Book 9B

© 2026 NeckPinch · www.neckpinch.com · All rights reserved.

Course 9Book 9B: Comparison, Convergence and Heat on ManifoldsChapter 1

Laplacian Comparison

The Riccati equation for the distance function, and the focusing of light.

21 min read · Updated Oct 3, 2026

Read with Petersen's Riemannian Geometry, the chapter on Ricci curvature comparison (the distance function, the Riccati equation, mean curvature and Laplacian comparison), and Lee's Introduction to Riemannian Manifolds (2nd edition), chapter 11 (comparison theory). Cheeger and Ebin's Comparison Theorems in Riemannian Geometry, chapter 1, is the classical reference.

In this chapter · 6 sections
  1. 1.1Focusing of light
  2. 1.2The distance function
  3. 1.3The Riccati equation
  4. 1.4Comparison
  5. 1.5History
  6. 1.6Exercises

Book 9A turned curvature into local statements: at a point, along a geodesic, for small balls. Book 9B turns curvature bounds into global control. If the Ricci curvature is at least some value everywhere, how fast can geodesics spread, how large can balls be, how small can a manifold get before it collapses, and what can limits of such manifolds look like? These are the facts that the Ricci flow uses in every compactness argument, and the Ricci flow books quote them in a few lines. This book proves the core ones and states the rest in the exact form used later.

The first tool is the distance function r(x)=d(p,x)r(x) = d(p, x) from a point. Its Hessian measures how the geodesic spheres around pp bend, and it obeys a first-order matrix ODE along each geodesic, a Riccati equation, driven by curvature. Comparing that ODE with the one for a model space gives Laplacian comparison: if Ric⁡≥0\operatorname{Ric} \geq 0, then Δr≤n−1r\Delta r \leq \frac{n - 1}{r}, as in Euclidean space. The same equation, read in spacetime, is Raychaudhuri's focusing equation, the engine of the singularity theorems of general relativity.

By the end of this chapter you will be able to:

  • describe where the distance function is smooth, and compute its gradient and Hessian;
  • derive the Riccati equation for the Hessian of distance and its traced form;
  • prove Laplacian comparison under a lower Ricci bound, and state Hessian comparison under sectional bounds;
  • explain in what sense the comparison holds across the cut locus;
  • relate the traced Riccati inequality to the focusing of light in general relativity.

Focusing of light

In the world Model Raychaudhuri, Penrose and the focusing of light

Follow a narrow bundle of light rays leaving a source, and measure its cross-sectional area AA. In general relativity, the expansion θ=1AdAdλ\theta = \frac{1}{A}\frac{dA}{d\lambda} (with λ\lambda an affine parameter along the rays) obeys Raychaudhuri's equation. For a bundle that is not twisting, in a four-dimensional spacetime,

dθdλ=−12θ2−∣σ∣2−Ric⁡(k,k),\frac{d\theta}{d\lambda} = -\frac12\theta^2 - |\sigma|^2 - \operatorname{Ric}(k, k),

where σ\sigma is the shear and kk the tangent to the rays. The 12\frac12 is 1d\frac{1}{d} with d=2d = 2, the dimension of the bundle's cross-section; for timelike geodesics (freely falling particles) the cross-section is three-dimensional and the coefficient is 13\frac13. Whenever matter has nonnegative energy density, Einstein's equations make Ric⁡(k,k)≥0\operatorname{Ric}(k, k) \geq 0, so θ′≤−12θ2\theta' \leq -\frac12\theta^2, and a bundle that starts converging reaches θ=−∞\theta = -\infty, a focal point, within a bounded affine distance.

Roger Penrose (1965) combined this inequality with a global argument to prove that a collapsing star which forms a "trapped surface" must produce a singularity: some light ray cannot be extended. Hawking and Penrose extended it to cosmology (1970), and Penrose received the 2020 Nobel Prize in Physics for the result. In this chapter the same inequality, with n−1n - 1 for dd, appears as the traced Riccati inequality for the distance function, and it controls the Laplacian of distance on a Riemannian manifold.

The distance function

Fix p∈Mp \in M, with MM complete, and let r(x)=d(p,x)r(x) = d(p, x). Then rr is smooth on M∖({p}∪Cut⁡(p))M\setminus(\{p\}\cup\operatorname{Cut}(p)), where Cut⁡(p)\operatorname{Cut}(p) is the cut locus of 9A.3 Geodesics and the Exponential Map, a closed set of measure zero. On that set:

  • ∣∇r∣=1|\nabla r| = 1 (the Gauss lemma), and ∇r=∂r\nabla r = \partial_r is the velocity of the unit-speed radial geodesics from pp;
  • the integral curves of ∇r\nabla r are those geodesics, so ∇∂r∂r=0\nabla_{\partial_r}\partial_r = 0;
  • the level sets {r=s}\{r = s\} are the geodesic spheres, and ∂r\partial_r is their unit normal.

The Hessian ∇2r\nabla^2r, viewed as the endomorphism S(X)=∇X∂r\mathcal S(X) = \nabla_X\partial_r, has ∂r\partial_r in its kernel (∇∂r∂r=0\nabla_{\partial_r}\partial_r = 0) and is symmetric. On vectors tangent to a geodesic sphere it is the sphere's shape operator with respect to the inward normal −∂r-\partial_r, in the convention of 9A.8 Submanifolds and Minimal Surfaces up to that sign. Its trace is the mean curvature of the sphere, and also the Laplacian: Δr=tr⁡S\Delta r = \operatorname{tr}\mathcal S. In the model spaces of curvature kk (9A.1 Riemannian Metrics and Model Spaces),

S=sn⁡k′(r)sn⁡k(r)(g−dr⊗dr),Δr=(n−1)sn⁡k′(r)sn⁡k(r),\mathcal S = \frac{\operatorname{sn}_k'(r)}{\operatorname{sn}_k(r)}\big(g - dr\otimes dr\big), \qquad \Delta r = (n - 1)\frac{\operatorname{sn}_k'(r)}{\operatorname{sn}_k(r)},

so Δr\Delta r is (n−1)cot⁡r(n - 1)\cot r on the unit sphere, n−1r\frac{n - 1}{r} in Euclidean space and (n−1)coth⁡r(n - 1)\coth r in hyperbolic space (Figure 1.1). The Euclidean value is the familiar radial term of the Laplacian, f′′+n−1rf′f'' + \frac{n - 1}{r}f', of 9A.6 The Laplacian and the Bochner Formula.

The Riccati equation

Proposition 1.1 The Riccati equation for distance

Along each radial geodesic, away from pp and Cut⁡(p)\operatorname{Cut}(p),

∇∂rS+S2+R∂r=0,R∂r(X)=R(X,∂r)∂r.\nabla_{\partial_r}\mathcal S + \mathcal S^2 + R_{\partial_r} = 0, \qquad R_{\partial_r}(X) = R(X, \partial_r)\partial_r.

Taking the trace, m=Δrm = \Delta r satisfies

∂rm+∣S∣2+Ric⁡(∂r,∂r)=0,hence∂rm≤−m2n−1−Ric⁡(∂r,∂r).\partial_rm + |\mathcal S|^2 + \operatorname{Ric}(\partial_r, \partial_r) = 0, \qquad\text{hence}\qquad \partial_rm \leq -\frac{m^2}{n - 1} - \operatorname{Ric}(\partial_r, \partial_r).

Proof. For a vector field XX, (∇∂rS)(X)=∇∂r∇X∂r−∇∇∂rX∂r(\nabla_{\partial_r}\mathcal S)(X) = \nabla_{\partial_r}\nabla_X\partial_r - \nabla_{\nabla_{\partial_r}X}\partial_r. By the definition of curvature and ∇∂r∂r=0\nabla_{\partial_r}\partial_r = 0,

∇∂r∇X∂r=R(∂r,X)∂r+∇X∇∂r∂r+∇[∂r,X]∂r=R(∂r,X)∂r+S([∂r,X]).\nabla_{\partial_r}\nabla_X\partial_r = R(\partial_r, X)\partial_r + \nabla_X\nabla_{\partial_r}\partial_r + \nabla_{[\partial_r, X]}\partial_r = R(\partial_r, X)\partial_r + \mathcal S([\partial_r, X]).

Since [∂r,X]=∇∂rX−∇X∂r=∇∂rX−S(X)[\partial_r, X] = \nabla_{\partial_r}X - \nabla_X\partial_r = \nabla_{\partial_r}X - \mathcal S(X), the two terms with ∇∂rX\nabla_{\partial_r}X cancel, leaving (∇∂rS)(X)=R(∂r,X)∂r−S2(X)=−R(X,∂r)∂r−S2(X)(\nabla_{\partial_r}\mathcal S)(X) = R(\partial_r, X)\partial_r - \mathcal S^2(X) = -R(X, \partial_r)\partial_r - \mathcal S^2(X). For the trace: tr⁡R∂r=Ric⁡(∂r,∂r)\operatorname{tr}R_{\partial_r} = \operatorname{Ric}(\partial_r, \partial_r), and tr⁡S2=∣S∣2\operatorname{tr}\mathcal S^2 = |\mathcal S|^2. Since S\mathcal S is symmetric with ∂r\partial_r in its kernel, it acts on an (n−1)(n - 1)-dimensional space, and the Cauchy–Schwarz inequality for traces (8A.7 Tensors and Index Notation) gives ∣S∣2≥(tr⁡S)2n−1|\mathcal S|^2 \geq \frac{(\operatorname{tr}\mathcal S)^2}{n - 1}.

On the unit sphere, S=cot⁡r\mathcal S = \cot r on the tangential directions, and indeed −csc⁡2r+cot⁡2r+1=0-\csc^2r + \cot^2r + 1 = 0 (Exercise 1.4). The equation is the infinitesimal form of the Jacobi equation of 9A.7 Jacobi Fields and Curvature versus Topology: if JJ is a Jacobi field along a radial geodesic with J(0)=0J(0) = 0, then ∇∂rJ=S(J)\nabla_{\partial_r}J = \mathcal S(J), and differentiating once more gives back J′′+R(J,∂r)∂r=0J'' + R(J, \partial_r)\partial_r = 0.

Figure 1.1. The Laplacian of distance, Δr=(n−1)sn⁡k′sn⁡k\Delta r = (n - 1)\frac{\operatorname{sn}_k'}{\operatorname{sn}_k}, in dimension n=3n = 3 for curvature k=1k = 1, 00, −1-1: 2cot⁡r2\cot r, 2r\frac2r, 2coth⁡r2\coth r. All are solutions of the model Riccati equation m′=−m2n−1−(n−1)km' = -\frac{m^2}{n - 1} - (n - 1)k with m∼n−1rm \sim \frac{n - 1}{r} as r→0r \to 0. On the sphere, mm reaches −∞-\infty at r=πr = \pi: the geodesic spheres collapse to the antipode.

Comparison

Theorem 1.2 Laplacian comparison

If Ric⁡≥(n−1)k g\operatorname{Ric} \geq (n - 1)k\,g, then at every point of M∖({p}∪Cut⁡(p))M\setminus(\{p\}\cup\operatorname{Cut}(p)),

Δr≤(n−1)sn⁡k′(r)sn⁡k(r).\Delta r \leq (n - 1)\frac{\operatorname{sn}_k'(r)}{\operatorname{sn}_k(r)}.

In particular, Ric⁡≥0\operatorname{Ric} \geq 0 implies Δr≤n−1r\Delta r \leq \frac{n - 1}{r} and Δr2≤2n\Delta r^2 \leq 2n.

Proof. Along a unit-speed radial geodesic, m(r)=Δrm(r) = \Delta r satisfies m′≤−m2n−1−(n−1)km' \leq -\frac{m^2}{n - 1} - (n - 1)k by the Riccati inequality, and m(r)=n−1r+O(r)m(r) = \frac{n - 1}{r} + O(r) as r→0r \to 0 (normal coordinates, 9A.3 Geodesics and the Exponential Map). The model function mk=(n−1)sn⁡k′sn⁡km_k = (n - 1)\frac{\operatorname{sn}_k'}{\operatorname{sn}_k} satisfies the same relation with equality and the same asymptotics. Set ψ=sn⁡k2(m−mk)\psi = \operatorname{sn}_k^2(m - m_k). Then, using both relations,

ψ′=2sn⁡ksn⁡k′(m−mk)+sn⁡k2(m′−mk′)≤sn⁡k2(m−mk)(2sn⁡k′sn⁡k−m+mkn−1)=−sn⁡k2(m−mk)2n−1≤0,\psi' = 2\operatorname{sn}_k\operatorname{sn}_k'(m - m_k) + \operatorname{sn}_k^2(m' - m_k') \leq \operatorname{sn}_k^2(m - m_k)\Big(\frac{2\operatorname{sn}_k'}{\operatorname{sn}_k} - \frac{m + m_k}{n - 1}\Big) = -\frac{\operatorname{sn}_k^2(m - m_k)^2}{n - 1} \leq 0,

because 2sn⁡k′sn⁡k=2mkn−1\frac{2\operatorname{sn}_k'}{\operatorname{sn}_k} = \frac{2m_k}{n - 1}. Since ψ→0\psi \to 0 as r→0r \to 0 (sn⁡k2=O(r2)\operatorname{sn}_k^2 = O(r^2) and m−mk=O(r)m - m_k = O(r)), ψ≤0\psi \leq 0, that is m≤mkm \leq m_k, as long as sn⁡k>0\operatorname{sn}_k > 0. For k>0k > 0 the geodesic meets the cut locus no later than r=πkr = \frac{\pi}{\sqrt k} (Bonnet–Myers, 9A.7 Jacobi Fields and Curvature versus Topology), so this covers every point where rr is smooth. The last claim: Δr2=2rΔr+2∣∇r∣2≤2(n−1)+2\Delta r^2 = 2r\Delta r + 2|\nabla r|^2 \leq 2(n - 1) + 2.

Sectional curvature bounds give the stronger, matrix version (Exercise 1.6).

Theorem 1.3 Hessian comparison

If K≥kK \geq k, then ∇2r≤sn⁡k′sn⁡k(g−dr⊗dr)\nabla^2r \leq \frac{\operatorname{sn}_k'}{\operatorname{sn}_k}(g - dr\otimes dr) where rr is smooth; if K≤kK \leq k, then ∇2r≥sn⁡k′sn⁡k(g−dr⊗dr)\nabla^2r \geq \frac{\operatorname{sn}_k'}{\operatorname{sn}_k}(g - dr\otimes dr) inside the injectivity radius (and, for k>0k > 0, for r<πkr < \frac{\pi}{\sqrt k}).

Across the cut locus. At a cut point, rr is not smooth, but it can only have a concave kink: near a point qq that is reached by two minimising geodesics, rr is the minimum of two smooth functions, the distances measured along nearby families of geodesics. A minimum of smooth functions bends down, never up. Eugenio Calabi (1958) made this precise: Δr≤(n−1)sn⁡k′sn⁡k\Delta r \leq (n - 1)\frac{\operatorname{sn}_k'}{\operatorname{sn}_k} holds on all of M∖{p}M\setminus\{p\} in the barrier sense. At every qq there is a smooth function ϕ≥r\phi \geq r near qq, with ϕ(q)=r(q)\phi(q) = r(q), whose Laplacian at qq is at most the bound plus any ε>0\varepsilon > 0. (Take ϕ(x)=δ+d(γ(δ),x)\phi(x) = \delta + d(\gamma(\delta), x) for a point γ(δ)\gamma(\delta) a little way along a minimising geodesic from pp to qq; qq is not a cut point of γ(δ)\gamma(\delta).) Upper barriers are what the maximum principle needs: at a maximum of u−ϕu - \phi, where ϕ\phi touches from above, the usual argument goes through. The comparison is valid in the sense of distributions too, and the cut locus can only help.

Figure 1.2. Level sets of the distance from a point on the square flat torus R2/Z2\mathbb{R}^2/\mathbb{Z}^2 (drawn in the fundamental square centred at the point, computed as the minimum over lattice translates). The cut locus is the boundary of the square, where two or more minimising geodesics meet and the distance function has a concave ridge: it is a minimum of smooth functions there.
Where this goes Where Laplacian comparison is used

Bishop–Gromov volume comparison (9B.2 Volume Comparison) integrates the inequality Δr≤mk\Delta r \leq m_k over spheres. The splitting theorem (9B.5 Splitting and Soul Theorems) applies it to Busemann functions. Under the Ricci flow, Perelman's estimate for how fast distances can shrink (Lemma 8.3 of his first paper) is a time-dependent Laplacian comparison, used throughout 12A.4 κ-Noncollapsing and 12A.6 Pseudolocality; his reduced distance satisfies a space-time version of it (12A.5 Reduced Distance and Reduced Volume).

History

The Riccati equation, named after Jacopo Riccati's study of first-order quadratic ODEs in the 1720s, entered Riemannian geometry through the second variation and Jacobi fields. Comparison theorems for sectional curvature go back to Rauch (1951); the Laplacian comparison under Ricci bounds is implicit in Bishop's volume estimate (1963). Calabi introduced the barrier trick in 1958, in his work on a maximum principle on manifolds. Amal Kumar Raychaudhuri published his equation in 1955; Penrose's singularity theorem appeared in 1965.

Recall Where we stand

The distance rr from a point is smooth away from pp and the cut locus, with ∣∇r∣=1|\nabla r| = 1; its Hessian S\mathcal S is the shape operator of the geodesic spheres, and Δr\Delta r their mean curvature. Along radial geodesics S′+S2+R∂r=0\mathcal S' + \mathcal S^2 + R_{\partial_r} = 0, and the trace gives m′≤−m2n−1−Ric⁡(∂r,∂r)m' \leq -\frac{m^2}{n - 1} - \operatorname{Ric}(\partial_r, \partial_r). Comparing with the model ODE: Ric⁡≥(n−1)k\operatorname{Ric} \geq (n - 1)k implies Δr≤(n−1)sn⁡k′sn⁡k\Delta r \leq (n - 1)\frac{\operatorname{sn}_k'}{\operatorname{sn}_k}, so Δr≤n−1r\Delta r \leq \frac{n - 1}{r} when Ric⁡≥0\operatorname{Ric} \geq 0; sectional bounds give Hessian comparison. Across the cut locus, rr has only concave kinks and the comparison holds in the barrier sense. In spacetime the same inequality is Raychaudhuri's focusing. 9B.2 Volume Comparison integrates it into volume comparison.

Exercises

Exercise 1.4 The model spaces

Check that S=sn⁡k′sn⁡k\mathcal S = \frac{\operatorname{sn}_k'}{\operatorname{sn}_k} on tangential vectors solves S′+S2+k=0\mathcal S' + \mathcal S^2 + k = 0 for k=1,0,−1k = 1, 0, -1, and that mk=(n−1)sn⁡k′sn⁡km_k = (n - 1)\frac{\operatorname{sn}_k'}{\operatorname{sn}_k} solves mk′=−mk2n−1−(n−1)km_k' = -\frac{m_k^2}{n - 1} - (n - 1)k.

Solution

sn⁡k′′=−ksn⁡k\operatorname{sn}_k'' = -k\operatorname{sn}_k, so (sn⁡k′sn⁡k)′=sn⁡k′′sn⁡k−sn⁡k′2sn⁡k2=−k−(sn⁡k′sn⁡k)2\big(\frac{\operatorname{sn}_k'}{\operatorname{sn}_k}\big)' = \frac{\operatorname{sn}_k''\operatorname{sn}_k - \operatorname{sn}_k'^2}{\operatorname{sn}_k^2} = -k - \big(\frac{\operatorname{sn}_k'}{\operatorname{sn}_k}\big)^2. Multiplying by n−1n - 1 gives the second identity.

Exercise 1.5 Euclidean distance

In Rn\mathbb{R}^n with r=∣x∣r = |x|, compute ∇r\nabla r, ∇2r\nabla^2r and Δr\Delta r directly, and check ∇2r2=2g\nabla^2r^2 = 2g.

Solution

∂ir=xir\partial_ir = \frac{x_i}{r}, ∂i∂jr=δijr−xixjr3=1r(δij−∂ir ∂jr)\partial_i\partial_jr = \frac{\delta_{ij}}{r} - \frac{x_ix_j}{r^3} = \frac1r(\delta_{ij} - \partial_ir\,\partial_jr), so Δr=n−1r\Delta r = \frac{n - 1}{r}. And ∂i∂j(r2)=2δij\partial_i\partial_j(r^2) = 2\delta_{ij}.

Exercise 1.6 Hessian comparison along a geodesic

Assume K≥kK \geq k. Let XX be a unit vector at γ(r0)\gamma(r_0) orthogonal to γ′\gamma', let EE be its parallel transport along γ\gamma, and set λ(r)=⟨SE,E⟩\lambda(r) = \langle\mathcal SE, E\rangle. Show λ′≤−λ2−k\lambda' \leq -\lambda^2 - k, using ⟨S2E,E⟩=∣SE∣2≥λ2\langle\mathcal S^2E, E\rangle = |\mathcal SE|^2 \geq \lambda^2. Compare with sn⁡k′sn⁡k\frac{\operatorname{sn}_k'}{\operatorname{sn}_k} as in the proof of Theorem 1.2 to deduce λ≤sn⁡k′sn⁡k\lambda \leq \frac{\operatorname{sn}_k'}{\operatorname{sn}_k}.

Solution

λ′=⟨(∇∂rS)E,E⟩=−∣SE∣2−Rm⁡(E,∂r,∂r,E)≤−λ2−k\lambda' = \langle(\nabla_{\partial_r}\mathcal S)E, E\rangle = -|\mathcal SE|^2 - \operatorname{Rm}(E, \partial_r, \partial_r, E) \leq -\lambda^2 - k, since ∣SE∣≥∣⟨SE,E⟩∣|\mathcal SE| \geq |\langle\mathcal SE, E\rangle| and K(E,∂r)≥kK(E, \partial_r) \geq k. With μ=sn⁡k′sn⁡k\mu = \frac{\operatorname{sn}_k'}{\operatorname{sn}_k}, which satisfies μ′=−μ2−k\mu' = -\mu^2 - k, the function sn⁡k2(λ−μ)\operatorname{sn}_k^2(\lambda - \mu) has derivative ≤−sn⁡k2(λ−μ)2≤0\leq -\operatorname{sn}_k^2(\lambda - \mu)^2 \leq 0 and tends to 00 at r=0r = 0, so λ≤μ\lambda \leq \mu.

Exercise 1.7 The cut locus of a flat torus

On R2/Z2\mathbb{R}^2/\mathbb{Z}^2, with p=0p = 0, show that r(x)=min⁡v∈Z2∣x−v∣r(x) = \min_{v \in \mathbb{Z}^2}|x - v| for xx in the square [−12,12]2[-\frac12, \frac12]^2, and that on the edge x1=12x_1 = \frac12 (away from corners) it is the minimum of the two smooth functions ∣x∣|x| and ∣x−(1,0)∣|x - (1, 0)|. Explain why the Laplacian of rr there is "−∞-\infty" in the distributional sense, consistent with the upper bound 1r\frac1r.

Solution

Geodesics from pp are straight lines in the universal cover, so the distance to xx is the shortest distance to a lift. On x1=12x_1 = \frac12, the two closest lifts of pp are 00 and (1,0)(1, 0), at equal distance. Across the edge, rr switches from one to the other, with a corner pointing up: the gradient jumps from x∣x∣\frac{x}{|x|} (with positive first component) to x−(1,0)∣x−(1,0)∣\frac{x - (1, 0)}{|x - (1, 0)|} (negative first component). A jump of ∂1r\partial_1r from positive to negative gives a negative multiple of a delta measure on the edge in ∂12r\partial_1^2r, so Δr\Delta r as a distribution is 1r\frac1r plus a negative measure, below the bound.

Exercise 1.8 Myers from the Riccati inequality

If Ric⁡≥(n−1)k>0\operatorname{Ric} \geq (n - 1)k > 0, use the comparison m≤(n−1)kcot⁡(kr)m \leq (n - 1)\sqrt k\cot(\sqrt kr) to show that no radial geodesic can stay minimising beyond r=πkr = \frac{\pi}{\sqrt k}, giving another proof of Bonnet–Myers (9A.7 Jacobi Fields and Curvature versus Topology).

Solution

While the geodesic minimises, rr is smooth along it (just before a cut point) and m≤(n−1)kcot⁡(kr)m \leq (n - 1)\sqrt k\cot(\sqrt kr), which tends to −∞-\infty as r→πkr \to \frac{\pi}{\sqrt k}. But mm is finite at every smooth point, so the geodesic must reach a cut point at or before πk\frac{\pi}{\sqrt k}. Every point of MM is therefore within distance πk\frac{\pi}{\sqrt k} of pp.

Exercise 1.9 Rehearsal: a cut-off function

On a complete manifold with Ric⁡≥0\operatorname{Ric} \geq 0, let η:R→[0,1]\eta : \mathbb{R} \to [0, 1] be smooth, equal to 11 on (−∞,1](-\infty, 1] and 00 on [2,∞)[2, \infty), with η′≤0\eta' \leq 0. Show that ϕ(x)=η(r(x)R)\phi(x) = \eta\big(\frac{r(x)}{R}\big) satisfies ∣∇ϕ∣≤CR|\nabla\phi| \leq \frac{C}{R} and, where rr is smooth, Δϕ≥−CR2\Delta\phi \geq -\frac{C}{R^2} for R≥1R \geq 1, with CC depending only on η\eta and nn. Such cut-offs localise the maximum principle in noncompact Ricci flows (11A.4 Maximum Principles under Ricci Flow), and the sign of η′\eta' is exactly what lets Laplacian comparison be used.

Solution

∇ϕ=η′R∇r\nabla\phi = \frac{\eta'}{R}\nabla r, so ∣∇ϕ∣≤sup⁡∣η′∣R|\nabla\phi| \leq \frac{\sup|\eta'|}{R}. And Δϕ=η′′R2∣∇r∣2+η′RΔr\Delta\phi = \frac{\eta''}{R^2}|\nabla r|^2 + \frac{\eta'}{R}\Delta r. Since η′≤0\eta' \leq 0 and Δr≤n−1r\Delta r \leq \frac{n - 1}{r}, the second term is ≥η′R⋅n−1r\geq \frac{\eta'}{R}\cdot\frac{n - 1}{r}, and η′≠0\eta' \neq 0 only where R≤r≤2RR \leq r \leq 2R, so it is ≥−(n−1)sup⁡∣η′∣R2\geq -\frac{(n - 1)\sup|\eta'|}{R^2}. Hence Δϕ≥−sup⁡∣η′′∣+(n−1)sup⁡∣η′∣R2\Delta\phi \geq -\frac{\sup|\eta''| + (n - 1)\sup|\eta'|}{R^2}. (Across the cut locus the same holds in the barrier sense, because η′≤0\eta' \leq 0 turns Calabi's upper barrier for rr into a lower barrier for ϕ\phi.)

© 2026 NeckPinch (www.neckpinch.com). All content in the guidebook (text, mathematics, figures and exercises) is protected by copyright. All rights reserved. No part may be copied, republished or redistributed without written permission.