Book 7A

© 2026 NeckPinch · www.neckpinch.com · All rights reserved.

Course 7Book 7A: Topology and the Fundamental GroupChapter 6

Covering Spaces

Lifting, universal covers, lens spaces and the Poincaré homology sphere.

22 min read · Updated Oct 3, 2026

Read with Lee, Introduction to Topological Manifolds, chapters 11 (covering maps) and 12 (group actions and covering maps), or Hatcher, Algebraic Topology, section 1.3. For the three-dimensional examples (lens spaces, the Poincaré homology sphere), Hatcher's examples in 1.3 and 2.2 are a good supplement.

In this chapter · 7 sections
  1. 6.1Unwrapping phase
  2. 6.2Covering maps
  3. 6.3Universal covers and deck transformations
  4. 6.4The 3-sphere and the rotation group
  5. 6.5Spherical space forms and the Poincaré homology sphere
  6. 6.6History
  7. 6.7Exercises

The proof that π1(S1)=Z\pi_1(S^1) = \mathbb{Z} unwrapped the circle onto the line (7A.4 The Fundamental Group). The line is a covering space of the circle: locally it looks exactly like the circle, but loops that go around the circle unroll into paths that don't close up. This chapter develops covering spaces in general. They turn questions about the fundamental group into questions about symmetry: a simply connected space with a group Γ\Gamma acting on it freely and discontinuously covers its quotient, and the quotient has fundamental group Γ\Gamma.

This is how the most important examples of three-manifolds arise. The 3-sphere is the group of unit quaternions, and it double covers the group of rotations SO(3)SO(3), so π1(SO(3))=Z/2\pi_1(SO(3)) = \mathbb{Z}/2: a fact you can demonstrate with a belt. Quotients of the 3-sphere by finite groups of rotations are the spherical space forms, including the lens spaces and the Poincaré homology sphere, whose fundamental group has 120 elements but no abelian quotient. These are exactly the manifolds that the Ricci flow leaves behind when it shrinks a three-manifold with finite fundamental group to a round point (12C.1 Reading Off the Topology).

By the end of this chapter you will be able to:

  • define covering maps and use the path lifting, homotopy lifting and lifting criteria;
  • describe the classification of coverings by subgroups of π1\pi_1, the universal cover and deck transformations;
  • prove that a free, properly discontinuous action of Γ\Gamma on a simply connected manifold has quotient with fundamental group Γ\Gamma;
  • compute π1\pi_1 of RPn\mathbb{R}P^n, tori and lens spaces, and construct the double cover SU(2)=S3→SO(3)SU(2) = S^3 \to SO(3);
  • describe the spherical space forms and the Poincaré homology sphere.

Unwrapping phase

In the world In use Phase unwrapping in radar interferometry

Satellites with synthetic aperture radar can measure how the ground moves, after an earthquake or as a volcano inflates or a city subsides, with an accuracy of millimetres. The method, interferometric SAR (InSAR), compares the phase of radar echoes from two passes of the satellite over the same place. A change in the distance from satellite to ground changes the phase, but a phase is only known modulo 2π2\pi: the measurement is a map from the ground into the circle R/2πZ\mathbb{R}/2\pi\mathbb{Z}, displayed as the familiar coloured fringes of an interferogram. To turn it into displacement one must lift it to a real-valued phase, choosing at each pixel the right multiple of 2π2\pi so that the result is continuous: this is phase unwrapping.

Along a single path, lifting is exactly the path lifting of 7A.4 The Fundamental Group, and it is unique once the starting value is fixed. In two dimensions the trouble is that noise can create points around which the measured phase winds by a non-zero multiple of 2π2\pi (residues), and then the lift depends on which way around such a point one integrates, just as a loop around the origin has no continuous logarithm (5A.2 Cauchy’s Theorem and Its Consequences). Richard Goldstein, Howard Zebker and Charles Werner's method ("Satellite radar interferometry: Two-dimensional phase unwrapping", Radio Science, 1988) locates the residues, pairs those of opposite sign, and connects them by "branch cuts" that the integration may not cross, so that on the cut-open region the lift is well defined. Their algorithm and its successors are standard in InSAR processing (Figure 6.1).

Figure 6.1. Top: a phase signal measured modulo 2π2\pi (computed from a smooth "true" phase plus small noise, then wrapped into (−π,π](-\pi, \pi]). Bottom: its unwrapping, the lift to R\mathbb{R} obtained by adding ±2π\pm2\pi whenever consecutive samples jump by more than π\pi. In one dimension this always works when the true phase changes by less than π\pi between samples; in two dimensions, residues make the lift path-dependent.

Covering maps

Definition 6.1 Covering map

A continuous surjection p:X~→Xp : \tilde X \to X is a covering map if every point of XX has an open neighbourhood UU that is evenly covered: p−1(U)p^{-1}(U) is a disjoint union of open sets (sheets), each mapped homeomorphically onto UU by pp. Then X~\tilde X is a covering space of XX.

Examples:

  • p:R→S1p : \mathbb{R} \to S^1, p(s)=e2πisp(s) = e^{2\pi is}, with infinitely many sheets (7A.4 The Fundamental Group).
  • pn:S1→S1p_n : S^1 \to S^1, z↦znz \mapsto z^n, with nn sheets (Figure 6.2).
  • Rn→Tn=Rn/Zn\mathbb{R}^n \to T^n = \mathbb{R}^n/\mathbb{Z}^n.
  • Sn→RPnS^n \to \mathbb{R}P^n, identifying antipodal points, with 22 sheets (Figure 6.2).
  • S3→L(p,q)S^3 \to L(p, q), with pp sheets (7A.1 Topological Spaces and Quotients, last exercise).

The lifting lemma of 7A.4 The Fundamental Group holds for every covering map, with the same proof: paths and homotopies lift uniquely once a starting point is chosen. Three consequences follow (Exercise 6.4).

  1. p∗:π1(X~,x~0)→π1(X,x0)p_* : \pi_1(\tilde X, \tilde x_0) \to \pi_1(X, x_0) is injective: a loop downstairs whose lift is a loop and is null-homotopic downstairs lifts to a null-homotopy upstairs.
  2. A loop in XX lifts to a loop in X~\tilde X exactly when its class lies in the subgroup p∗π1(X~)p_*\pi_1(\tilde X); the number of sheets equals the index of this subgroup.
  3. (Lifting criterion) For a connected, locally path-connected YY, a map f:Y→Xf : Y \to X lifts to X~\tilde X if and only if f∗π1(Y)⊆p∗π1(X~)f_*\pi_1(Y) \subseteq p_*\pi_1(\tilde X). In particular, every map from a simply connected space lifts.
Figure 6.2. Left: the 3-sheeted covering z↦z3z \mapsto z^3 of the circle by itself; each point below has three preimages, and a loop going once around below lifts to a path going a third of the way around above. Right: the 2-sheeted covering S2→RP2S^2 \to \mathbb{R}P^2, identifying antipodal points; RP2\mathbb{R}P^2 can be drawn as a disc (the upper hemisphere) with antipodal points of its boundary identified.

Universal covers and deck transformations

A covering X~→X\tilde X \to X with X~\tilde X simply connected is a universal cover. It exists for every connected, locally path-connected and "semi-locally simply connected" space, which includes every connected manifold, and it is unique up to isomorphism. It covers every other connected covering of XX, and the connected coverings of XX are classified by subgroups of π1(X)\pi_1(X): each subgroup HH corresponds to the covering with p∗π1=Hp_*\pi_1 = H, and conjugate subgroups give isomorphic coverings (Hatcher, section 1.3).

A deck transformation of a covering is a homeomorphism ϕ:X~→X~\phi : \tilde X \to \tilde X with p∘ϕ=pp\circ\phi = p: it permutes the sheets over each point. For the universal cover, the deck transformations form a group isomorphic to π1(X)\pi_1(X), acting simply transitively on each fibre. For R→S1\mathbb{R} \to S^1 they are the translations s↦s+ns \mapsto s + n, and π1(S1)=Z\pi_1(S^1) = \mathbb{Z} again.

Turned around, this produces manifolds from group actions.

Definition 6.2 Covering space actions

An action of a group Γ\Gamma on a space MM by homeomorphisms is a covering space action if every point has a neighbourhood UU with gU∩U=∅gU\cap U = \varnothing for all g≠eg \neq e.

Such an action is free (no non-identity element has a fixed point). Conversely, a free action of a finite group on a Hausdorff space is a covering space action (Exercise 6.5); so is the action of Zn\mathbb{Z}^n on Rn\mathbb{R}^n by translations.

Theorem 6.3 Quotients by covering space actions

If Γ\Gamma acts on a connected, locally path-connected space MM by a covering space action, then p:M→M/Γp : M \to M/\Gamma is a covering map, its deck group is Γ\Gamma, and if MM is simply connected,

π1(M/Γ)≅Γ.\pi_1(M/\Gamma) \cong \Gamma.

If MM is a manifold, so is M/ΓM/\Gamma.

Proof. (Sketch.) For UU as in the definition, p−1(p(U))=⨆g∈ΓgUp^{-1}(p(U)) = \bigsqcup_{g\in\Gamma}gU is a disjoint union of open sets each mapped homeomorphically onto p(U)p(U), so p(U)p(U) is evenly covered. For the isomorphism, fix x~0\tilde x_0; a loop at p(x~0)p(\tilde x_0) lifts to a path from x~0\tilde x_0 to gx~0g\tilde x_0 for a unique gg, which depends only on the homotopy class of the loop (homotopy lifting), giving a homomorphism π1(M/Γ)→Γ\pi_1(M/\Gamma) \to \Gamma. It is onto because MM is path-connected (join x~0\tilde x_0 to gx~0g\tilde x_0 and project), and injective because if g=eg = e the lift is a loop in the simply connected MM, which contracts. Whether the quotient is Hausdorff is a separate matter: it holds for finite groups acting freely on Hausdorff spaces and for the examples below, and in general it follows from the stronger condition of a properly discontinuous action (Lee, chapter 12; Exercise 6.5 shows what can go wrong).

Examples.

  • π1(Tn)=π1(Rn/Zn)=Zn\pi_1(T^n) = \pi_1(\mathbb{R}^n/\mathbb{Z}^n) = \mathbb{Z}^n.
  • π1(RPn)=π1(Sn/{±1})=Z/2\pi_1(\mathbb{R}P^n) = \pi_1(S^n/\{\pm1\}) = \mathbb{Z}/2 for n≥2n \geq 2, since SnS^n is simply connected (7A.4 The Fundamental Group). The same answer as 7A.5 Computing π₁, by a different route.
  • π1(L(p,q))=Z/p\pi_1(L(p, q)) = \mathbb{Z}/p, from the free action of Z/p\mathbb{Z}/p on S3S^3 (7A.1 Topological Spaces and Quotients).
  • A simply connected manifold has no non-trivial connected coverings: a covering of it is a covering by a space whose p∗π1p_*\pi_1 has index equal to the number of sheets, and the index of a subgroup of the trivial group is 11.

The 3-sphere and the rotation group

Let H\mathbb{H} be the quaternions, q=a+bi+cj+dkq = a + bi + cj + dk with i2=j2=k2=ijk=−1i^2 = j^2 = k^2 = ijk = -1, and ∣q∣2=a2+b2+c2+d2|q|^2 = a^2 + b^2 + c^2 + d^2. The unit quaternions form the 3-sphere S3⊂H=R4S^3 \subset \mathbb{H} = \mathbb{R}^4, and since ∣qr∣=∣q∣∣r∣|qr| = |q||r| they form a group, isomorphic to SU(2)SU(2) (Exercise 6.6). Identify R3\mathbb{R}^3 with the pure quaternions bi+cj+dkbi + cj + dk. For a unit quaternion qq, the map

Rq(v)=qvqˉR_q(v) = qv\bar q

preserves pure quaternions and their lengths, and is a rotation of R3\mathbb{R}^3: writing q=cos⁡θ2+sin⁡θ2 uq = \cos\frac\theta2 + \sin\frac\theta2\,u with uu a unit pure quaternion, RqR_q is the rotation by angle θ\theta about the axis uu. Every rotation arises this way, and Rq=Rq′R_q = R_{q'} exactly when q′=±qq' = \pm q. So

S3=SU(2)→SO(3),q↦Rq,S^3 = SU(2) \to SO(3), \qquad q \mapsto R_q,

is a 2-sheeted covering and a group homomorphism with kernel {±1}\{\pm1\}. Hence SO(3)≅S3/{±1}=RP3SO(3) \cong S^3/\{\pm1\} = \mathbb{R}P^3, and

π1(SO(3))≅Z/2.\pi_1(SO(3)) \cong \mathbb{Z}/2.

A loop of rotations that turns once around an axis, θ\theta from 00 to 2π2\pi, lifts to the path q=cos⁡θ2+sin⁡θ2uq = \cos\frac\theta2 + \sin\frac\theta2u from 11 to −1-1, which is not a loop: the loop is not contractible. Going around twice lifts to a loop in the simply connected S3S^3, and is contractible.

In the world Model The belt trick

Hold the buckle end of a belt, fix the other end, and turn the buckle through one full turn (360°) about the belt's length. The belt now has a twist that can't be removed by moving the buckle around while keeping its orientation fixed. Turn it through a second full turn (720°) in the same direction, and the belt, surprisingly, can be untwisted: pass the buckle around the belt, keeping it pointing the same way, and the twist disappears. The same works with a plate held flat on the palm of the hand: rotating it twice in the horizontal plane, with the arm following, returns arm and plate to the start, while once leaves the arm twisted. (Paul Dirac used a version with strings to illustrate spin, and it is often called Dirac's string trick.)

The belt records a path in SO(3)SO(3): the orientation of each cross-section of the belt, from the fixed end to the buckle. One full turn is the non-trivial element of π1(SO(3))=Z/2\pi_1(SO(3)) = \mathbb{Z}/2, and two full turns are the trivial element. In quantum mechanics the state of a spin-12\frac12 particle, such as an electron or a neutron, transforms under rotations through SU(2)SU(2) rather than SO(3)SO(3), so a 360°360° rotation multiplies it by −1-1 and only 720°720° returns it to itself. Because an overall sign is not directly observable, this was tested by interference: in 1975 Helmut Rauch and colleagues, and independently Samuel Werner and colleagues, split a neutron beam, rotated the spins in one path by a magnetic field and recombined the beams, and observed the 4π4\pi periodicity in the interference pattern.

In the world In use Quaternions in attitude control and animation

Spacecraft attitude control systems, flight simulators and 3D game engines represent orientations by unit quaternions: four numbers instead of a 3×33\times3 matrix, with no singular configurations (unlike Euler angles, which suffer "gimbal lock"). The double cover shows up in practice: qq and −q-q represent the same orientation, so software that interpolates between two orientations, such as Ken Shoemake's spherical linear interpolation (SLERP, 1985), must first choose the sign of one of them so that the two quaternions are on the same side, ⟨q1,q2⟩≥0\langle q_1, q_2\rangle \geq 0; otherwise the interpolation takes the long way round, an extra full turn. That sign check is π1(SO(3))=Z/2\pi_1(SO(3)) = \mathbb{Z}/2 written as code.

Spherical space forms and the Poincaré homology sphere

A finite subgroup Γ\Gamma of SO(4)SO(4) that acts freely on S3S^3 gives a closed three-manifold S3/ΓS^3/\Gamma with fundamental group Γ\Gamma. Since Γ\Gamma acts by isometries of the round metric, S3/ΓS^3/\Gamma inherits a metric of constant curvature +1+1: it is a spherical space form. Examples:

  • lens spaces L(p,q)L(p, q), Γ=Z/p\Gamma = \mathbb{Z}/p acting by (z,w)↦(ζz,ζqw)(z, w) \mapsto (\zeta z, \zeta^qw) with gcd⁡(p,q)=1\gcd(p, q) = 1;
  • RP3=L(2,1)\mathbb{R}P^3 = L(2, 1);
  • quotients by finite subgroups Γ⊂SU(2)\Gamma \subset SU(2) acting by left multiplication on S3=SU(2)S^3 = SU(2), which is always free (a group element other than 11 fixes no point under left multiplication). The finite subgroups of SU(2)SU(2) are the preimages of the finite rotation groups of R3\mathbb{R}^3: cyclic, binary dihedral, and the binary tetrahedral, octahedral and icosahedral groups, of orders 2424, 4848 and 120120.

The Poincaré homology sphere is S3/I∗S^3/I^*, where I∗I^* is the binary icosahedral group: the 120120 unit quaternions that map to the 6060 rotational symmetries of a regular icosahedron. Poincaré found this manifold in 1904 (by a different construction) as a closed three-manifold with the same homology as S3S^3 but not homeomorphic to it. Its fundamental group I∗I^* has 120120 elements and is perfect: it equals its own commutator subgroup, so its abelianisation, which is H1H_1, is trivial (7A.8 Homology in Brief). It is the reason the Poincaré conjecture is stated in terms of π1\pi_1 and not homology (7A.9 The Poincaré Conjecture, Precisely).

Where this goes What the Ricci flow leaves behind

Hamilton's 1982 theorem says that a closed three-manifold with positive Ricci curvature evolves under the normalised Ricci flow to a metric of constant positive curvature (11A.6 Hamilton’s 1982 Theorem): so it is diffeomorphic to S3/ΓS^3/\Gamma, a spherical space form. Perelman's proof extends this: a closed three-manifold with finite fundamental group, run through the Ricci flow with surgery, becomes extinct in finite time, and its pieces are spherical space forms (12C.1 Reading Off the Topology, 12C.2 Finite Extinction). If π1=1\pi_1 = 1, the only spherical space form available is S3S^3 itself. That every free action of a finite group on S3S^3 is conjugate to a linear one is the elliptization part of geometrization, which Perelman's work also proves (10A.5 Thurston’s Eight Geometries).

History

Covering spaces appeared in Riemann's work on multivalued functions (Riemann surfaces as coverings of the sphere) and were formalised by Poincaré and Hermann Weyl (Die Idee der Riemannschen Fläche, 1913). Poincaré's homology sphere appeared in the fifth supplement to Analysis Situs (1904). Heinrich Tietze introduced lens spaces in 1908, and Kurt Reidemeister classified them up to combinatorial equivalence in 1935. Heinz Hopf studied spherical space forms in the mid-1920s, and the classification of finite groups acting freely and linearly on S3S^3 was completed by Herbert Seifert and William Threlfall in 1930–33. William Rowan Hamilton discovered the quaternions in 1843. The neutron 4π4\pi experiments were published in 1975, Goldstein, Zebker and Werner's phase unwrapping method in 1988, and Shoemake's SLERP in 1985.

Recall Where we stand

A covering map is locally a stack of homeomorphic sheets; paths and homotopies lift uniquely, p∗p_* is injective, the number of sheets is the index of p∗π1(X~)p_*\pi_1(\tilde X), and maps from simply connected spaces lift. Connected coverings correspond to subgroups of π1\pi_1, and the universal cover is simply connected with deck group π1\pi_1. A covering space action of Γ\Gamma on a simply connected MM gives π1(M/Γ)=Γ\pi_1(M/\Gamma) = \Gamma: so π1(Tn)=Zn\pi_1(T^n) = \mathbb{Z}^n, π1(RPn)=Z/2\pi_1(\mathbb{R}P^n) = \mathbb{Z}/2, π1(L(p,q))=Z/p\pi_1(L(p, q)) = \mathbb{Z}/p. Unit quaternions S3=SU(2)S^3 = SU(2) double cover SO(3)=RP3SO(3) = \mathbb{R}P^3, so π1(SO(3))=Z/2\pi_1(SO(3)) = \mathbb{Z}/2: the belt trick. Spherical space forms S3/ΓS^3/\Gamma include the Poincaré homology sphere S3/I∗S^3/I^*, with perfect fundamental group of order 120120. 7A.7 Smooth Topology turns to smooth maps and degree.

Exercises

Exercise 6.4 Consequences of lifting

Prove consequences 1 and 2 in the text from the path and homotopy lifting properties. For 2, show that the fibre p−1(x0)p^{-1}(x_0) is in bijection with the right cosets of p∗π1(X~,x~0)p_*\pi_1(\tilde X, \tilde x_0) in π1(X,x0)\pi_1(X, x_0) when X~\tilde X is path-connected.

Exercise 6.5 Free actions of finite groups

Let a finite group Γ\Gamma act freely on a Hausdorff space MM. For x∈Mx \in M, the points gxgx (g∈Γg \in \Gamma) are distinct; choose pairwise disjoint neighbourhoods VgV_g of them, and let U=⋂gg−1VgU = \bigcap_g g^{-1}V_g. (a) Show that hU∩U=∅hU\cap U = \varnothing for h≠eh \neq e, so the action is a covering space action. (b) Let Z\mathbb{Z} act on R2∖{0}\mathbb{R}^2\setminus\{0\} by (x,y)↦(2x,y2)(x, y) \mapsto (2x, \frac y2). Show that this is a covering space action, but that the quotient is not Hausdorff: every neighbourhood of the orbit of (1,0)(1, 0) meets every neighbourhood of the orbit of (0,1)(0, 1). (The point (1,2−n)(1, 2^{-n}) is close to (1,0)(1, 0), and applying the generator's inverse nn times sends it to (2−n,1)(2^{-n}, 1), close to (0,1)(0, 1).)

Exercise 6.6 Unit quaternions and SU(2)SU(2)

Show that q=a+bi+cj+dk↦(a+bic+di−c+dia−bi)q = a + bi + cj + dk \mapsto \begin{pmatrix}a + bi & c + di\\ -c + di & a - bi\end{pmatrix} is a group isomorphism from the unit quaternions onto SU(2)SU(2), the 2×22\times2 complex matrices (αβ−βˉαˉ)\begin{pmatrix}\alpha & \beta\\ -\bar\beta & \bar\alpha\end{pmatrix} with ∣α∣2+∣β∣2=1|\alpha|^2 + |\beta|^2 = 1. Deduce that SU(2)SU(2) is homeomorphic to S3S^3.

Exercise 6.7 Quaternions rotate

Let q=cos⁡θ2+sin⁡θ2 kq = \cos\frac\theta2 + \sin\frac\theta2\,k. Compute q i qˉq\,i\,\bar q and q j qˉq\,j\,\bar q and show that RqR_q rotates the (i,j)(i, j)-plane by the angle θ\theta and fixes kk. Check that q=−1q = -1 (when θ=2π\theta = 2\pi) gives the identity rotation.

Solution

With c=cos⁡θ2c = \cos\frac\theta2, s=sin⁡θ2s = \sin\frac\theta2: q i qˉ=(c+sk)i(c−sk)=(ci+sj)(c−sk)=c2i−csik+scj−s2jkq\,i\,\bar q = (c + sk)i(c - sk) = (ci + sj)(c - sk) = c^2i - csik + scj - s^2jk; using ik=−jik = -j and jk=ijk = i: =c2i+csj+scj−s2i=cos⁡θ i+sin⁡θ j= c^2i + csj + scj - s^2i = \cos\theta\,i + \sin\theta\,j. Similarly q j qˉ=−sin⁡θ i+cos⁡θ jq\,j\,\bar q = -\sin\theta\,i + \cos\theta\,j, and kk commutes with qq, so it is fixed.

Exercise 6.8 Simply connected manifolds have no covers

Show that a connected covering p:M~→Mp : \tilde M \to M of a simply connected, locally path-connected space is a homeomorphism. (Use the lifting criterion to lift id⁡M\operatorname{id}_M to a section s:M→M~s : M \to \tilde M, and show that ss is onto.)

Exercise 6.9 Rehearsal: round space forms under Ricci flow

Let Γ⊂SO(4)\Gamma \subset SO(4) act freely on S3S^3, and give S3/ΓS^3/\Gamma the metric inherited from the unit sphere. (a) Show that its volume is 2π2∣Γ∣\frac{2\pi^2}{|\Gamma|} (the unit 3-sphere has volume 2π22\pi^2). (b) Under the Ricci flow, the round unit S3S^3 evolves by g(t)=(1−4t)g0g(t) = (1 - 4t)g_0 (6A.1 What a PDE Is, with n=3n = 3). Explain why the quotient S3/ΓS^3/\Gamma evolves by the same formula, so it shrinks to a point at t=14t = \frac14, independently of Γ\Gamma. (c) Compute the volume of L(5,1)L(5, 1) and of the Poincaré homology sphere at t=0t = 0 and t=18t = \frac18. In Perelman's proof, the pieces that become extinct are exactly such round quotients, possibly after surgery (12C.1 Reading Off the Topology).

Solution

(a) The covering S3→S3/ΓS^3 \to S^3/\Gamma is a local isometry with ∣Γ∣|\Gamma| sheets. (b) The Ricci flow is local and invariant under isometries, so a solution on S3S^3 that is invariant under Γ\Gamma descends; the round shrinking solution is invariant under all of SO(4)SO(4). (c) Volume scales by (1−4t)3/2(1 - 4t)^{3/2}: L(5,1)L(5, 1) has 2π25≈3.95\frac{2\pi^2}{5} \approx 3.95, then 2π25(12)3/2≈1.40\frac{2\pi^2}{5}(\frac12)^{3/2} \approx 1.40; the Poincaré sphere 2π2120≈0.164\frac{2\pi^2}{120} \approx 0.164, then ≈0.058\approx 0.058.

© 2026 NeckPinch (www.neckpinch.com). All content in the guidebook (text, mathematics, figures and exercises) is protected by copyright. All rights reserved. No part may be copied, republished or redistributed without written permission.