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Course 6Book 6C: Nonlinear PDE: Variational and Geometric MethodsChapter 3
Symmetry, Noether’s Theorem and Moving Planes
Invariance gives conservation laws, and maximum principles give symmetry.
Read with Evans, Partial Differential Equations, section 8.6 (invariance and Noether's theorem; 2nd edition) and section 9.5 (geometric properties of solutions: star-shaped level sets, radial symmetry by moving planes). Gidas, Ni and Nirenberg, "Symmetry and related properties via the maximum principle" (Comm. Math. Phys. 68, 1979), and Berestycki and Nirenberg, "On the method of moving planes and the sliding method" (Bol. Soc. Brasil. Mat. 22, 1991), are the original sources. This chapter proves Noether's theorem for translations and internal symmetries, the maximum principles for narrow and small domains, and the Gidas–Ni–Nirenberg symmetry theorem.
Symmetry enters PDE in two opposite directions. If an equation is symmetric, invariant under translations, rotations, scalings or some internal transformation of the unknown, then its solutions satisfy conservation laws: integrals that do not change in time, or divergence identities that hold for every solution. That is Emmy Noether's theorem (1918), the reason energy is conserved because the laws of physics do not change in time, and momentum because they do not change from place to place. Pohozaev's identity (6C.2 Critical Points and the Mountain Pass) is a Noether identity for scaling.
The other direction is subtler: if the problem is symmetric (the domain is a ball, the equation is rotation invariant), are its solutions symmetric too? Not always, since symmetric problems can have asymmetric solutions (a buckled beam chooses a side). But for positive solutions of in a ball with zero boundary values, the answer is yes, and the proof, the method of moving planes of Basilis Gidas, Wei-Ming Ni and Louis Nirenberg (1979), is a beautiful use of the maximum principle: reflect the solution in a plane, compare it with itself, and move the plane until it reaches the centre. The same method classifies the "bubbles" that appear when compactness fails at the critical exponent, and symmetry results of this kind, proved by maximum principles, are a recurring theme in the classification of solitons and singularity models of geometric flows.
By the end of this chapter you will be able to:
- derive the energy–momentum tensor of a variational problem, and prove that it is divergence-free when the Lagrangian does not depend on ;
- prove Noether's theorem for internal symmetries, and derive energy, momentum and charge conservation for wave and Schrödinger equations;
- see Pohozaev's identity as the conservation law of the scaling symmetry;
- prove the maximum principle for narrow domains and, with the Alexandrov–Bakelman–Pucci estimate, for domains of small measure;
- prove that positive solutions of in a ball vanishing on the boundary are radially symmetric and decreasing, and identify the critical-exponent bubbles.
Round stars
A star in equilibrium balances gravity against pressure. In the simplest models the pressure depends on the density as a power, (a polytrope of index ), and combining hydrostatic equilibrium with Newton's law of gravitation gives, after scaling, the Lane–Emden equation
with proportional to and the Laplacian in three dimensions. Jonathan Homer Lane derived it in 1870, Robert Emden studied it in depth in his 1907 book Gaskugeln ("gas spheres"), and Arthur Eddington used polytropes to build the first quantitative models of stellar interiors in the 1920s. The index models fully convective stars and white dwarfs at low density; is Eddington's standard model; is the critical exponent for , at which the star has infinite radius but finite mass.
Astronomers always assume the star is spherical and solve an ODE in the radius. Is that justified? A non-rotating fluid star should be round, and for the Lane–Emden equation on a ball with on the surface, the Gidas–Ni–Nirenberg theorem of this chapter proves it: every positive solution is radially symmetric and decreasing outward. (Rotation, magnetic fields and companions break the symmetry, and real stars are slightly oblate; the theorem is about the idealised problem.)
Translations: the energy–momentum tensor
Consider a variational problem with Lagrangian that does not depend on , and its Euler–Lagrange equation (6A.11 Calculus of Variations and Gradient Flows)
The independence of means the problem is invariant under translations . Noether's theorem says each such symmetry gives a divergence-free vector field.
If and solves the Euler–Lagrange equation, then for each ,
Proof. By the product rule and the Euler–Lagrange equation,
On the other hand, since depends on only through and , the chain rule gives . The two expressions agree, so .
The matrix is the energy–momentum tensor (or stress tensor) of the problem. For time-dependent problems, treat time as one of the coordinates.
The wave equation is the Euler–Lagrange equation of , with in the variables , , . Invariance under time translation () gives
(Exercise 3.9): the energy density changes only by the flux , so the total energy is conserved for solutions decaying at infinity (6B.3 The Wave Equation). Invariance under the space translation in gives conservation of the momentum . These are exactly the conserved quantities of a vibrating string or membrane.
Integrating a divergence identity. Noether identities are usually used integrated against a vector field or over a region. Integrating over a domain gives boundary relations; multiplying by and summing gives the virial or Pohozaev-type identities. For , the scaling vector field is not a symmetry (except at the critical exponent), but the identity holds for every solution (using ), and . Integrated over with on , this is exactly Pohozaev's identity (Exercise 3.11). Scaling would be a symmetry if were a divergence, which happens at the critical exponent, where the identity has no interior term left: that is why the critical exponent is special.
Internal symmetries
A symmetry can also act on the values of rather than on : rotating a complex-valued function by a phase, , or rotating a vector-valued one. Let , with , and let be a one-parameter group of linear maps of with and generator .
Suppose for all , , , where acts on each column of . If solves the Euler–Lagrange equations (), then the current
is divergence-free: .
Proof. Differentiate the invariance in at :
Since is constant, . Now compute the divergence of , using the Euler–Lagrange equations:
For the Schrödinger equation with complex , the phase symmetry gives conservation of , the total probability (or charge), with current (Exercise 3.10). For harmonic maps into a sphere (6C.1 Regularity of Minimisers and Constraints), rotations of the target give the conservation laws , which Frédéric Hélein used in 1991 to prove that weakly harmonic maps from surfaces are smooth, a case where De Giorgi–Nash–Moser fails (6C.7 Harmonic Maps and Their Heat Flow).
The general theorem (Evans, section 8.6.2) treats transformations that move both and , and it gives a conserved current for every one-parameter group of symmetries. Emmy Noether's 1918 paper also contained a "second theorem", for symmetries depending on arbitrary functions (gauge symmetries, diffeomorphisms): such symmetries give identities satisfied by the Euler–Lagrange expressions themselves, whether or not is a solution. The contracted Bianchi identity of Riemannian geometry is one (Exercise 3.15).
Maximum principles for thin and small domains
The second half of the chapter proves symmetry. Its key tool is a maximum principle for operators whose zero-order coefficient has no sign, which is what comparing two solutions of a nonlinear equation produces. Such operators do not satisfy the maximum principle in general ( has the positive solution with zero boundary values, and so does ), but they do on domains that are thin or small, because there the Laplacian dominates.
Let be bounded and contained in a slab , and let in . Suppose satisfies in and on . If , then in .
Proof. Let . On the slab the argument of the cosine lies in , so , and with . Write . Then
If , hence , were negative somewhere, would have a negative minimum at an interior point (it is on ). There and , so , since , and . That contradicts .
Thinness in one direction is not always available. Smallness of volume is enough, thanks to the Alexandrov–Bakelman–Pucci estimate of 6B.8 Lᵖ Theory and Strong Solutions.
Let and . There is such that if , then in and on imply in .
Proof. Let , so in and on , and suppose . Work on the open set . On its boundary (a boundary point inside has by continuity; one on has and, as a limit of points with , also ). In , . Apply ABP (6B.8 Lᵖ Theory and Strong Solutions) on , with , , and diameter at most :
If , the factor in front of is less than , so , a contradiction.
Both lemmas give only . To upgrade this to , and to get a sign for the normal derivative at the boundary, we need the strong maximum principle and Hopf's lemma of 6A.5 Maximum Principles in the presence of a zero-order term. For non-negative supersolutions they carry over.
Let be connected, , and with and in . Then either or in . If in , and at a point where has an interior ball, is up to with , then for the outward normal .
Proof. Since , , so . Put , so . First a weak maximum principle: a function with cannot have a non-negative interior maximum, since there and . Now repeat the proof of Hopf's lemma in 6A.5 Maximum Principles (the lemma there with , ): on the ball touching at , with inside, the barrier satisfies on the annulus once is large. With , in the annulus and on its boundary for small , so in the annulus by the weak principle just proved, and . Hence , i.e. . The first statement follows exactly as the strong maximum principle followed from Hopf's lemma in 6A.5 Maximum Principles: if and were both non-empty, a largest ball in touching at an interior point would give , while is an interior minimum of , so .
Moving planes
Let be the unit ball in , locally Lipschitz, and a solution of
Then is radially symmetric, , and for .
Proof. Set-up. It suffices to prove symmetry in the direction (then apply it to every direction, by rotation invariance of the problem). For let , the cap , and the reflection of in . The reflected cap lies inside (reflecting a point of the cap towards the centre moves it closer to the centre; Exercise 3.12). On compare with its reflection:
Since also solves the equation,
(and where the denominator vanishes). Because is Lipschitz on , for a constant independent of . On the boundary of the cap: on the flat part , ; on the curved part , while is an interior point of , so .
Claim: in for every .
Step 1: start near the edge. For close to , the cap lies in the slab of width , so Lemma 3.4 gives . And (it is positive on the curved boundary). Lemma 3.6 gives in the (connected) cap.
Step 2: move the plane. Let , and suppose . By continuity in , in , and as in Step 1 it is not identically zero, so there. Let be the constant of Lemma 3.5 for and this , and choose a compact with . On , , so by uniform continuity on for all in some interval , and also, shrinking , . On the open set we have , and on its boundary (on by the previous sentence, on and the curved boundary as in the set-up). By Lemma 3.5, on , hence on all of , and by Lemma 3.6 . This holds for every , contradicting the definition of . So .
Step 3: symmetry. Letting , for . Applying the same argument in the direction gives the reverse inequality, so is symmetric under . Every direction is equivalent, so is symmetric under every reflection through a hyperplane through the origin, hence radial.
Step 4: monotonicity. For , in and on . By Lemma 3.6 (the cap has an interior ball at each point of ), the normal derivative of into the cap is positive: on . There, (as on the plane). So on for every , which for the radial function means for .
The proof never solved the equation. It compared the solution with its own reflection, used the maximum principle to keep the comparison one-signed, and slid the plane until it could go no further. That only the sign of and the boundary condition entered, together with the Lipschitz bound on , is why the method is so robust: it works for fully nonlinear equations and on unbounded domains with suitable decay.
Positivity is needed. Sign-changing solutions in a ball need not be radial: for the second eigenfunctions of the disc, , are odd in . And the ball is needed: in an annulus, positive solutions need not be radial: Charles Coffman showed in 1984 that in thin planar annuli has positive non-radial solutions, more and more of them as the annulus gets thinner.
Bubbles
On all of , a moving-plane argument "from infinity" classifies the positive solutions at the critical exponent.
Every positive solution of on , , is of the form
for some and .
These are the bubbles of 4A.11 Sobolev Embeddings and Critical Exponents: they all have the same energy , they are the extremals of the sharp Sobolev inequality (Aubin and Talenti, 1976), and they are the profiles that concentrate when Palais–Smale fails at the critical exponent (6C.2 Critical Points and the Mountain Pass). Luis Caffarelli, Basilis Gidas and Joel Spruck proved the theorem in 1989 (without assuming any decay at infinity, which is the hard part; Gidas, Ni and Nirenberg had proved it under a decay assumption). Geometrically, the bubbles are the round metric of the sphere, pulled back to by stereographic projection and written as a conformal factor (Exercise 3.14).
Perelman's functionals are invariant under diffeomorphisms, and Noether's second theorem is why their first variations satisfy identities (such as the contracted Bianchi identity) that make the Ricci flow a gradient flow only up to diffeomorphism (12A.2 Ricci Flow as a Gradient Flow, Exercise 3.15). Maximum-principle symmetry theorems recur in the classification of singularity models: Simon Brendle proved in 2013 that every three-dimensional steady gradient Ricci soliton that is non-collapsed is rotationally symmetric, hence is the Bryant soliton, settling a question Perelman raised; his argument uses maximum principles for the linearised soliton equation in the same spirit as moving planes (11B.1 Ricci Solitons, 12B.1 κ-Solutions). In mean curvature flow, Brendle and Choi (2019) proved by related methods that every non-compact, strictly convex, non-collapsed ancient solution in is, up to symmetries, the bowl soliton.
History
Emmy Noether proved her theorems in 1918, in a paper motivated by the problem of energy conservation in Einstein's general relativity, at the invitation of Hilbert and Klein. Jonathan Lane (1870) and Robert Emden (1907) studied polytropic stars. The method of moving planes was invented by Aleksandr Alexandrov in 1956 to prove that the only compact embedded hypersurfaces of constant mean curvature are round spheres ("Alexandrov's soap bubble theorem"); James Serrin used it in 1971 for an overdetermined problem in fluid mechanics, and Gidas, Ni and Nirenberg adapted it to semilinear equations in 1979. Henri Berestycki and Louis Nirenberg simplified it with the small-domain maximum principle in 1991. Caffarelli, Gidas and Spruck's classification dates from 1989.
For a Lagrangian independent of , the energy–momentum tensor is divergence-free on solutions: energy and momentum conservation for waves. An internal symmetry with generator gives the divergence-free current : charge conservation for Schrödinger, rotation currents for harmonic maps into spheres. Contracting with the scaling field gives Pohozaev's identity. Operators with bounded of any sign satisfy the maximum principle on narrow domains (by a cosine weight) and on domains of small measure (by ABP). The method of moving planes reflects a positive solution of in a ball, compares it with itself on caps, and slides the plane to the centre: the solution is radial and decreasing (Gidas–Ni–Nirenberg). On , positive solutions at the critical exponent are exactly the bubbles. 6C.4 The Yamabe Problem and Critical Exponents puts the bubbles to work: they are the round sphere in disguise, and their energy is the threshold below which the Yamabe problem, the model variational problem at the critical exponent, regains compactness.
Exercises
With in the variables , compute and for from Theorem 3.1 and check that is the energy identity of Example 3.2.
Solution
and . So , and . The identity is .
For with complex and real , show directly that , and deduce that is constant for decaying solutions. Which symmetry of the equation is responsible?
Solution
, since . And , whose imaginary part is . So . The phase symmetry , generated by .
For , so : (a) show for solutions; (b) integrate over , with on , and recover Pohozaev's identity of 6C.2 Critical Points and the Mountain Pass.
Solution
(a) , and summing, the second term vanishes by Theorem 3.1. . (b) The divergence theorem gives . On , and , so . Rearranging gives .
For and with , show that , where . (Compare with .)
Solution
since and . So .
On the slab in one dimension, the function satisfies , at the ends, and is a negative solution. Explain why this shows that some smallness condition on relative to is necessary in Lemma 3.4, and compare the threshold obtained from this example with the lemma's .
Solution
With the function satisfies , is on the boundary, and is negative inside: the conclusion fails when . So the maximum principle can hold only for (the first Dirichlet eigenvalue must exceed ). The lemma's threshold is smaller by a factor , the price of using on a shifted interval so that stays bounded below; the sharp statement is that the maximum principle for with holds exactly when the first eigenvalue of on the domain exceeds .
For the critical exponent is . Show that solves on , using the radial Laplacian. Check that it is the case , of Theorem 3.8, and that .
Solution
With : , , and . So and , equal when . The formula gives . And at infinity, integrable in three dimensions.
On a closed manifold, the total scalar curvature is invariant under diffeomorphisms: . Its first variation in a direction is (9A.5 Computing Curvature, 12A.2 Ricci Flow as a Gradient Flow). (a) An infinitesimal diffeomorphism generated by a vector field changes by , with components . Show that invariance gives for every . (b) Integrate by parts (using the symmetry of ) to get for all , and conclude the contracted Bianchi identity . This is an identity, true for every metric, not only for critical points: exactly the content of Noether's second theorem for a symmetry group depending on arbitrary functions. Perelman's -functional has the same diffeomorphism invariance, and its corresponding identity is what allows the Ricci flow to be written as its gradient flow modulo diffeomorphisms (12A.2 Ricci Flow as a Gradient Flow).
Solution
(a) The family , with the flow of , has and , so the first variation in this direction vanishes. (b) With symmetric, , and integrating by parts on the closed manifold, . Since this vanishes for every , , that is, .
Free resources for this chapter
Chosen for what this chapter covers, and all free to read. Links checked Oct 20, 2026.
- Reference Noether's theoremWikipediaSymmetries and conservation laws.
- Reference Noether's second theoremWikipediaGauge symmetries and identities such as the Bianchi identity.
- Reference Stress–energy tensorWikipediaThe energy–momentum tensor in physics.
- Reference Lane–Emden equationWikipediaPolytropic stars and their radial solutions.
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