Book 10A

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Course 10Book 10A: Three-Manifolds and GeometrizationChapter 6

Necks, Caps and Their Topology

What an ε-neck is, how necks overlap and chain into tubes, and which manifolds necks and caps can build.

40 min read · Updated Oct 23, 2026

Read with Morgan and Tian's Ricci Flow and the Poincaré Conjecture, chapter 2, §6 (ε-necks), Definition 9.72 ((C, ε)-caps) and chapter 19, the appendix on canonical neighbourhoods, which this chapter follows in outline. Hatcher's Notes on Basic 3-Manifold Topology, chapter 1, supplies the cut-and-paste facts about spheres.

In this chapter · 11 sections
  1. 6.1Closeness of metrics
  2. 6.2The model neck and ε\varepsilonε-necks
  3. 6.3The geometry of an ε\varepsilonε-neck
  4. 6.4Gluing products
  5. 6.5Overlapping necks and chains
  6. 6.6Manifolds covered by necks
  7. 6.7Caps
  8. 6.8Components covered by necks and caps
  9. 6.9The topological effect of surgery
  10. 6.10History
  11. 6.11Exercises
  12. ↗Free resources

Perelman's description of a Ricci flow at high curvature, the canonical neighbourhood theorem (12B.5 The Canonical Neighbourhood Theorem), says that every point where the scalar curvature is large has a neighbourhood that, after rescaling, looks like one of a few models: a long, nearly round cylinder (an ε\varepsilon-neck), a cylinder capped off by a ball or by a punctured projective space (an ε\varepsilon-cap), or a whole compact component of controlled positive curvature. Surgery cuts the manifold along the central spheres of necks, and the components it throws away are entirely covered by such neighbourhoods. Two things have to be known about these models, and both are topological once the geometry is set up:

  1. what the regions covered by necks and caps are: tubes S2×(0,1)S^2\times(0, 1), balls, punctured copies of RP3\mathbb{RP}^3, and a short list of closed manifolds;
  2. how necks fit together: two overlapping necks line up, and a chain of them is again a tube.

Morgan and Tian devote an appendix, their chapter 19, to these facts, and they use them in every chapter from 9 on. This chapter develops them. It begins with the precise definitions, shows what the geometry of a neck is like (curvature, distances, the spheres), proves the gluing lemma that makes chains of necks into tubes, and classifies the components covered by necks and caps. It ends with the topological effect of surgery, which combines everything with 10A.5 The Prime Decomposition.

By the end of this chapter you will be able to:

  • define closeness of metrics in the CkC^k topology, ε\varepsilon-necks, their scale, central spheres and ss-coordinate, and (C,ε)(C, \varepsilon)-caps;
  • compute the curvature of the model neck and estimate curvature and distances on an ε\varepsilon-neck;
  • prove that gluing two products S2×IS^2\times I along a sphere gives a product, and that a chain of overlapping necks is a tube S2×(0,1)S^2\times(0, 1);
  • identify the core of a cap as a ball or RP3\mathbb{RP}^3 minus a ball, and identify RP3\mathbb{RP}^3 minus a ball with the twisted line bundle over RP2\mathbb{RP}^2;
  • list the closed manifolds covered by necks and caps, S3S^3, RP3\mathbb{RP}^3, RP3#RP3\mathbb{RP}^3\#\mathbb{RP}^3, S2×S1S^2\times S^1 and the twisted S2S^2-bundle over S1S^1, and prove that the capped ones are on the list;
  • describe the topological effect of a surgery, and why the Poincaré conjecture follows from extinction.

Closeness of metrics

All definitions in this chapter compare a metric with a model through a diffeomorphism, as in Cheeger–Gromov convergence (9B.4 Convergence of Manifolds).

Definition 6.1 Closeness in the CkC^k topology

Let gg and g0g_0 be metrics on a manifold XX. Then gg is within ε\varepsilon of g0g_0 in the CkC^k topology if

sup⁡x∈X(∣g−g0∣g02+∑ℓ=1k∣∇g0ℓg∣g02)<ε2,\sup_{x \in X}\Big(|g - g_0|^2_{g_0} + \sum_{\ell=1}^k|\nabla_{g_0}^\ell g|^2_{g_0}\Big) < \varepsilon^2,

where ∇g0\nabla_{g_0} is the Levi-Civita connection of g0g_0 and the norms are the pointwise g0g_0-norms of the tensors. Two metrics on different manifolds are within ε\varepsilon if one of them, pulled back by a diffeomorphism, is within ε\varepsilon of the other.

Two remarks. Since ∇g0g0=0\nabla_{g_0}g_0 = 0, the derivatives ∇g0ℓg=∇g0ℓ(g−g0)\nabla_{g_0}^\ell g = \nabla_{g_0}^\ell(g - g_0) measure the derivatives of the difference. And Perelman always takes k=[1/ε]k = [1/\varepsilon], the integer part of 1ε\frac1\varepsilon: a single small number then says both "very close" and "close in very many derivatives". That is convenient, because the conclusions drawn from closeness (about curvature, distances, the shape of the spheres) need a few derivatives each, and with k=[1/ε]k = [1/\varepsilon] there are always enough once ε\varepsilon is small.

What closeness buys is continuity of everything built from the metric and finitely many derivatives. The curvature tensor is a polynomial in gijg_{ij}, gijg^{ij}, ∂gij\partial g_{ij} and ∂2gij\partial^2g_{ij} (9A.4 Curvature and What It Means). So if gg is within ε\varepsilon of g0g_0 in C2C^2, with ε\varepsilon small, then ∣Rm⁡(g)−Rm⁡(g0)∣g0≤Cε|\operatorname{Rm}(g) - \operatorname{Rm}(g_0)|_{g_0} \leq C\varepsilon, with CC depending on bounds for g0g_0's own curvature and the dimension; and in Ck+2C^{k+2}, the first kk derivatives of curvature are close too.

The model neck and ε\varepsilon-necks

Let h0h_0 be the round metric on S2S^2 with scalar curvature 11. A round sphere of radius ρ\rho has Gauss curvature 1ρ2\frac{1}{\rho^2} and scalar curvature 2ρ2\frac{2}{\rho^2}, so h0h_0 is the sphere of radius 2\sqrt2, with Gauss curvature 12\frac12, area 8π8\pi and intrinsic diameter 2π\sqrt2\pi. The model neck is S2×RS^2\times\mathbb{R} with the product metric h0+ds2h_0 + ds^2. Its curvature, by the product formulas of 9A.5 Computing Curvature:

  • the sectional curvature of the plane tangent to the sphere is 12\frac12; planes containing ∂s\partial_s have curvature 00;
  • the Ricci tensor is 12h0⊕0\frac12h_0\oplus0, with eigenvalues 12,12,0\frac12, \frac12, 0; the scalar curvature is 11;
  • in Hamilton's normalisation (11A.2 How Curvature Evolves) the curvature operator has eigenvalues 1,0,01, 0, 0.

It is the shrinking cylinder of 11A.1 The Equation and Its First Solutions at the moment when its scalar curvature is 11.

Definition 6.2 ε\varepsilon-neck

Let (M,g)(M, g) be a Riemannian 3-manifold, x∈Mx \in M, ε>0\varepsilon > 0. An ε\varepsilon-neck centred at xx is an open set N⊂MN \subset M with a diffeomorphism φ:S2×(−ε−1,ε−1)→N\varphi : S^2\times(-\varepsilon^{-1}, \varepsilon^{-1}) \to N such that x∈φ(S2×{0})x \in \varphi(S^2\times\{0\}) and the rescaled pullback R(x)φ∗gR(x)\varphi^*g is within ε\varepsilon of h0+ds2h_0 + ds^2 in the C[1/ε]C^{[1/\varepsilon]} topology.

The definition comes with a vocabulary, used constantly in Morgan–Tian.

  • The scale of NN is rN=R(x)−1/2r_N = R(x)^{-1/2}. Since the rescaled metric is close to the model, the spheres φ(S2×{s})\varphi(S^2\times\{s\}) have area close to 8πrN28\pi r_N^2 and intrinsic diameter close to 2πrN\sqrt2\pi r_N: the scale is the size of the neck's cross-section, up to the factor 2\sqrt2.
  • The ss-coordinate is sN=pr⁡2∘φ−1:N→(−ε−1,ε−1)s_N = \operatorname{pr}_2\circ\varphi^{-1} : N \to (-\varepsilon^{-1}, \varepsilon^{-1}). Its level sets are the 2-spheres of the neck, and SN=φ(S2×{0})S_N = \varphi(S^2\times\{0\}) is the central sphere. In the metric gg, the ss-coordinate measures length along the neck in units of rNr_N: the neck has length about 2ε−1rN2\varepsilon^{-1}r_N.
  • The ends, halves, middle third and so on are defined through sNs_N: the positive half is sN−1(0,ε−1)s_N^{-1}(0, \varepsilon^{-1}), the middle third is sN−1(−13ε,13ε)s_N^{-1}(-\frac{1}{3\varepsilon}, \frac{1}{3\varepsilon}). Reversing the direction (composing φ\varphi with (ω,s)↦(ω,−s)(\omega, s) \mapsto (\omega, -s)) gives the opposite neck structure.

The definition is scale-invariant: if NN is an ε\varepsilon-neck for gg, it is one for λg\lambda g, with the same φ\varphi, since Rλg(x)λg=Rg(x)gR_{\lambda g}(x)\lambda g = R_g(x)g. A neck is a statement about shape, not size, and the size is recorded separately by rNr_N. Small ε\varepsilon asks for a long neck, of length 2ε−12\varepsilon^{-1} times its scale, that is close to round in many derivatives.

The geometry of an ε\varepsilon-neck

Throughout, "for ε\varepsilon small enough" means: there is ε0>0\varepsilon_0 > 0, depending on the stated tolerances, such that the statement holds for all ε≤ε0\varepsilon \leq \varepsilon_0. By scale invariance we may rescale so that R(x)=1R(x) = 1.

Proposition 6.3 Curvature on a neck

For every α>0\alpha > 0 there is ε1(α)>0\varepsilon_1(\alpha) > 0 such that on any ε\varepsilon-neck with ε≤ε1\varepsilon \leq \varepsilon_1 and R(x)=1R(x) = 1: at every point the eigenvalues of the curvature operator (Hamilton's normalisation) are within α\alpha of {1,0,0}\{1, 0, 0\}, the scalar curvature satisfies 1−α<R<1+α1 - \alpha < R < 1 + \alpha, and there is a unique 2-plane of largest sectional curvature, which makes an angle less than α\alpha with the tangent plane of the sphere of the neck through that point.

Proof. On the model all three statements hold exactly, with the plane of largest curvature (curvature 12\frac12) tangent to the spheres, and the gap between the largest eigenvalue 11 and the others 00 is 11. The rescaled metric φ∗g\varphi^*g is within ε\varepsilon of the model in C[1/ε]C^{[1/\varepsilon]}, and [1/ε]≥2[1/\varepsilon] \geq 2 once ε≤12\varepsilon \leq \frac12, so the curvature operator of φ∗g\varphi^*g is within CεC\varepsilon of the model's at every point, with CC a universal constant (the model has bounded geometry). Eigenvalues of symmetric operators depend continuously on the operator (they move by at most the operator norm of the perturbation), so they are within CεC\varepsilon of {1,0,0}\{1, 0, 0\}, and RR, their sum, is within 3Cε3C\varepsilon of 11. The eigenvector of the largest eigenvalue, which is simple with gap at least 1−2Cε1 - 2C\varepsilon, moves by O(ε)O(\varepsilon) (perturbation of a simple eigenvalue), and a unit 2-form close to the area form of the sphere's tangent plane is the area form of a nearby plane. Take ε1\varepsilon_1 with 3Cε1<α3C\varepsilon_1 < \alpha.

The proposition is how Perelman and Morgan–Tian recognise necks intrinsically: at a point of a neck the curvature operator has one large eigenvalue and two small ones, and the plane of the large one is tangent to the cross-sectional sphere. This plane field is canonical (it does not depend on the choice of φ\varphi), and it is what lets two overlapping necks be compared.

Distances in a neck are nearly those of the model. On the model, d((ω,s),(ω′,s′))2=dh0(ω,ω′)2+(s−s′)2d\big((\omega, s), (\omega', s')\big)^2 = d_{h_0}(\omega, \omega')^2 + (s - s')^2, with dh0≤2πd_{h_0} \leq \sqrt2\pi; so for points far apart along the neck, d≈∣s−s′∣d \approx |s - s'| with an error at most π2∣s−s′∣\frac{\pi^2}{|s - s'|}. On an ε\varepsilon-neck the metric is within a factor 1±Cε1 \pm C\varepsilon of the model, so lengths of curves inside NN are distorted by at most that factor. With a little care about curves that leave NN (they must cross the ends, which costs length), this gives:

Proposition 6.4 Distances on a neck

For every α>0\alpha > 0 there is ε2(α)>0\varepsilon_2(\alpha) > 0 such that for any ε\varepsilon-neck NN centred at xx with R(x)=1R(x) = 1 and ε≤ε2\varepsilon \leq \varepsilon_2:

  1. if p,q∈Np, q \in N and ∣sN(p)−sN(q)∣≥ε−1100|s_N(p) - s_N(q)| \geq \frac{\varepsilon^{-1}}{100}, then (1−α)∣sN(p)−sN(q)∣≤d(p,q)≤(1+α)∣sN(p)−sN(q)∣(1 - \alpha)|s_N(p) - s_N(q)| \leq d(p, q) \leq (1 + \alpha)|s_N(p) - s_N(q)|;
  2. B(x,(1−α)ε−1)⊂N⊂B(x,(1+α)ε−1)B(x, (1 - \alpha)\varepsilon^{-1}) \subset N \subset B(x, (1 + \alpha)\varepsilon^{-1});
  3. a minimising geodesic of length more than ε−1100\frac{\varepsilon^{-1}}{100} inside NN crosses each sphere of the neck at most once, and its direction is within angle α\alpha of ±∂s\pm\partial_s.

Proof. We prove (1) for the model and indicate the perturbation; Morgan and Tian (Lemma 19.4 and Corollary 19.5) give the full argument. On the model, ∣s−s′∣≤d≤(s−s′)2+2π2≤∣s−s′∣+π2∣s−s′∣|s - s'| \leq d \leq \sqrt{(s - s')^2 + 2\pi^2} \leq |s - s'| + \frac{\pi^2}{|s - s'|}, which is within a factor 1+α1 + \alpha of ∣s−s′∣|s - s'| once ∣s−s′∣≥ε−1100|s - s'| \geq \frac{\varepsilon^{-1}}{100} and ε\varepsilon is small. For φ∗g\varphi^*g, curves inside NN change length by a factor in [1−Cε,1+Cε][1 - C\varepsilon, 1 + C\varepsilon], which proves both inequalities for distances realised by curves inside NN; a curve from pp to qq that leaves NN must run to an end and back, which is longer than ∣s(p)−s(q)∣|s(p) - s(q)|, because pp and qq lie strictly inside. (2) follows from (1) applied to xx and points near the ends. For (3): on the model, a minimising geodesic between points with ∣s−s′∣|s - s'| large is a straight line in S2×RS^2\times\mathbb{R} (the product of a great-circle arc and a segment), whose angle with ∂s\partial_s is at most arctan⁡2π∣s−s′∣\arctan\frac{\sqrt2\pi}{|s - s'|}; and a geodesic crossing a sphere twice could be shortened by replacing the part between crossings with a path inside the sphere. Closeness in C2C^2 makes geodesics of the perturbed metric close to those of the model on the scale of the neck.

Gluing products

The topology of chains of necks rests on one simple lemma and one standard fact about spheres in products.

Lemma 6.5 Gluing two products along a sphere

Let A=S2×(a,0]A = S^2\times(a, 0] and B=S2×[0,b)B = S^2\times[0, b), and let f:S2×{0}→S2×{0}f : S^2\times\{0\} \to S^2\times\{0\} be any diffeomorphism. Then A∪fBA\cup_fB, obtained by identifying the boundary sphere of AA with that of BB through ff, is diffeomorphic to S2×(a,b)S^2\times(a, b). The same holds with closed or half-open intervals at the outer ends.

Proof. Write f(ω,0)=(f0(ω),0)f(\omega, 0) = (f_0(\omega), 0) with f0f_0 a diffeomorphism of S2S^2. Define F:A∪fB→S2×(a,b)F : A\cup_fB \to S^2\times(a, b) by F(ω,s)=(f0(ω),s)F(\omega, s) = (f_0(\omega), s) on AA and F(ω,s)=(ω,s)F(\omega, s) = (\omega, s) on BB. On the glued sphere a point of AA, (ω,0)(\omega, 0), is identified with (f0(ω),0)∈B(f_0(\omega), 0) \in B, and both formulas give (f0(ω),0)(f_0(\omega), 0), so FF is well defined; it is a bijection and a diffeomorphism on each piece. To make it smooth across the gluing sphere, the smooth structure on A∪fBA\cup_fB is defined by collars, and with product collars the formula is smooth.

Notice that the lemma needs no knowledge of the diffeomorphism group of S2S^2: the twist f0f_0 is absorbed into one side. (A deeper fact, Smale's theorem that the orientation-preserving diffeomorphisms of S2S^2 form a group that deformation retracts onto SO(3)SO(3), is what one uses to see that such gluings can be made compatible with families; Morgan and Tian use it in chapter 12. Here it is not needed.)

The standard fact is the product region theorem: an embedded 2-sphere Σ\Sigma in S2×(0,1)S^2\times(0, 1) that is isotopic to a sphere S2×{s}S^2\times\{s\} cuts S2×(0,1)S^2\times(0, 1) into two pieces, each diffeomorphic to S2×S^2\times a half-open interval, with Σ\Sigma as the boundary. Equivalently, two disjoint isotopic spheres in a tube cobound a region diffeomorphic to S2×[0,1]S^2\times[0, 1]. (This is the version of Alexander's theorem (10A.5 The Prime Decomposition) for S2×RS^2\times\mathbb{R}; it follows from it by capping the tube with two balls to get S3S^3 and applying Alexander's theorem on each side. Statement here; Hatcher's notes, chapter 1.)

Proposition 6.6 The union of two overlapping tubes

Let U1,U2U_1, U_2 be open subsets of a 3-manifold, each diffeomorphic to S2×(0,1)S^2\times(0, 1). Suppose U1∩U2U_1\cap U_2 is diffeomorphic to S2×(0,1)S^2\times(0, 1), is a neighbourhood of one end of U1U_1 and of one end of U2U_2, and contains a sphere Σ\Sigma isotopic in U1U_1 to the spheres of U1U_1 and in U2U_2 to the spheres of U2U_2. Then U1∪U2U_1\cup U_2 is diffeomorphic to S2×(0,1)S^2\times(0, 1).

Proof. Σ\Sigma cuts U1U_1 into two pieces, each a half-open product by the product region theorem; let AA be the piece away from the end that U1∩U2U_1\cap U_2 neighbours. Likewise Σ\Sigma cuts U2U_2, and let BB be the piece away from its end in U1∩U2U_1\cap U_2. Then U1∪U2=A∪ΣBU_1\cup U_2 = A\cup_\Sigma B: every point of U1∪U2U_1\cup U_2 lies on one side of Σ\Sigma, and the parts of U1U_1 beyond Σ\Sigma (towards the overlap) lie in U2U_2's piece BB, and vice versa. By Lemma 6.5 the union is S2×(0,1)S^2\times(0, 1).

Overlapping necks and chains

Two ε\varepsilon-necks that meet substantially are almost aligned. Precisely (Morgan–Tian, Proposition 19.11; statement here, with the idea): if NN and N′N' are ε\varepsilon-necks centred at xx and x′x' that intersect, and ε\varepsilon is small enough, then

  • their scales agree to within a factor 1±α1 \pm \alpha: 1−α<R(x)R(x′)<1+α1 - \alpha < \frac{R(x)}{R(x')} < 1 + \alpha;
  • at a point yy well inside both, the spheres of NN and of N′N' through yy are nearly tangent, and, after possibly reversing one neck, ∂sN\partial_{s_N} and ∂sN′\partial_{s_{N'}} nearly agree;
  • the spheres of either neck that lie in the middle of the other are isotopic, inside the other, to its spheres.

The idea: by Proposition 6.3, at a point y∈N∩N′y \in N\cap N' the scalar curvature is close to R(x)R(x) (from NN) and to R(x′)R(x') (from N′N'), which gives the first statement; the plane of largest sectional curvature is canonical and close to the tangent planes of the spheres of both necks, which gives the second; and a sphere of NN in the middle of N′N' is then a nearly round sphere of nearly the right size whose tangent planes are nearly those of N′N''s spheres, so it is a graph over a sphere of N′N' and isotopic to it (Morgan–Tian, Corollary 19.3).

Definition 6.7 Chains of necks and ε\varepsilon-tubes

A chain of ε\varepsilon-necks is a sequence Na,…,NbN_a, \ldots, N_b (finite or infinite) such that each Ni∩Ni+1N_i\cap N_{i+1} contains the positive-most quarter of NiN_i and the negative-most quarter of Ni+1N_{i+1} and is contained in the positive-most three quarters of NiN_i and the negative-most three quarters of Ni+1N_{i+1}. An ε\varepsilon-tube is a submanifold diffeomorphic to S2×(0,1)S^2\times(0, 1) that is a union of ε\varepsilon-necks and in which every point is the centre of an ε\varepsilon-neck.

Proposition 6.8 A chain of necks is a tube

For ε\varepsilon small enough, the union of a chain of ε\varepsilon-necks is diffeomorphic to S2×(0,1)S^2\times(0, 1). The spheres of the necks can be interpolated to a fibration of the union by 2-spheres over an interval, each fibre nearly tangent to the spheres of the necks containing it.

Proof. For a finite chain, induct on the number of necks. One neck is S2×(−ε−1,ε−1)S^2\times(-\varepsilon^{-1}, \varepsilon^{-1}). If U=Na∪⋯∪Nb−1U = N_a\cup\cdots\cup N_{b-1} is a tube and NbN_b meets it as in the definition, then U∩NbU\cap N_b is the overlap Nb−1∩NbN_{b-1}\cap N_b (later necks do not reach back past it, by the conditions on quarters and the distance estimates of Proposition 6.4), which is a product region at one end of each; and it contains a sphere of Nb−1N_{b-1} that is isotopic, by the alignment of overlapping necks, to the spheres of NbN_b. Proposition 6.6 gives that U∪NbU\cup N_b is a tube. For an infinite chain, the union is an increasing union of tubes, each obtained from the last by adding a product region at one end, which is again S2×(0,1)S^2\times(0, 1) (exhaust (0,1)(0, 1) by intervals correspondingly). The fibration statement is proved by interpolating, with a partition of unity in the ss-coordinates, between the projection maps sNis_{N_i} on overlaps, where they nearly agree up to a translation.

A frontier remark used in the arguments: the union UU of a chain has frontier only at its two extreme ends (the negative end of the first neck and the positive end of the last), so a connected set that meets both UU and its complement must reach one of these extreme ends. And an infinite chain has no frontier at its infinite end.

Manifolds covered by necks

Proposition 6.9 Every point a neck centre

For ε\varepsilon small enough: if every point of a connected Riemannian 3-manifold MM is the centre of an ε\varepsilon-neck, then either MM is an ε\varepsilon-tube, diffeomorphic to S2×(0,1)S^2\times(0, 1), or MM is a 2-sphere bundle over the circle, S2×S1S^2\times S^1 or the nonorientable bundle S2×~S1S^2\tilde\times S^1.

Proof. Build a maximal chain of necks. Start with one neck and extend the chain neck by neck at both ends, choosing new necks centred at points of the frontier (every such point is a neck centre, and a neck centred at a frontier point of a chain extends the chain, after possibly reversing it; Morgan–Tian, Lemmas 19.17–19.18). Two things can happen. If the process never closes up, the union of the (finite or infinite) chain is a tube UU, open in MM; its frontier is empty when the chain is extended to infinity at both ends, so UU is also closed, and by connectedness U=MU = M: MM is a tube. Otherwise, at some stage the new neck at one end of the chain overlaps the neck at the other end, and the chain closes up into a ring. Then MM is a union of product regions glued cyclically, which is the mapping torus of a diffeomorphism ff of S2S^2: an S2S^2-bundle over S1S^1. If ff preserves orientation, it is isotopic to the identity (every orientation-preserving diffeomorphism of S2S^2 is, a classical fact that also follows from Smale's theorem), mapping tori of isotopic maps are diffeomorphic, and the mapping torus is S2×S1S^2\times S^1; if it reverses orientation, the mapping torus is the twisted bundle S2×~S1S^2\tilde\times S^1, which is nonorientable.

The manifolds S2×RS^2\times\mathbb{R}, S2×S1S^2\times S^1 and S2×~S1S^2\tilde\times S^1 all carry metrics in which every point is the centre of an ε\varepsilon-neck: long round cylinders, closed up or not. In a Ricci flow they appear as components that are entirely necks, and they are thrown away by surgery when their curvature is large.

Caps

Definition 6.10 (C,ε)(C, \varepsilon)-caps (simplified)

An ε\varepsilon-cap in (M,g)(M, g) is an open submanifold C\mathcal C with an ε\varepsilon-neck N⊂CN \subset \mathcal C such that C∖N\mathcal C\setminus N is compact, C\mathcal C is diffeomorphic either to an open 3-ball or to RP3\mathbb{RP}^3 minus a point, and the frontier of the core Y=C∖NY = \mathcal C\setminus N is the central sphere of an ε\varepsilon-neck. It is a (C,ε)(C, \varepsilon)-cap if in addition its geometry is controlled by CC at its own scale: R>0R > 0 on C\mathcal C; its diameter is less than C(sup⁡CR)−1/2C(\sup_{\mathcal C}R)^{-1/2}; the ratio of scalar curvatures at any two of its points is less than CC; its volume is less than C(sup⁡CR)−3/2C(\sup_{\mathcal C}R)^{-3/2}; the core's balls of radius comparable to the curvature scale are C−1C^{-1}-noncollapsed; and ∣∇R∣<CR3/2|\nabla R| < CR^{3/2}, ∣∂tR∣<CR2|\partial_tR| < CR^2. (This is Morgan and Tian's Definition 9.72 in words.)

The neck is oriented so that its negative end meets the core. Like necks, caps are scale-invariant notions. They arise in 12B.3 The Structure of κ-Solutions as the ends of noncompact κ\kappa-solutions: by the soul theorem (9B.5 Splitting and Soul Theorems) a noncompact κ\kappa-solution with positive curvature is diffeomorphic to R3\mathbb{R}^3, and seen from far away it looks like a half-infinite neck with a cap at the soul. The other possible core comes from quotients.

Proposition 6.11 RP3\mathbb{RP}^3 minus a ball

The quotient of S2×RS^2\times\mathbb{R} by the free involution ι(ω,s)=(−ω,−s)\iota(\omega, s) = (-\omega, -s) is diffeomorphic to RP3\mathbb{RP}^3 minus a point, and to the total space of the nontrivial line bundle over RP2\mathbb{RP}^2. Its end is a half-infinite tube S2×(0,∞)S^2\times(0, \infty), and removing that end leaves RP3\mathbb{RP}^3 minus an open ball.

Proof. ι\iota is free because −ω≠ω-\omega \neq \omega. A fundamental domain for ι\iota is S2×[0,∞)S^2\times[0, \infty), with the identification only on S2×{0}S^2\times\{0\}, where (ω,0)∼(−ω,0)(\omega, 0) \sim (-\omega, 0). So the quotient is S2×[0,∞)S^2\times[0, \infty) with the boundary sphere divided by the antipodal map: the mapping cylinder of the double cover S2→RP2S^2 \to \mathbb{RP}^2, with an open end. Projecting to RP2\mathbb{RP}^2, the fibre over [±ω][\pm\omega] is {(ω,s)}∪{(−ω,s)}\{(\omega, s)\}\cup\{(-\omega, s)\} modulo ι\iota, a line (R\mathbb{R}, parametrised by s∈Rs \in \mathbb{R} through the representative ω\omega); going around a loop in RP2\mathbb{RP}^2 that lifts to a path from ω\omega to −ω-\omega changes the parametrisation by s↦−ss \mapsto -s, so it is the nontrivial (Möbius-type) line bundle. On the other hand, RP3=B3/(antipodal identification on ∂B3)\mathbb{RP}^3 = B^3/(\text{antipodal identification on }\partial B^3): the closed ball modulo x∼−xx \sim -x on the boundary sphere. Removing the centre of the ball, B3∖{0}≅S2×(0,1]B^3\setminus\{0\} \cong S^2\times(0, 1], and the boundary identification is the antipodal map on S2×{1}S^2\times\{1\}; this is the same mapping cylinder, with the open end at the removed centre. So the quotient is RP3\mathbb{RP}^3 minus a point, and cutting off the end S2×(s0,∞)S^2\times(s_0, \infty) leaves RP3\mathbb{RP}^3 minus an open ball.

In a Ricci flow, (S2×R)/ι(S^2\times\mathbb{R})/\iota with the quotient of the round cylinder metric is the model for the second type of cap: a neck closed off at one end not by a ball but by an RP2\mathbb{RP}^2, the "cross-cap". It is a quotient of the shrinking cylinder, so it is an ancient solution, and it is one of the κ\kappa-solutions of 12B.1 κ-Solutions.

Components covered by necks and caps

Theorem 6.12 Components covered by canonical neighbourhoods

For ε\varepsilon small enough and any CC: let XX be a connected subset of a Riemannian 3-manifold MM such that every point of XX is the centre of an ε\varepsilon-neck or lies in the core of a (C,ε)(C, \varepsilon)-cap. Then one of the following holds:

  1. XX lies in a component of MM that is the union of two caps, diffeomorphic to S3S^3, RP3\mathbb{RP}^3 or RP3#RP3\mathbb{RP}^3\#\mathbb{RP}^3;
  2. XX lies in a component that is a double capped tube (a tube with a cap at each end), again diffeomorphic to S3S^3, RP3\mathbb{RP}^3 or RP3#RP3\mathbb{RP}^3\#\mathbb{RP}^3;
  3. XX lies in a single cap;
  4. XX lies in a capped tube (a tube with a cap at one end), diffeomorphic to an open ball or to RP3\mathbb{RP}^3 minus a point;
  5. XX lies in a tube;
  6. XX lies in a component that is an S2S^2-bundle over S1S^1 and a union of necks.

The structural part, that the possibilities are only these, is Morgan and Tian's Proposition 19.21; its proof extends chains of necks as in Proposition 6.9, uses the frontier remarks to see what happens when a chain runs into the core of a cap, and rules out infinite nested sequences of caps by the curvature and diameter controls of a (C,ε)(C, \varepsilon)-cap. The identification of the closed components, which is the part used at the end of the Poincaré conjecture, follows from the gluing lemma and can be done completely.

Proof (Proof of the identifications). Capped tubes. The core YY of a cap is a ball or RP3\mathbb{RP}^3 minus a ball, with boundary a sphere of a neck. Attaching a tube S2×[0,1)S^2\times[0, 1) along that sphere attaches a collar, which does not change the interior up to diffeomorphism: the result is an open ball or RP3\mathbb{RP}^3 minus a point.

Two caps, or a double capped tube. A component that is a tube with caps at both ends is Y1∪(S2×[0,1])∪Y2Y_1\cup(S^2\times[0, 1])\cup Y_2, and by Lemma 6.5 (absorb the tube into a collar of Y1Y_1) it is Y1∪fY2Y_1\cup_fY_2 for some diffeomorphism ff of the boundary spheres. Two caps overlapping along their necks give the same description. Now:

  • if both cores are balls, B3∪fB3=S3B^3\cup_fB^3 = S^3, whatever ff (the Alexander trick, 10A.3 Building Three-Manifolds: genus-00 Heegaard splitting);
  • if one is a ball and one is RP3\mathbb{RP}^3 minus a ball, the union is RP3\mathbb{RP}^3: gluing a ball onto a manifold with sphere boundary refills the removed ball, and the result is independent of the gluing map by the Alexander trick again;
  • if both are RP3\mathbb{RP}^3 minus a ball, the union is, by the definition of the connected sum (10A.5 The Prime Decomposition), RP3#RP3\mathbb{RP}^3\#\mathbb{RP}^3 (the connected sum is well defined, independent of the gluing up to the choice of orientations, and RP3\mathbb{RP}^3 admits an orientation-reversing diffeomorphism, so even that choice does not matter).

Why only these. The list in Theorem 6.12 is short because of what caps are allowed to be: a ball or a punctured RP3\mathbb{RP}^3. That restriction is not a definition of convenience but a theorem about κ\kappa-solutions (12B.3 The Structure of κ-Solutions): the only ways a three-dimensional κ\kappa-solution can end, seen at the scale of its curvature, are a capped neck with core a ball (positive curvature, soul theorem) or the cross-cap quotient above. Everything else that is compact and highly curved is a whole component of positive curvature, a CC-component diffeomorphic to S3S^3 or RP3\mathbb{RP}^3, or an ε\varepsilon-round component, which is a spherical space form (10A.2 Finite Rotation Groups and Spherical Space Forms).

The topological effect of surgery

Combine this with 10A.5 The Prime Decomposition. At a surgery time, the flow has a region where the curvature stays bounded and ε\varepsilon-horns, tubes along which the spheres shrink towards the singular set. In each horn that matters, a sphere deep inside, the central sphere of a strong δ\delta-neck, is cut, and the piece beyond it is replaced by a cap from the standard solution (12B.9 Surgery). Topologically:

  • each cut is a surgery along a 2-sphere in an S2×IS^2\times I, which by 10A.5 The Prime Decomposition undoes a connected sum or removes an S2×S1S^2\times S^1 summand, and may split off copies of S3S^3;
  • each component thrown away entirely is covered by ε\varepsilon-necks and (C,ε)(C, \varepsilon)-caps, or is a CC-component or an ε\varepsilon-round component, and so is diffeomorphic to S3S^3, RP3\mathbb{RP}^3, RP3#RP3\mathbb{RP}^3\#\mathbb{RP}^3, S2×S1S^2\times S^1, S2×~S1S^2\tilde\times S^1, or a spherical space form.

So the manifold before surgery is a connected sum of the manifold after surgery with copies of these, and of copies of S2×S1S^2\times S^1 (or S2×~S1S^2\tilde\times S^1) from nonseparating cuts. If the flow eventually becomes extinct, the original manifold is a connected sum of spherical space forms and S2S^2-bundles over S1S^1, which is Morgan and Tian's deduction of their main theorem from finite extinction. For a simply connected manifold, every summand must be simply connected, and the only simply connected entry on the list is S3S^3 (10A.5 The Prime Decomposition, corollary on surgery on simply connected manifolds).

Where this goes Where necks and caps are used

12B.3 The Structure of κ-Solutions proves that κ\kappa-solutions are covered by necks and caps at their own scale; 12B.5 The Canonical Neighbourhood Theorem transfers this to points of high curvature in any Ricci flow, the canonical neighbourhood theorem; 12B.9 Surgery performs surgery in the necks of ε\varepsilon-horns; 12C.1 Reading Off the Topology reads off the topology with the theorem above.

History

Hamilton introduced necks into the study of singularities in his 1995 survey and used them to do surgery on four-manifolds in 1997. Perelman's definitions of ε\varepsilon-necks, caps and canonical neighbourhoods are in §12 of his first preprint and throughout the second (2002–03). The careful development of overlapping necks, chains and the components covered by canonical neighbourhoods is in Kleiner and Lott's notes and in Morgan and Tian's appendix (2006–07). Smale proved that the diffeomorphism group of S2S^2 deformation retracts onto O(3)O(3) in 1959.

Recall Where we stand

An ε\varepsilon-neck centred at xx is a region that, rescaled by R(x)R(x), is ε\varepsilon-close in C[1/ε]C^{[1/\varepsilon]} to S2(2)×(−ε−1,ε−1)S^2(\sqrt2)\times(-\varepsilon^{-1}, \varepsilon^{-1}), the cylinder of scalar curvature 11; it has scale R(x)−1/2R(x)^{-1/2}, an ss-coordinate, a central sphere, and curvature eigenvalues near {1,0,0}\{1, 0, 0\}, with the top plane tangent to the spheres. Distances along a neck are ∣Δs∣|\Delta s| up to a factor 1±α1 \pm \alpha. Two products glued along a sphere make a product, so overlapping necks, which nearly align, chain into tubes S2×(0,1)S^2\times(0, 1); a manifold covered by necks is a tube or an S2S^2-bundle over S1S^1. Caps have core a ball or RP3\mathbb{RP}^3 minus a ball, the latter being (S2×R)/ι(S^2\times\mathbb{R})/\iota, the line bundle over RP2\mathbb{RP}^2. Two cores glued give S3S^3, RP3\mathbb{RP}^3 or RP3#RP3\mathbb{RP}^3\#\mathbb{RP}^3. So surgery splits off connected summands and discards standard pieces, and extinction makes a manifold a connected sum of space forms and S2S^2-bundles over S1S^1. 10A.7 Seifert Spaces and the JSJ Decomposition cuts irreducible manifolds along tori.

Exercises

Exercise 6.13 The model neck

For the round cylinder S2(ρ)×RS^2(\rho)\times\mathbb{R}, compute the sectional curvatures, the Ricci tensor and the scalar curvature, and show that R=1R = 1 exactly when ρ=2\rho = \sqrt2. Then show that the cylinder S2(2−2t)×RS^2(\sqrt{2 - 2t})\times\mathbb{R}, t<1t < 1, is a Ricci flow with R=11−tR = \frac{1}{1 - t} at time tt, and that at every time and point it is the centre of an ε\varepsilon-neck for every ε>0\varepsilon > 0.

Solution

Planes tangent to the sphere have curvature 1ρ2\frac{1}{\rho^2}, planes containing ∂s\partial_s have curvature 00 (9A.5 Computing Curvature). Ric⁡=1ρ2gS2(ρ)⊕0\operatorname{Ric} = \frac{1}{\rho^2}g_{S^2(\rho)}\oplus0 (each sphere direction has Ricci curvature 1ρ2+0\frac{1}{\rho^2} + 0), and R=2ρ2R = \frac{2}{\rho^2}, which is 11 iff ρ=2\rho = \sqrt2. Under the flow the sphere factor evolves by ∂t(ρ2)=−2⋅1\partial_t(\rho^2) = -2\cdot1 (11A.1 The Equation and Its First Solutions), so ρ2=2−2t\rho^2 = 2 - 2t from ρ(0)=2\rho(0) = \sqrt2, and R=2ρ2=11−tR = \frac{2}{\rho^2} = \frac{1}{1 - t}. At time tt, multiplying the metric by R=11−tR = \frac{1}{1 - t} gives the cylinder of radius 2\sqrt2 exactly, so for every ε\varepsilon the map (ω,s)↦(ω,1−t (s+s0))(\omega, s) \mapsto (\omega, \sqrt{1 - t}\,(s + s_0)) (recentred at any point) is an ε\varepsilon-neck structure with zero error.

Exercise 6.14 How long is a neck?

On an ε\varepsilon-neck with ε=0.01\varepsilon = 0.01, how many times longer than its cross-sectional diameter is the neck, approximately? How many derivatives of the metric are controlled?

Solution

The length is about 2ε−1rN=200rN2\varepsilon^{-1}r_N = 200r_N, and the cross-section, a nearly round sphere of radius 2rN\sqrt2r_N, has intrinsic diameter about 2πrN≈4.44rN\sqrt2\pi r_N \approx 4.44r_N. So the neck is about 2004.44≈45\frac{200}{4.44} \approx 45 times longer than it is wide. The closeness is in C[1/ε]=C100C^{[1/\varepsilon]} = C^{100}: one hundred derivatives.

Exercise 6.15 Three products in a row

Using Lemma 6.5 twice, show that S2×(0,1]∪fS2×[1,2]∪f′S2×[2,3)S^2\times(0, 1]\cup_fS^2\times[1, 2]\cup_{f'}S^2\times[2, 3) is diffeomorphic to S2×(0,3)S^2\times(0, 3) for any diffeomorphisms f,f′f, f' of the gluing spheres. Then explain why a cyclic gluing S2×[0,1]S^2\times[0, 1] with S2×{0}S^2\times\{0\} glued to S2×{1}S^2\times\{1\} by ff need not be S2×S1S^2\times S^1.

Solution

Glue the first two: by the lemma, S2×(0,1]∪fS2×[1,2]≅S2×(0,2]S^2\times(0, 1]\cup_fS^2\times[1, 2] \cong S^2\times(0, 2], by a diffeomorphism that is the identity on S2×[1,2]S^2\times[1, 2], so the second gluing sphere and f′f' are unchanged; then glue on the third. In the cyclic case there is no free end to absorb the twist into: the result is the mapping torus of ff, which is S2×S1S^2\times S^1 when ff is isotopic to the identity and the nonorientable S2×~S1S^2\tilde\times S^1 when ff reverses orientation (for instance ff the antipodal map).

Exercise 6.16 The cross-cap is κ\kappa-noncollapsed

Let Z=(S2×R)/ιZ = (S^2\times\mathbb{R})/\iota with the quotient of the cylinder metric of scalar curvature 11. Show that ZZ has ∣Rm⁡∣|\operatorname{Rm}| bounded and that its balls of radius 11 have volume bounded below by a positive constant independent of the centre. Why does this make ZZ a candidate model for a cap in a three-dimensional flow, while the cigar times a line is not?

Solution

ZZ is locally isometric to the cylinder, so its curvature is that of the cylinder, constant and bounded. A ball of radius 11 in ZZ centred at [p][p] is the image of the ball of radius 11 around a lift pp in the cylinder, under the 2-to-1 projection; so its volume is at least half that of a cylinder ball, which is a fixed positive number v0v_0 (the cylinder is homogeneous). So ZZ is κ\kappa-noncollapsed at scale 11 with κ≥v02\kappa \geq \frac{v_0}{2}, and as an ancient solution (the quotient of the shrinking cylinder) it is a κ\kappa-solution. The cigar times a line has ends that are collapsed at large scales (9B.3 Collapsing and Noncollapsing), which Perelman's noncollapsing excludes; the cross-cap has no collapsed end.

Exercise 6.17 Gluing two caps

Show that gluing two copies of RP3\mathbb{RP}^3 minus a ball along their boundary spheres by any diffeomorphism gives RP3#RP3\mathbb{RP}^3\#\mathbb{RP}^3, and that its fundamental group is Z/2∗Z/2\mathbb{Z}/2 * \mathbb{Z}/2. Show that this group is infinite and that RP3#RP3\mathbb{RP}^3\#\mathbb{RP}^3 is not a spherical space form, although it is covered by necks and caps.

Solution

The union is the connected sum by definition, and the connected sum does not depend on the gluing (orientation-preserving gluings are isotopic; an orientation-reversing one can be corrected by an orientation-reversing self-diffeomorphism of RP3\mathbb{RP}^3, which exists, induced by a reflection of S3S^3 commuting with x↦−xx \mapsto -x). By van Kampen (7A.5 Computing π₁), π1=Z/2∗Z/2=⟨a,b∣a2=b2=1⟩\pi_1 = \mathbb{Z}/2 * \mathbb{Z}/2 = \langle a, b \mid a^2 = b^2 = 1\rangle, and abab has infinite order (the words (ab)n(ab)^n are reduced and distinct), so the group is infinite. A spherical space form has finite fundamental group, so RP3#RP3\mathbb{RP}^3\#\mathbb{RP}^3 is not one. It is covered by necks and caps: a long round cylinder with a cross-cap at each end. Its universal cover is S2×RS^2\times\mathbb{R} (10A.4 Homotopy Groups, Degree and the Hurewicz Theorem).

Exercise 6.18 Rehearsal: what extinction leaves

Suppose a Ricci flow with surgery on a closed simply connected MM becomes extinct, and that at the last surgery every remaining component is a capped or double capped tube or a component covered by necks, a CC-component or an ε\varepsilon-round component. Use Theorem 6.12, 10A.2 Finite Rotation Groups and Spherical Space Forms and 10A.5 The Prime Decomposition to prove that M≅S3M \cong S^3, listing where simple connectivity is used.

Solution

Every surgery is along a sphere, and in a simply connected manifold every sphere separates and every piece stays simply connected (10A.5 The Prime Decomposition); so MM is the connected sum of all the components discarded along the way. Each discarded component is simply connected (it is a summand). On the list of possible components, S3S^3, RP3\mathbb{RP}^3, RP3#RP3\mathbb{RP}^3\#\mathbb{RP}^3, S2×S1S^2\times S^1, S2×~S1S^2\tilde\times S^1 and the spherical space forms S3/ΓS^3/\Gamma, the only simply connected ones are S3S^3 (and S3/ΓS^3/\Gamma with Γ=1\Gamma = 1, which is S3S^3): π1(RP3)=Z/2\pi_1(\mathbb{RP}^3) = \mathbb{Z}/2, π1(RP3#RP3)\pi_1(\mathbb{RP}^3\#\mathbb{RP}^3) is infinite, π1(S2×S1)=π1(S2×~S1)=Z\pi_1(S^2\times S^1) = \pi_1(S^2\tilde\times S^1) = \mathbb{Z}. So every summand is S3S^3 and M≅S3#⋯#S3≅S3M \cong S^3\#\cdots\#S^3 \cong S^3. Simple connectivity was used to make every surgery separating (no S2×S1S^2\times S^1 summands appear from cuts) and to exclude every entry but S3S^3.

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