+logβ‘ΟƒΟ„βˆ’2)\mathcal W = \tau\frac{2\sigma}{4\sigma^2} + \frac{2\sigma}{4\sigma} + \frac12\log\frac\sigma\tau - 1 = \frac12\big(\frac\tau\sigma + 1 + \log\frac\sigma\tau - 2\big). With s=τσs = \frac\tau\sigma: sβˆ’1βˆ’log⁑sβ‰₯0s - 1 - \log s \geq 0, with equality only at s=1s = 1.

Exercise 3.5 From Wβ‰₯0\mathcal W \geq 0 to Gross

On Rn\mathbb{R}^n with Ο„=12\tau = \frac12, write u=(2Ο€)βˆ’n/2eβˆ’fu = (2\pi)^{-n/2}e^{-f} and f=∣x∣22βˆ’2log⁑ϕf = \frac{|x|^2}{2} - 2\log\phi, so that u=Ο•2Ξ³u = \phi^2\gamma with Ξ³\gamma the standard Gaussian density and βˆ«Ο•2 dΞ³=1\int\phi^2\,d\gamma = 1. Show that W=∫[12βˆ£βˆ‡f∣2+fβˆ’n]u dx\mathcal W = \int\big[\frac12|\nabla f|^2 + f - n\big]u\,dx becomes, after an integration by parts, 2βˆ«βˆ£βˆ‡Ο•βˆ£2dΞ³βˆ’βˆ«Ο•2log⁑ϕ2 dΞ³2\int|\nabla\phi|^2d\gamma - \int\phi^2\log\phi^2\,d\gamma, so Wβ‰₯0\mathcal W \geq 0 is Gross's inequality.

Solution

βˆ‡f=xβˆ’2βˆ‡Ο•Ο•\nabla f = x - \frac{2\nabla\phi}{\phi}, so 12βˆ£βˆ‡f∣2u=(∣x∣22βˆ’2⟨x,βˆ‡Ο•βŸ©Ο•+2βˆ£βˆ‡Ο•βˆ£2Ο•2)Ο•2Ξ³\frac12|\nabla f|^2u = \big(\frac{|x|^2}{2} - 2\frac{\langle x, \nabla\phi\rangle}{\phi} + \frac{2|\nabla\phi|^2}{\phi^2}\big)\phi^2\gamma. And (fβˆ’n)u=(∣x∣22βˆ’log⁑ϕ2βˆ’n)Ο•2Ξ³(f - n)u = \big(\frac{|x|^2}{2} - \log\phi^2 - n\big)\phi^2\gamma. Integrating by parts against the Gaussian, ∫2Ο•βŸ¨x,βˆ‡Ο•βŸ©Ξ³=∫⟨x,βˆ‡Ο•2⟩γ=βˆ«Ο•2(∣x∣2βˆ’n)Ξ³\int2\phi\langle x, \nabla\phi\rangle\gamma = \int\langle x, \nabla\phi^2\rangle\gamma = \int\phi^2(|x|^2 - n)\gamma. Collecting: ∫(∣x∣2βˆ’(∣x∣2βˆ’n)βˆ’n)Ο•2Ξ³+2βˆ«βˆ£βˆ‡Ο•βˆ£2Ξ³βˆ’βˆ«Ο•2log⁑ϕ2Ξ³=2βˆ«βˆ£βˆ‡Ο•βˆ£2dΞ³βˆ’βˆ«Ο•2log⁑ϕ2dΞ³\int\big(|x|^2 - (|x|^2 - n) - n\big)\phi^2\gamma + 2\int|\nabla\phi|^2\gamma - \int\phi^2\log\phi^2\gamma = 2\int|\nabla\phi|^2d\gamma - \int\phi^2\log\phi^2d\gamma.

Exercise 3.6 From the pointwise formula to the integral

Assume β–‘βˆ—v=βˆ’2Ο„βˆ£Ric⁑+βˆ‡2fβˆ’g2Ο„βˆ£2u\square^*v = -2\tau|\operatorname{Ric} + \nabla^2f - \frac{g}{2\tau}|^2u (Perelman I, Proposition 9.1). Using βˆ‚t dV=βˆ’R dV\partial_t\,dV = -R\,dV, show ddt∫v dV=∫(βˆ‚tvβˆ’Rv) dV=βˆ’βˆ«β–‘βˆ—v dV\frac{d}{dt}\int v\,dV = \int(\partial_tv - Rv)\,dV = -\int\square^*v\,dV, and that ∫v dV=W\int v\,dV = \mathcal W. Deduce the monotonicity formula.

Solution

ddt∫v dV=∫(βˆ‚tvβˆ’Rv)dV=∫(βˆ’β–‘βˆ—vβˆ’Ξ”v)dV=βˆ’βˆ«β–‘βˆ—v dV\frac{d}{dt}\int v\,dV = \int(\partial_tv - Rv)dV = \int(-\square^*v - \Delta v)dV = -\int\square^*v\,dV, since βˆ«Ξ”v=0\int\Delta v = 0. And ∫v=∫[Ο„(2Ξ”fβˆ’βˆ£βˆ‡f∣2+R)+fβˆ’n]u\int v = \int[\tau(2\Delta f - |\nabla f|^2 + R) + f - n]u, with βˆ«Ξ”f u=βˆ«βˆ£βˆ‡f∣2u\int\Delta f\,u = \int|\nabla f|^2u (integrate by parts, βˆ‡u=βˆ’uβˆ‡f\nabla u = -u\nabla f), so ∫v=W\int v = \mathcal W. Hence ddtW=∫2Ο„βˆ£β‹―βˆ£2uβ‰₯0\frac{d}{dt}\mathcal W = \int2\tau|\cdots|^2u \geq 0.

Exercise 3.7 Rehearsal: a test function on the sphere

On the round unit SnS^n, the constant ff satisfying the constraint is f=log⁑∣Sn∣(4πτ)n/2f = \log\frac{|S^n|}{(4\pi\tau)^{n/2}}. Show that W(g,f,Ο„)=n(nβˆ’1)Ο„+log⁑∣Sn∣(4πτ)n/2βˆ’n\mathcal W(g, f, \tau) = n(n - 1)\tau + \log\frac{|S^n|}{(4\pi\tau)^{n/2}} - n, and for n=2n = 2 that this is 2Ο„βˆ’logβ‘Ο„βˆ’22\tau - \log\tau - 2, minimised at Ο„=12\tau = \frac12. What does its negativity there tell you about ΞΌ(S2,12)\mu(S^2, \frac12)?

Solution

With constant ff, βˆ£βˆ‡f∣2=0|\nabla f|^2 = 0, R=n(nβˆ’1)R = n(n - 1), and ∫u=1\int u = 1, so W=Ο„n(nβˆ’1)+fβˆ’n\mathcal W = \tau n(n - 1) + f - n. For n=2n = 2, ∣S2∣=4Ο€|S^2| = 4\pi and f=log⁑4Ο€4πτ=βˆ’log⁑τf = \log\frac{4\pi}{4\pi\tau} = -\log\tau. The derivative 2βˆ’1Ο„2 - \frac1\tau vanishes at Ο„=12\tau = \frac12, where the value is 1+log⁑2βˆ’2=log⁑2βˆ’1<01 + \log2 - 2 = \log2 - 1 < 0. Since ΞΌ\mu is an infimum, ΞΌ(S2,12)≀log⁑2βˆ’1<0\mu(S^2, \frac12) \leq \log2 - 1 < 0.

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