The Riccati equation for the distance function, and the focusing of light.
21 min read · Updated Oct 3, 2026
Read with Petersen's Riemannian Geometry, the chapter on Ricci curvature comparison (the distance function, the Riccati equation, mean curvature and Laplacian comparison), and Lee's Introduction to Riemannian Manifolds (2nd edition), chapter 11 (comparison theory). Cheeger and Ebin's Comparison Theorems in Riemannian Geometry, chapter 1, is the classical reference.
Book 9A turned curvature into local statements: at a point, along a geodesic, for small balls. Book 9B turns curvature bounds into global control. If the Ricci curvature is at least some value everywhere, how fast can geodesics spread, how large can balls be, how small can a manifold get before it collapses, and what can limits of such manifolds look like? These are the facts that the Ricci flow uses in every compactness argument, and the Ricci flow books quote them in a few lines. This book proves the core ones and states the rest in the exact form used later.
The first tool is the distance functionr(x)=d(p,x) from a point. Its Hessian measures how the geodesic spheres around p bend, and it obeys a first-order matrix ODE along each geodesic, a Riccati equation, driven by curvature. Comparing that ODE with the one for a model space gives Laplacian comparison: if Ric≥0, then Δr≤rn−1, as in Euclidean space. The same equation, read in spacetime, is Raychaudhuri's focusing equation, the engine of the singularity theorems of general relativity.
By the end of this chapter you will be able to:
describe where the distance function is smooth, and compute its gradient and Hessian;
derive the Riccati equation for the Hessian of distance and its traced form;
prove Laplacian comparison under a lower Ricci bound, and state Hessian comparison under sectional bounds;
explain in what sense the comparison holds across the cut locus;
relate the traced Riccati inequality to the focusing of light in general relativity.
In the worldModelRaychaudhuri, Penrose and the focusing of light
Follow a narrow bundle of light rays leaving a source, and measure its cross-sectional area A. In general relativity, the expansionθ=A1dλdA (with λ an affine parameter along the rays) obeys Raychaudhuri's equation. For a bundle that is not twisting, in a four-dimensional spacetime,
dλdθ=−21θ2−∣σ∣2−Ric(k,k),
where σ is the shear and k the tangent to the rays. The 21 is d1 with d=2, the dimension of the bundle's cross-section; for timelike geodesics (freely falling particles) the cross-section is three-dimensional and the coefficient is 31. Whenever matter has nonnegative energy density, Einstein's equations make Ric(k,k)≥0, so θ′≤−21θ2, and a bundle that starts converging reaches θ=−∞, a focal point, within a bounded affine distance.
Roger Penrose (1965) combined this inequality with a global argument to prove that a collapsing star which forms a "trapped surface" must produce a singularity: some light ray cannot be extended. Hawking and Penrose extended it to cosmology (1970), and Penrose received the 2020 Nobel Prize in Physics for the result. In this chapter the same inequality, with n−1 for d, appears as the traced Riccati inequality for the distance function, and it controls the Laplacian of distance on a Riemannian manifold.
Fix p∈M, with M complete, and let r(x)=d(p,x). Then r is smooth on M∖({p}∪Cut(p)), where Cut(p) is the cut locus of 9A.3 Geodesics and the Exponential Map, a closed set of measure zero. On that set:
∣∇r∣=1 (the Gauss lemma), and ∇r=∂r is the velocity of the unit-speed radial geodesics from p;
the integral curves of ∇r are those geodesics, so ∇∂r∂r=0;
the level sets {r=s} are the geodesic spheres, and ∂r is their unit normal.
The Hessian∇2r, viewed as the endomorphism S(X)=∇X∂r, has ∂r in its kernel (∇∂r∂r=0) and is symmetric. On vectors tangent to a geodesic sphere it is the sphere's shape operator with respect to the inward normal −∂r, in the convention of 9A.8 Submanifolds and Minimal Surfaces up to that sign. Its trace is the mean curvature of the sphere, and also the Laplacian: Δr=trS. In the model spaces of curvature k (9A.1 Riemannian Metrics and Model Spaces),
so Δr is (n−1)cotr on the unit sphere, rn−1 in Euclidean space and (n−1)cothr in hyperbolic space (Figure 1.1). The Euclidean value is the familiar radial term of the Laplacian, f′′+rn−1f′, of 9A.6 The Laplacian and the Bochner Formula.
Since [∂r,X]=∇∂rX−∇X∂r=∇∂rX−S(X), the two terms with ∇∂rX cancel, leaving (∇∂rS)(X)=R(∂r,X)∂r−S2(X)=−R(X,∂r)∂r−S2(X). For the trace: trR∂r=Ric(∂r,∂r), and trS2=∣S∣2. Since S is symmetric with ∂r in its kernel, it acts on an (n−1)-dimensional space, and the Cauchy–Schwarz inequality for traces (8A.7 Tensors and Index Notation) gives ∣S∣2≥n−1(trS)2.
On the unit sphere, S=cotr on the tangential directions, and indeed −csc2r+cot2r+1=0 (Exercise 1.4). The equation is the infinitesimal form of the Jacobi equation of 9A.7 Jacobi Fields and Curvature versus Topology: if J is a Jacobi field along a radial geodesic with J(0)=0, then ∇∂rJ=S(J), and differentiating once more gives back J′′+R(J,∂r)∂r=0.
Figure 1.1. The Laplacian of distance, Δr=(n−1)snksnk′, in dimension n=3 for curvature k=1, 0, −1: 2cotr, r2, 2cothr. All are solutions of the model Riccati equation m′=−n−1m2−(n−1)k with m∼rn−1 as r→0. On the sphere, m reaches −∞ at r=π: the geodesic spheres collapse to the antipode.
If Ric≥(n−1)kg, then at every point of M∖({p}∪Cut(p)),
Δr≤(n−1)snk(r)snk′(r).
In particular, Ric≥0 implies Δr≤rn−1 and Δr2≤2n.
Proof. Along a unit-speed radial geodesic, m(r)=Δr satisfies m′≤−n−1m2−(n−1)k by the Riccati inequality, and m(r)=rn−1+O(r) as r→0 (normal coordinates, 9A.3 Geodesics and the Exponential Map). The model function mk=(n−1)snksnk′ satisfies the same relation with equality and the same asymptotics. Set ψ=snk2(m−mk). Then, using both relations,
because snk2snk′=n−12mk. Since ψ→0 as r→0 (snk2=O(r2) and m−mk=O(r)), ψ≤0, that is m≤mk, as long as snk>0. For k>0 the geodesic meets the cut locus no later than r=kπ (Bonnet–Myers, 9A.7 Jacobi Fields and Curvature versus Topology), so this covers every point where r is smooth. The last claim: Δr2=2rΔr+2∣∇r∣2≤2(n−1)+2.
Sectional curvature bounds give the stronger, matrix version (Exercise 1.6).
Theorem 1.3Hessian comparison
If K≥k, then ∇2r≤snksnk′(g−dr⊗dr) where r is smooth; if K≤k, then ∇2r≥snksnk′(g−dr⊗dr) inside the injectivity radius (and, for k>0, for r<kπ).
Across the cut locus. At a cut point, r is not smooth, but it can only have a concave kink: near a point q that is reached by two minimising geodesics, r is the minimum of two smooth functions, the distances measured along nearby families of geodesics. A minimum of smooth functions bends down, never up. Eugenio Calabi (1958) made this precise: Δr≤(n−1)snksnk′ holds on all of M∖{p}in the barrier sense. At every q there is a smooth function ϕ≥r near q, with ϕ(q)=r(q), whose Laplacian at q is at most the bound plus any ε>0. (Take ϕ(x)=δ+d(γ(δ),x) for a point γ(δ) a little way along a minimising geodesic from p to q; q is not a cut point of γ(δ).) Upper barriers are what the maximum principle needs: at a maximum of u−ϕ, where ϕ touches from above, the usual argument goes through. The comparison is valid in the sense of distributions too, and the cut locus can only help.
Figure 1.2. Level sets of the distance from a point on the square flat torus R2/Z2 (drawn in the fundamental square centred at the point, computed as the minimum over lattice translates). The cut locus is the boundary of the square, where two or more minimising geodesics meet and the distance function has a concave ridge: it is a minimum of smooth functions there.
The Riccati equation, named after Jacopo Riccati's study of first-order quadratic ODEs in the 1720s, entered Riemannian geometry through the second variation and Jacobi fields. Comparison theorems for sectional curvature go back to Rauch (1951); the Laplacian comparison under Ricci bounds is implicit in Bishop's volume estimate (1963). Calabi introduced the barrier trick in 1958, in his work on a maximum principle on manifolds. Amal Kumar Raychaudhuri published his equation in 1955; Penrose's singularity theorem appeared in 1965.
RecallWhere we stand
The distance r from a point is smooth away from p and the cut locus, with ∣∇r∣=1; its Hessian S is the shape operator of the geodesic spheres, and Δr their mean curvature. Along radial geodesics S′+S2+R∂r=0, and the trace gives m′≤−n−1m2−Ric(∂r,∂r). Comparing with the model ODE: Ric≥(n−1)k implies Δr≤(n−1)snksnk′, so Δr≤rn−1 when Ric≥0; sectional bounds give Hessian comparison. Across the cut locus, r has only concave kinks and the comparison holds in the barrier sense. In spacetime the same inequality is Raychaudhuri's focusing. 9B.2 Volume Comparison integrates it into volume comparison.
Check that S=snksnk′ on tangential vectors solves S′+S2+k=0 for k=1,0,−1, and that mk=(n−1)snksnk′ solves mk′=−n−1mk2−(n−1)k.
Solution
snk′′=−ksnk, so (snksnk′)′=snk2snk′′snk−snk′2=−k−(snksnk′)2. Multiplying by n−1 gives the second identity.
Exercise 1.5Euclidean distance
In Rn with r=∣x∣, compute ∇r, ∇2r and Δr directly, and check ∇2r2=2g.
Solution
∂ir=rxi, ∂i∂jr=rδij−r3xixj=r1(δij−∂ir∂jr), so Δr=rn−1. And ∂i∂j(r2)=2δij.
Exercise 1.6Hessian comparison along a geodesic
Assume K≥k. Let X be a unit vector at γ(r0) orthogonal to γ′, let E be its parallel transport along γ, and set λ(r)=⟨SE,E⟩. Show λ′≤−λ2−k, using ⟨S2E,E⟩=∣SE∣2≥λ2. Compare with snksnk′ as in the proof of Theorem 1.2 to deduce λ≤snksnk′.
Solution
λ′=⟨(∇∂rS)E,E⟩=−∣SE∣2−Rm(E,∂r,∂r,E)≤−λ2−k, since ∣SE∣≥∣⟨SE,E⟩∣ and K(E,∂r)≥k. With μ=snksnk′, which satisfies μ′=−μ2−k, the function snk2(λ−μ) has derivative ≤−snk2(λ−μ)2≤0 and tends to 0 at r=0, so λ≤μ.
Exercise 1.7The cut locus of a flat torus
On R2/Z2, with p=0, show that r(x)=minv∈Z2∣x−v∣ for x in the square [−21,21]2, and that on the edge x1=21 (away from corners) it is the minimum of the two smooth functions ∣x∣ and ∣x−(1,0)∣. Explain why the Laplacian of r there is "−∞" in the distributional sense, consistent with the upper bound r1.
Solution
Geodesics from p are straight lines in the universal cover, so the distance to x is the shortest distance to a lift. On x1=21, the two closest lifts of p are 0 and (1,0), at equal distance. Across the edge, r switches from one to the other, with a corner pointing up: the gradient jumps from ∣x∣x (with positive first component) to ∣x−(1,0)∣x−(1,0) (negative first component). A jump of ∂1r from positive to negative gives a negative multiple of a delta measure on the edge in ∂12r, so Δr as a distribution is r1 plus a negative measure, below the bound.
Exercise 1.8Myers from the Riccati inequality
If Ric≥(n−1)k>0, use the comparison m≤(n−1)kcot(kr) to show that no radial geodesic can stay minimising beyond r=kπ, giving another proof of Bonnet–Myers (9A.7 Jacobi Fields and Curvature versus Topology).
Solution
While the geodesic minimises, r is smooth along it (just before a cut point) and m≤(n−1)kcot(kr), which tends to −∞ as r→kπ. But m is finite at every smooth point, so the geodesic must reach a cut point at or before kπ. Every point of M is therefore within distance kπ of p.
Exercise 1.9Rehearsal: a cut-off function
On a complete manifold with Ric≥0, let η:R→[0,1] be smooth, equal to 1 on (−∞,1] and 0 on [2,∞), with η′≤0. Show that ϕ(x)=η(Rr(x)) satisfies ∣∇ϕ∣≤RC and, where r is smooth, Δϕ≥−R2C for R≥1, with C depending only on η and n. Such cut-offs localise the maximum principle in noncompact Ricci flows (11A.4 Maximum Principles under Ricci Flow), and the sign of η′ is exactly what lets Laplacian comparison be used.
Solution
∇ϕ=Rη′∇r, so ∣∇ϕ∣≤Rsup∣η′∣. And Δϕ=R2η′′∣∇r∣2+Rη′Δr. Since η′≤0 and Δr≤rn−1, the second term is ≥Rη′⋅rn−1, and η′=0 only where R≤r≤2R, so it is ≥−R2(n−1)sup∣η′∣. Hence Δϕ≥−R2sup∣η′′∣+(n−1)sup∣η′∣. (Across the cut locus the same holds in the barrier sense, because η′≤0 turns Calabi's upper barrier for r into a lower barrier for ϕ.)